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Post by Don Barone on May 9, 2017 7:24:13 GMT -5
Hi all ... well this is very interesting. I chanced to look at an old image I had posted at Graham's on Jan 6th, 2011 and since visions of right angled triangles are dancing through my head an idea occurred to me ... Here is the image ... You will note that the diagram shows that the distance from the north face of The Great Pyramid or G1 down to the north face of The Pyramid of Menkare works out to be the diameter in a circle precisely 14 Mars years in length. A Martian year is equal to 686.98 Earth days. I found that very interesting then and actually I still do. Quite the co-incidence I have always thought. I don't know why I have never done this before but this morning I decided to see if the Martian year might be encoded anywhere else at Giza and I have to admit although Giza has always surprised me, this one almost knocked me out of my chair ... The first number I tried was 10 and got 6869.8 and on the surface did not ring any bells and then I had a thought well The Great Pyramid is in the ratio of 22/28 so maybe I should check this ratio next and so I decided to check (this is where it gets mind boggling) what 11 times a Martian year would equal and as I said I can't believe I had never done this before ... anyway I decided to multiply the number of days in a Martian year in Earth days or 686.98 by 11 and got ... I do hope you are sitting down for this one I got ... 7556.78 ! Well maybe it is because I have lived with these numbers at Giza for over 17 years but that number immediately looked awesome ... and it was for it is none other than 10 TIMES THE NUMBER OF FEET IN THE BASE OF THE GREAT PYRAMID !!!!!!!! Proof being 7556.78 / 10 = 755.78 (feet) times 12 inches = 9068.136 !!!!!!!! The base of the actual Great Pyramid ... I must admit to being dumbfounded ! Well the next move was obvious and so I decided to multiply 686.98 by 7 and got 4808.86 and again immediately recognizing this number and sure enough we find the when divided by 10 and multiplied by 12 (for inches) we get ... 4808.86 / 10 = 480.886 FEET x 12 inches = 5770.632 inches and the precise height to the inch (maybe) of The Great Pyramid. So what have we discovered today ? Well we have discovered that The Great Pyramid, as well as showing us Mercury and Earth can now be said to be showing us Mars as well for in it's ratio of 11 and 7 the number of feet (inches) in the base and height using the Martian Year in Earth days as 1 foot equal the exact ratio of 11 by 7 or ... Base = 11 x 686.98 / 10 while Height = 7 x 686.98 / 10. I continue to stand humbled by what is hidden at Giza ... This really is quite neat !!! I LOVE GIZA !!!!!!! Cheers Don Barone .
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Post by Don Barone on May 9, 2017 8:30:39 GMT -5
Okay well let's continue our search for Mars and do a simple multiplication table This is so exciting look at all the new numbers I have to torture ! Cheers Don Barone
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Post by Don Barone on May 9, 2017 8:53:43 GMT -5
Okay there are a couple right off the bat that look promising so let's start with those but first an image I designed 3 x 686.98 from our chart above = 2060.94 now divided by 100 as is our want and we get 20.6094 or possibly the number of inches in a cubit although most would wager on 20.62 however there are many who would give the nod to 20.61 and others who would give the nod to 20.625. Let's continue. Now I have to admit something has always bothered me. This was a melding of the inch and the ancient cubit and it had to fit nicely ... or so I reasoned so I always believed The Great Pyramid it had to be in the ratio of 440 cubits by 280 cubits but I also totally believed the inch was involved so how to rectify it all. Well if we accept the base unit measuring system as the number of Earth days in a Martian year ( I know a rather large pill to swallow in today's time) we find that it fits almsot precisely with the number of feet in the proper ratio but what of Ancient Egypt and The Master Builders what base were they using ? To solve that we should if we accept 440 and 280 cubits as a correct and logical measurement we would simply divide the number of inches we have calculated which is 755.678 x 12 or 9068.136 inches and when we divide by 440 we arrive at (not surprisingly I suppose) 9068.136 / 440 = 20.6094 inches per cubit and exactly the same number we got when we multiplied 686.98 x 3 then divided by 10. So in this new Martian based system the leading candidate for the number of inches in a cubit is obviously 20.61 inches ... Very interesting but could there be more proof to find ? Well maybe ... If we allow the base to equal 755.678 feet as in mandated by our new Martian Year base unit then what would a cubit equal in relation to a foot ? Well that is simple enough to figure out we would just divide 755.678 by 440 to get 1.71745 ... So a cubit in this number system is equal to 1.71745 feet ... Well can we find that number anywhere in our chart and sure enough we find that 25 times a Martian Year of 686.98 = 17174.5 or EXACTLY 10,000 TIMES OUR CUBIT TO FOOT RATIO !!! Not sure about you but I wonder what else we might find at Giza using a cubit of 20.6094 inches. Cheers Don Barone .
