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Post by Don Barone on May 17, 2017 19:25:38 GMT -5
Hi all ... Well I honestly try to stay on one topic but I just can't do it ... Case in point Saqqara ... Legended as the first pyramid of the genius that was Imhotep. Now I had looked at this enclosure in the past and had tried to convince people Pi was involved and if you go to Ma'at you can read all about it but tonight ... a break through of the enlightened kind as it all became crystal clear and the genius of Imhotep is on display for all to see. I was going through some posts at Ma'at and lobo-hotei made this comment on my theories of sq rt of 5 ... Well as luck would have it I had just completed this diagram and posted it to Ma'at ... Well I have some bad news for you ... The outer perimeter is of the form that the short side is 1/2 the long side or in other words 1 to 2 and sorry lobo ... the diagonal is indeed the square root of 5. But I have discovered more for you ... Allow me to quote: From this website : And becasue I know every one loves my pictures I put the answer in picture form ... Yes not only do we have the 1, 2 and sq rt triangle BUT WE ALSO HAVE THE 1, sq rt of 3 (1.73205) and 2 triangle ... I know, I know just a co-incidence ... LOL Cheers Don Barone But I wasn't quite done for the evening as I continued to torture the numbers and came away with this final drawing ... And just one last one to make everyone's day ... this one is very, very interesting ... they even managed to slip in the NOTE CORRECTED TO READ 5.5 / 7 (7 / 11) ratio and the 3, 4 and 5 sided triangle as well. ... It is perfection indeed. A work of art from The Master Builder himself ... Quite clever actually ) Okay this shows that the side is 573.765 and is 4 units and the long side is 8 units ... It shows that the distance from The Great Court to the right side is 5 units ... it shows that the SHORT base of The Step Pyramid is 3 units ... It probably shows more but is is time to give my brain a rest ... Cheers Don Barone
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Post by Don Barone on May 17, 2017 19:39:00 GMT -5
And just to get the height in the ball game we have it at 62.18 meters or 2448.03 inches or 118.72 cubits which makes it .... 208.34 (3 units) / 118.72 (?) = 1.75(5) To equal 1.75 exactly we need 119.05 cubits 62.35 meters ?? 1.76 = 118.375 = 62.00 meters exactly (61.9987) Still working on the longer of the two bases .... Cheers Don Barone
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Post by Don Barone on May 17, 2017 20:05:49 GMT -5
Okay so we have this side line to the main body .... 5.5 / 7 = 0.7857142857 x 1000 = 785.71 ... Okay let's bring our old friend Mars back for a visit ... Remember Mars at 686.98 days ? We11 suppose we were to divide 785.71 NOW REMEMBER WHERE WE GOT THIS NUMBER and divide it by 686.98 well we get 785.71 / 686.98 or 1.1437222 ... and what do you suppose the significance of that number is ? Well it is