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Post by Don Barone on May 9, 2017 9:39:58 GMT -5
Okay let's take a look at this one .... 32 x 686.98 = 21983.36 Now if we divide by 100 we get ... 219.8336 and on the surface too small to be 1/2 base of G1 but let's do it anyway 219.8336 x 2 = 439.6672. Now if we multiply this by our cubit of 20.6094 inches we get ... 20.6094 x 439.6672 and we get 9061.27719168 ... Now I had seen that number, 906, in other places in my research (haven't a clue where at the moment) so I decided to simply, as a beginning, to divide by our 10 and then find the square root of this number 906.127719168 and found that the square root of this number is 30.10195540... Now again I guess because I have worked at this for so long that number immediately rang a bell with me and so I went to this page www.eightplanetsfacts.com/neptune.php to confirm what I suspected and here is what this page showed. It said ... For the planet Neptune that the ... Semi-major axis: 4,503,443,661 km, 30.10366151 AE. So here is our base unit of a Martian Year in Earth Days defining the distance from The Sun to Neptune in Earth Astronomical Units which is 149,597,870.7 kilometres to an accuracy of ( 30.10195540 / 30.10366151 = 0.99994 or 6 parts in 100,000 ( 100 thousand) Now again that is interesting ... but was it simply yet another co-incidence brought about by torturing some poor defenceless number ? We shall see as I press forward ... Cheers Don Barone
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Post by Don Barone on May 9, 2017 10:04:29 GMT -5
Okay for a formula to be called good it should work for more than one item so let's try our luck at Uranus ... So let's pick on lucky 13 and see how we fair. 13 x 686.98 = 8930.74 Now in the example about we divided by 100 and we get 89.3074 then we multiplied by 2 and we get 178.6148 ... now we multiply by our cubit of 20.6094 and we get 3681.14385912 then we divided by 10 and it leaves us 368.114385912 and then we took the sqaure root of that number and in this case we arrive at 19.18630725 ... Now what does the internet say about the semi major axis of Uranus ? Well returning to that page again we find that Uranus is 19.22941195 Astronomical Units or 2,876,679,082 kilometres while using our number would arrive at 149,597,870.7 x 19.186307 to arrive at 2,870,230,711.3 kilometres not great but considering there are a variety of answers on the internet for the semi major axis of Uranus ... Now just to show that I may have stumbled onto something I would like to quote this page ... physics.unm.edu/101lab/lab3/lab3_C.html which has the semi major axis of Uranus at 19.18 ... Interesting ... Cheers that's 2 down and 6 to go ... Don Barone .
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Post by Don Barone on May 9, 2017 10:47:33 GMT -5
Well the other planets are not cooperating so it appears that part of the theory, that it will yield the formula for the planet distances still eludes us.
Cheers Don Barone
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Post by Don Barone on May 10, 2017 9:05:32 GMT -5
Hi all .... Well I am really not sure if I had found this before or not. I have searched a few threads and although Clive had discovered another use for these numbers I don't think either of us saw this. In one of Clive's early drawings he suggested this: But surprisingly him and I both I think missed a very obvious one. The numbers we are using are the numbers of days in a year in Earth days for both Mars and Earth with Mars being 686.98 and Earth being 365.25. Now in the diagram above you can see how Clive showed that 2 Mars + 1 Earth equalled the overall height of The Giza Rectangle while 1 Mars and 2 Earths equalled the horizontal distance or width. Then in this thread I showed how the three pyramid's base length led to all sort sorts of things ... concentrating toward diameters and such ... Here is that link.But this morning I did a very obvious thing after trying a zillion other things to make the numbers talk and I simply added 1 Mars and 1 Earth and got 686.98 + 365.25 and arrived at 1052.23 ... Now anyone who has followed my work will immediately recognize that number ... but if not allow me to show you again. Base of G1 + G2 + G3 = 440 + 411 + 201.46 = 1052.46 ... almost an exact match ... So on top of everything else these pyramids have shown us they now show us the number of days in 1 Martian Year plus 1 Earth year in days when the scale is 1 cubit = 1 day ... I am working on other things as well so hopefully there will be more soon ... Cheers Don Barone .
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Post by Don Barone on May 10, 2017 9:35:46 GMT -5
Okay I think I have a bit more ... but first we have to realize that Petrie made an error in his calculations and the diagram I am about to post is the corrected version. It still uses all of his original data but simply adjust two calculations so that 29102 turns out to be 29112 inches and thus the diagonal is adjusted accordingly. Now in earlier posts in this thread I had suggested that 3 Martian years which equal 2060.94 was in fact showing us the actual length of inches in 100 cubits so that 1 cubit would equal 20.6094 inches. It seemed to work very good for the base and height of The Great Pyramid but could I find another possible proof of this. So looking at Clive's diagram again I decide to once again see what 2 Earths + 1 Mars equal and got ... 365.25 + 365.25 + 686.98 and found that this equalled 1417.46 cubits. Remembering our new scale of 1 year = 1 cubit. Now if this were to work then we would have to multiply by our new cubit length of 20.6094 inches and that should give us the correct number of inches across the Giza Plateau ... Ready ? Okay 1417.48 x 20.6094 = 29213.412312 inches. So if this reasoning is correct the correct distance across The Giza Plateau should be 29,213.4 inches ... Now what do you suppose we get ? Well have a look ... So according to this diagram we check for 5 inches ... Not too bad ... The 1417.13 cubits is if we use 20.618034 inches per cubit .... Cheers Don Barone .
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Post by Charlotte on May 10, 2017 9:48:50 GMT -5
Hi Don,
Love our logo image, you and me both love Giza and the Pyramids as do so many others. Eternal Egypt, radiating continuous energy.
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Post by Don Barone on May 10, 2017 10:11:07 GMT -5
Well "The Mars Ruler" is showing us some super surprising things and this one has to almost be the top of the cake. In this diagram again: ... we had shown that the horizontal or width distance was 1417.48 and then times 20.6094 (Martian Cubit) or 29,213.4 inches so I then tried to make sense of the vertical distance at Giza. In the diagram we have height or vertical distance as 35,723.5 inches. Now if we divide this by our Martian Cubit of 20.6094 inches we get 35,723.5 / 20.6094 = 1733.36 cubits. The inevitable conclusion I have come to is ... MORE THAN ONE CUBIT HAS BEEN USED IN THE LAYOUT OF THE GIZA RECTANGLE !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! I will explain how I came to that conclusion later ... Cheers Don Barone ,
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Post by Don Barone on May 10, 2017 10:49:54 GMT -5
Hi Don, Love our logo image, you and me both love Giza and the Pyramids as do so many others. Eternal Egypt, radiating continuous energy. Thanks Charlotte ... I continue to note that Venus seems to be missing form The Great Pyramid even thought I keep looking for it ... Cheers Don Barone "Lost in space ... yet again"
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Post by Charlotte on May 11, 2017 8:51:23 GMT -5
Hi Don, Love our logo image, you and me both love Giza and the Pyramids as do so many others. Eternal Egypt, radiating continuous energy. Thanks Charlotte ... I continue to note that Venus seems to be missing form The Great Pyramid even thought I keep looking for it ... Cheers Don Barone "Lost in space ... yet again" You will be back eventually to with the rest of us mortals deal with daily life on Earth
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Post by Don Barone on May 11, 2017 18:29:21 GMT -5
Sigh ... yes I know However now armed with our new and maybe improved Martian Cubit of 20.6094 inches let's see what goodies we can squeeze out of G2. Since we have found that the number of days of the orbital period of Mars fits rather nicely into G1 I set about seeing if it or any of the other planer's orbital periods would yield anything useful ... Let's list them ... Mercury 88 days (exact 87.969) Venus = 224.7 (exact 224.701) Earth = 365.25 (exact 365.256363004) Mars 686.98 (exact = 686.971) ( another website has it at Orbital Period: 686.92971 days) but the vast majority use 686.98 Ceres = 4.60 years or 1680.18 days Jupiter = 4,332.59 days or 11.8618 years Saturn = 10,759.22 or 29.4571 Uranus = 30,688.5 days or 84.0205 yrs Neptune = 89,666 days or I decided to try Venus first with it's year of 224.701 days ... Now since The Great Pyramid can said to represent so many things I will list them below ... The Great Pyramid equals depending on what you are doing and what measurement system you are using can yield any and all of the following: Mercury, Earth, Mars, the square root of 3, a simple 11 by 7 pyramid, The perfect Pi Pyramid. a perfect Phi Pyramid But what of The Pyramid of Khafre ? What can it show us ? Well we already have discovered that it is in the ratio 3, 4 and 5 and that the diagonal of G2 when using 411.035 cubits = 581.29 and using this as a diameter we find the we get for the circumference Pi x 581.29 or 1826.1804 and we find when we divide this by 5 we get 365.24 days ... an Earth Year in days We also had already discovered that if G1 = sq rt of 3 or 440 cubits or 9068.2 inches G2 = Phi or 411.035838 cubits or 8471.20 inches. G2 can also said to represent The Sun since the Equatorial surface gravity of The Sun is 274.0 m/s2sqrd and the height of G2 in cubits is also 274 ... (274.02 cubits) But we already knew all this and I was looking for something new ... so after exhausting any 686.98 possibility for G2 I decide to use Venus itself at 224.7 and see what I could come up with. Well G1 had been discovered by using the orbital period of Mars compared to FEET ! so I reasoned let's try that approach and this is what I got ... 8471.2 inches (using all the previous data including the Martian Cubit of 20.6094) we find that 8471.2 inches = 8471.2/12 = 705.93 FEET ! And who would have thought that when one divides the number of feet in the base of G2 ( 705.93 FEET ) BY PI ... we get ....... 224.706 ... THE ORBITAL PERIOD OF VENUS ( to within 5/1000th of a day or 432 seconds or 7.2 minutes) ... Now that's neat again !!!!!! Cheers Don Barone ,
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Post by Don Barone on May 11, 2017 18:59:22 GMT -5
Just a very quick one as I am very tired and just didn't want to lose the thought ... Keeping with FEET now I decide to see what G3 could give us so I used 4154 inches and divide by 12 and we get 346.1667 now since in G1 we multiplied by 10 I decided to try that here as well and got 346.1667 x 10 = 3461.667 and then ... I multiplied by Pi and got 10875 and nothing that rang any bells so i decided to DIVIDE by Pi and got 1101.88 now what could that mean ? ... Well .... It might relate to this diagram ... then again it might not ... will study it further later ... Cheers Don Barone
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Post by Don Barone on May 12, 2017 19:12:51 GMT -5
Hi all this post was supposed to be on G3 and also finding Phi squared at G2 but then I chanced on an old diagram I have on my hard drive which I viewed again as I was going through it ... Here is the diagram ... This need more work but is getting really interesting ... Another image from Jim Allison ...
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Post by Don Barone on May 12, 2017 20:24:11 GMT -5
Okay not sure if that is really all that perfect ... but anyway ... back to G2 ... Firstly let's look at an old post from 2012: Author: Ahatmose () Date: November 14, 2012 08:07PM Hi Greg. Clive Ross noted several years ago that the ratio of a volume of a sphere and the cube was staring us in the face. volume of cube:volume of sphere=(4Pi/3)(1/2x)^3 : x^3 (pi/6)x^3:x^3 answer is pi:6 or pi/6 The ratio of a volume of a sphere and the cube = 6/pi = 1.90986 Okay so as I was playing with the measurements of G2 remember we got 705.919 in feet for the base but remember this is actual 6 in our 3, 4 and 5 sided right angled triangle so the height is 4 and the slope is 5 and 1/2 base is 3 ... well base is 6 so slope is 5 and if base is Pi x 244.701 slope would be Pi x 244.701 divided by 5 and we get ... 705.919 / 5 and we get ... 117.653 x 5 = 588.2658 feet ... now interestingly 588.2658 / 224.701 (orbital period of Venus in case you had forgotten) gives us 2.618 ... Hmmm .... So we get Pi / 6 (0.5236) then times 5 = 2.618 or Phi squared ... ALMOST ! Cheers Don Barone Sorry I am very tired not nearly as clear as I wanted to make it.
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Post by spaceyhippie on May 22, 2017 12:20:07 GMT -5
Hi all .... But this morning I did a very obvious thing after trying a zillion other things to make the numbers talk and I simply added 1 Mars and 1 Earth and got 686.98 + 365.25 and arrived at 1052.23 ... Now anyone who has followed my work will immediately recognize that number ... but if not allow me to show you again. Base of G1 + G2 + G3 = 440 + 411 + 201.46 = 1052.46 ... almost an exact match ... i have often found that it matters what they are off by... in this case, the decimal 46 is twice the other decimal 23 also, 46° is another way to say 44° depending if yer measuring from east or north dudeman.net/astra/giza/4445.html
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Post by Don Barone on Jun 4, 2017 19:07:07 GMT -5
Hi all ... Well while going over some old diagrams new revelations are sure to follow. Case in point below ... Here is a diagram from quite a while ago where I showed the semi major axis' of Earth and Mars fitted in perfectly using the centre of G2 as The Sun. And then I found this other diagram from about the same time that showed a relationship between the diameters of Earth and Mars. And then tonight while looking at them a light went off and I came up with these two images: This is a nice one showing the two orbits of Earth and Mars with the center of G2 as The Sun ... And then this little gem ... What I had failed to see in the past is that not only are the two orbits showing us something the ratios of the diameters of Earth and Mars are showing us the exact same ratio ... observe ! Semi major axis of Earth is 149,598,261 km Semi major axis of Mars is 227,939,100 Diameter of Mars = 6792 km Diameter of Earth i= 12,756.28 km So if you look at the diagram you will see diameter of Earth's obit is 2 x 149,598,261 or 299,196,522 km NOW AMAZINGLY DIAMETER OF EARTH ORBIT IS EQUAL TO 1118.1466 AND SUBTRACT FROM WIDTH OF GIZA RECTANGLE OF 1417.50 GIVES US 299.3534 OR AN ALMOST EXACT MATCH. If you look at the diagram you will see Mars orbit is 2 x 227,939,100 km or 455,878,200 km SO IN THE DIAGRAM OF THE TWO PLANETS SUPERIMPOSED THE DIAMETER OF EARTH IS EQUAL TO 1118.1466 and is equal to 12,756.28 km . Then we move to Mars but we only have half of Mars so we have to double the 299.196 to get 598.392 So we now have a ratio of 1118.1466 and 598.392. If my diagram is correct they should give us the ratio of Mars and Earth. Let's go and see ... Earth = 12,756.28 / Mars 6,792 = 1.87813 actual measurements and according to Giza ... Earth = 1118.1466 / Mars = 598.392 = 1.8686 according to Giza Checks to .9950 So we have that the difference in distance of Earth and Mars is 1/2 the diameter of 2 Earths meaning 149,598,261 x 2 = 299,196,522 and difference in orbits of Mars at 227,939,100 and Earth at 149,598,261 or 78,340,839 So 2 times difference of Mars and Earth or 156,681,678 = mars And 2 times 149598261 or 299,196,522 = Earth So both the ratio of the planets diameters and their orbits are told in the exact same story. Very nice. Not as good as normal but still pretty clever ... Cheers Don Barone
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Post by Don Barone on Jun 4, 2017 19:19:12 GMT -5
oh dear I also find errors some times ... Case in point ... In this diagram: So it still works for the diameters BUT NOT for the semi major axis' ... Cheers Onward Don Barone
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Post by Don Barone on Jun 7, 2017 8:53:09 GMT -5
Hi all ... well for today's "discussion" ( as one sided as that may be ) we are going back to The Great Pyramid with yet another fresh look at things ... First an article from Nova: Okay so there you have it. Nova says the present height of The Great Pyramid is 449.5 feet high but is that accurate ? Well Peter Tompkins in his book Secrets of the Great Pyramid on a page put down the measurements of the present top of the pyramid and I made an image of it. Here is the that image: Well since we have the "base" of the missing part and we know the slope angle of 7 / 5.5 or 1.27272727 it should be a simple matter to confirm the accuracy of the Nova article: Okay so average base is 215.0 + 214.1 + 224.5 + 217.5 / 4 or 217.75 inches ( x 2) So if 1 / 2 "base" of missing section is 217.75 then the missing height is simply 217.75 x 1.2727272 (7 / 5.5) or 277.16818 inches or 23.10 feet. But wait Nova said 31 feet was missing .... I smell the proverbial rat. Let's see what Wiki says ... " ... 138.8 meters (455 ft) (contemporary) .... " Okay but if height is 5773.5 inches / 12 or 481.125 feet then 481.125 - 455 = 26.125 closer but still not correct. Well so I decided to make my own scale drawing and try to figure out what was going. First we will show the measurements of Petrie: Okay so the very top course measured by Petrie is 5451.8 inches or 454.32 and making Wiki look pretty good but wait we had determined that using the top of The Great Pyramid and the proper angle that distance by Petrie could not be right or if it was Tompkins had to be wrong ... hmmm. So I figured draw my own diagram to scale and here it is ... As you can see I calculated that if Tompkins was correct then the top of the present day pyramid should have been at 5500 inches or 459.32 feet or 266.73 cubits of 20.62 inches. But it isn't ! It is almost 5499.86 - 5451.8 = 48.06 inches or basically 4 feet !!!!!!! Okay so let us assume they are both correct. Then the only thing that allows both of them to be correct is that the angle of The Great Pyramid CAN NOT BE 5.5 to 7 !!!!!! Okay and as we are pondering this another gem came to my attention. It concerned the squaring of the circle and here is the iamge I found online Now sometimes I miss the obvious but one simply has to take the height of The Great Pyramid and draw a circle using center of sqaure as the origin and we have a nice, neat example of the squaring of the circle. But as I was doing that I said to myself ( I do talk to myself quite often when I am working on things ) I said I wonder what the difference is from the edge of the circle to the corner of the square and so I decided to find out. Now most would say The Great Pyramid is simply in the 7 / 5.5 ratio but others claim it is perfect Pi so allowing the perfect Pi we get base as 439.823 ( we have all seen this number a zillion times) but I decided to see what the measurement was from the circle to the corner of the square and got a pleasant surprise. It is simply 1 / 2 the diagonal of sq rt of 439.823 x 439.823 x 2 = 1 / 2 of 622.003611342 or 311.00180567108563729111166930425 - 280 or 31.00180567 AND ... THE CUBE ROOT OF PI !!!!! CUBE ROOT OF PI IS 31.0062766803 SO CHECKING TO 0.99986 IF WE REVERSE IT AND START WITH CUBE ROOT OF PI OR 31.006276680299820175476315067101 THEN ADD IT TO 280.00 WE GET 311.0062766802998201754763150671 THEN TIMES 2 TO TO GET THE DIAGONAL OF OUR SQUARE OF 622.0125533605996403509526301342. We then simply do the math and go 622.01255 squared = 386899.61653817281494118782352492 then divided by 2 to get 193449.80826908640747059391176246 and then sq rooting this to get our sqaure of 439.82929446443924589398779181348
NOW IF WE START WITH PI X 280 X 2 = 1759.2918860102842135390802946365 AND DIVIDE BY 4 GIVES US THE PERFECT PI BASE OF 439.82297150257105338477007365913CHECKS TO: 439.82929446443924589398779181348 AND 439.82297150257105338477007365913------------------------------------------------ 0.999985624 ...... ===================================== I never knew that ... did you ? But the diagram I came across has let more worms out of that damn can. Observe my observation of Pi cubed but note his idea as well. Note his brilliant observation that if we use 1000 times the tan of the angle we get 1111 as a diagonal and 1000 squares the circle ... But his numbers have been fudged to fit so I will post the correct numbers and see what happens. Pi / 4 = 0.7853982 and times 1000 gives us 785.3982 for the base of The Great Pyramid. The diagonal is 785.3982 squared then times 2 and then square rooted for 1110.7207. The difference according to me is Pi cubed so we have 1110.7207 - 785.3982 or 325.3225 and cube root of this is 6.87762 ... Not sure what this number means ... So yet one new way to look at The Great Pyramid : Base = 1000 times Pi / 4 or 785.3982 (219.91 cubits) Height = 1000 !!!!! (280.00 cubits) Diagonal = 1110.7 ( 1111 rounded) (311.00 cubits) Nice !!!!!! Cheers until next time. Don Barone
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Post by Don Barone on Jun 7, 2017 10:04:24 GMT -5
Okay taking this new way of looking at The Great Pyramid: We can come up with this. It is my contention that the height of the Great Pyramid is 5773.50 inches or sq rt of 3 then / 3 then times 10,000 Using our new found system we find that since height = 1000 the diagonal ( I will use 10 / 9 or 1.1111111111 .... ) would be 5773.50 x 1.111111 and we get .... 6415.003Now you are probably scratching your head and wondering why I high lighted this number and made it green ,,, well for that answer we must return to The Giza Plateau ... so let's go ! And here we are ... Now you must understand that all these numbers we are generating are pure numbers. There are no feet and no inches and no cubits YET ! But this holds yet another major key to understanding Giza. For that you must go back to my work on The Power of Times Ten Divided by Pi It was this work where I pointed out the unbelievable relationship between G1 and G3 when I pointed out that when G1 and G3 were added together such as 9068.2 + 4153.8 we got 13,222 and we found unbelievably that when G3 was divided into the total we got the inverse of Pi. Example 13222 / 4153.8 = 3.183109442 and inverse and we get 0.31415822 and times 10 = 3.1415822 and checks to Pi to 0.999997 ... A PERFECT MATCH !!!!!!!!!!!!! MIND BOGGLING !!!!!! MIND NUMBING !!!!!! AMAZING !!!!! Why all the excitement you might say well ... and this is going to rank up there with the very best thing I have ever discovered as the simple fact of calling height of The Great Pyramid sq rt of 3 then divided by 3 then multiplied by 10,000 to get 5773.50 and using the 10 / 9 ratio in the pyramid height to diagonal ratio to get 6415.00 we have defined how many cubits to use and it is done so beautifully and amazingly. For we now know that G1 + G3 = 1 / PI x 10 or 3.183098862 but using our 10/9 ratio of 10000 time 1 / 3rd of sq rt of 3 we got 6415.00. So we finally have this ... 6415 / 3.183098862 = 2015.3 and remainder = 4399.7 and when we divide by 10 we get 201.53 and 439.97 and defines what logically would be the number of cubits or any units to design the pyramids to be. Simply a stunning discovery !!!!!! So now we have found the lengths of the pyramids and the real reason why. For the beauty of this solution is that no matter what unit is used be it feet, cubit or meter or "Warwicks" it is will always be 440 by 280 of the particular unit chosen and has never been about the number of cubits but the number generated by numbers that have no units ... simple mathematical numbers that would work no matter what unit is chosen. So we could build it 440 feet by 280 feet or 440 meters by 280 meters it is not important ... ONLY THE RATIOS AS DEFINED FROM SQ RT OF 3 AND PI ARE IMPORTANT. It is beyond belief !!!!!!! but is has to be 440 and 201.5 because they are defined in the math. I am honestly stunned .... Amazed Don Barone
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Post by Don Barone on Jun 7, 2017 11:10:03 GMT -5
Okay let's try to put Humpty Dumpty together .... Here is our starting point where I found again unbelievably that the number of "future inches" is defined in a very simple formula: Okay what this diagram shows is that when you have a perimeter of sq rt of 2 x 10,000 or 1414.21356 "units" each side is 1 / 4 of sq rt of 2 so that would make the radius of the circle diagonal x Pi or .35355 x .35355 = 0.5 x Pi = 1.570796327 x 1000 = 1570.796 if we take this and divide by sq rt of 3 or 1.73205 we get 906.89968 and times 10 gives us exactly then number of "inches" in The Great Pyramid. So we have managed to define a number for The Great Pyramid of 9068.9968 "whatevers" without actually measuring anything yet. So let's go with what we have so far. 9068.9968 and 1507.7963 and 1.73205 So 1.5077963 ( 1 / 2 of Pi ) divided into 9068.9968 = 5773.502678 and is sq rt of 3 / 3 x 10,000 and still we have used no inches, no cubits, no feet no nothing, Just sq rt of 3 and Pi. So we have a) = 5773.05 and B) = 9068.9968 and of course by definition these are in the ratio of Pi. So lets go visit our last post. According to me I determined that of our two pyramids one had to be 440 "units" and the other had to be 201.50 "units" So using that train of thought the ratio of 440 to 9068.9968 is 20.6113563636 But we also know that pyramid by definition the builders tried to incorporate Pi and so determined that a + b = 1 / Pi or 3.1831 or "440 + 201.5 = 9068.9968 + ?? = 3.1831 So if total is 3.1831 then one pyramid had to be 1 and the other had to be 2.1831 so let us take 9068.9968 as 2.1831 and for "1" we get 9068.9968 / 2.1831 = 4153.19 So Pyramid "a" = 9068.9968 "units" and Pyramid "b" = 4153.19 so let us go now to our 6415.00 number generated from 10/9 ths of height and we get this: 6415.00 = 3.1831 1 = 6415 / 3.1831 = 2015.3 / 10 = 201.53 so pyramid "b" = 201.53 "other units" 2 = 6415 - 2015.3 = 4399.669 / 10 = 439.9669 "other units" So we have manged to figure out the pyramids ( at least G1 and G3 ) without ever having to lift a ruler or take a measurement. Nice and simple. Did I hear someone say "KISS" ? Cheers Don Barone
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Post by Don Barone on Jun 7, 2017 16:06:17 GMT -5
A hint of where we are going to explore next ... The mathematical constant "e" is times 12 eg: 2.718281828459 x 12 = 32.6194 Diameters
2.235078 = 1 Mercury = 2.1831 Venus = 5.41534 Earth = 5.70731 Mars = 3.03980 Ceres = Jupiter = 63.9727 ( close to 64 ) Saturn = 53.9292 Uranus = 22.87078 Neptune = 22.17909 Cheers Don Barone
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Post by Don Barone on Jun 7, 2017 16:54:36 GMT -5
Just some thoughts as I have to go out tonight to celebrate my daughter's 24th birthday - yes that was the little one known as Alice who was waving her finger at Graham 17.50 = 1 192.5 = 11 = Pharaoh 175.00 = 10 168.00 = 9.6 = Man 157.5 = 9.00 = Woman 200.00 = 11.42857142 210.00 = 12 = ? 227.50 = 13 = ? 245.00 = 14 262.50 = 15 280.00 = 16 = height of The Great Pyramid 315.00 = 18 332.50 = 19 350.00 = 20 367.50 = 21 385.00 = 22 402.50 = 23 420.00 = 24 = Base of Red Pyramid IT SEEMS 9.6 IS A LOT MORE USEFUL THAT 11 420 or 24 / 9.6 = 2.5 280 or 16 / 9.6 = 1.666666667 210.00 or 12 / 9.6 = 1.25 And 2.618033988 or Phi squared times Man of 9.6 = 25.1331263 and times 17.50 = 439.82971 and perfect Pi to accuracy of 0.999985 Cheers Don Barone
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Post by Don Barone on Jun 7, 2017 21:46:22 GMT -5
Consider this ...
Diameter of Mercury = 4879.4 Diameter of Mars = 6794.4
Total of the three pyramid bases in "cubits" is 439.823 + 411.00 + 201.53 = 1052.353
Ratio of Mars to Mercury is 6794.4 / 4879.4 = 1.3924663
1052.353 / 1.3924663 = 755.74756
If we allow "feet" we get 755.74756 x 12 = 9068.9707 and my value is 9068.9968
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Start with 9068.9968 a number that was generated by sq rt of 3 and Pi and divide by 12 and we get 9068.9968 / 12 = 755.74973333333333333333333333333
755.74973333333333333333333333333 x Mars / Mercury = 755.74973333333333333333333333333 x 6794.4 or 5134865.98816 and divide by 4879.4 (Mercury) = 1052.3560 --- checks for 0.999997
Therefore:
755.7497333 = Mercury and base of The Great Pyramid in feet and 1052.3560 = Mars and the total of all the bases in "cubits" but generated from 5773.50 x 1.111111111111 / 10
EXACTLY !!!!!!!!!!!!!!!!!!!!!!!
Nice !
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Cheers Don Barone
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Post by Charlotte on Jun 8, 2017 9:35:07 GMT -5
Surfing a loooong wave, turning the board, sailing through a tunnel and out again, Don,
"The Pyramids of Egypt never let you rest", maybe they, and the Plateau, are the elusive 'Hall of Records'.
I think it would be rewarding for you to visit the sacred place, sit alone (your guide at a respectful distance) high upon the plateau at the time 'the gods gather in the day', the holy atmosphere itself will impose silence of thought and by virtue of their guarded power, the gods, whose design this Wonder of the World was, you wondered, will take you into the mystic.
The world is waiting for an answer as to who created this wonder.
Cheers and safe surfing.
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Post by Don Barone on Jun 8, 2017 18:15:26 GMT -5
Hi Charlotte ... my research is now focusing on trying to solve all of this, Giza, The Solar System, Man, Woman and "Pharaoh" using just simple equations and only Pi, sq rt of 3, sq rt of 2 and 9, 9.6, 10, 11 and any multiple or divisions of these numbers. I am trying to ignore feet, inches, meters and cubits but what I seem to be finding is that the units we use are themselves a product of this research and so I am starting to think that maybe "The Royal Cubit" is not really a measurement per se but may be simply a ratio of a couple of equations that make up the pyramid in question and thus since different pyramids may follow different rules the ratio or "Royal Cubit" could change and may perhaps be a reason there are many different values for "The Royal Cubit" .
The best and starting point in all of this is this:
Pi --- / √3 = 0.90689968 and miraculously once we multiply by 10,000 we get the number of the units we call inches in the base of The Great Pyramid 2 Many people have missed the significance of this discovery. The significance is that by using a very simple formula and only Pi and sq rt of 3 we have managed to somehow come up with the precise number of what we call inches in the base of The Great Pyramid. The beauty of this is that it could be anything. It could be digits, or centimeters or even miles there will always be 9068.9968 of them in the base and 5773.5027 of them in the height. And then there was our"
√3 / 3 and times 10,000 and then multiplying this by 10/9ths or 1.1111111111 to get amazingly 6415.00 and totaling the width in "cubits" of 440 and 201.50 and G1 and G3 but so far we have not really used a measurement system yet. We have just used the values of square root of 3 and a fraction 10/9 ths and what we get is very interesting. For The Great Pyramid we get, as shown in earlier posts, 440 and 201.5. so therefore a ratio between
Pi --- / √3 x 1000 then times 10/9ths gives us for The Great Pyramid 9068.9968 as one unit value and another of 440.00 2
As a ratio we get 9068.9968 / 440 and we get a ratio of 20.611356364 so some might call this a unit of measure and perhaps maybe even "The Royal Cubit" but as I have demonstrated it really is simply a ratio of two numbers (9068.9968 and 440.00) that have been defined by the square root of 3. Since there may be different formulae involved in the other pyramids it is possible this ratio may change and thus so might "The Royal Cubit"
Just a thought for tonight as I press onward ...
Cheers Don Barone
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Post by Don Barone on Jun 8, 2017 20:05:18 GMT -5
Okay I think you are going to enjoy this one ... I know I did. I thought I had done every possible combination of numbers at Giza but here is one I missed. I was looking at this image: and started to think I had never really played around with G2 and G3 or 411 and 201.53 and so I decided to see what the diagonal would equal when I did this. Here is the starting diagram ... The number that was revealed to me was , I know I have overused this word but was STUNNING AND AMAZING ! Because of the number I got I decided to use 612.53 AS A 1 /2 the base instead of the entire base and got this diagram ... . And here is the image with the diagonal ... Now folks I have been working on and at Giza for many, many years and had thought I had tried all possible combinations but I obviously had not done this one for what do you suppose the diagonal equals ? Well let's call in our expert Pythagoras who tells us if we square each side and multiply by 2 and take the sqaure root remember a² + b² = c² So we have 1225.06² + 1225.06² = √ x Diagonal = √1225.06² + 1225.06² Diagonal = √1500772.0036 + 1500772.0036 Diagonal = √3001544.0072 Now believe me there are no cooked numbers. You all have seen how I have got them so be amazed as once again Giza blows our minds. THE DIAGONAL = 1732.50 But now think of some of my earlier work and we find that "Mercury" or "440" is in a DIRECT AND PERFECT RATIO TO MARS AND THE DIAGONAL IT PRODUCES !!!!!!! Observe ... Giza never disappoints ! Cheers Don Barone
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Post by Don Barone on Jun 8, 2017 20:39:31 GMT -5
And one final image for all those who have tried to find a nice neat way to place Venus on Our Solar System at Giza. Just to show you the math is correct. Mercury is 57,909,050 km and Venus is 108,208,000 km so ratio is 1:1.8685853 since Mercury is 440 in our diagram Venus would be 440 x 1.8685853 or 822.18 ( to fit exactly we would need Mercury to equal 439.91). Regardless may I present to you the formerly hidden planet Venus ... Cheers Don Barone
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Post by Don Barone on Jun 8, 2017 21:05:10 GMT -5
Okay this really is my last imAge for tonight. Please remember this is a to scale representation of the distances that the planets are from The Sun AND NOT their diameters !!! LARGER IMAGECheers Don Barone
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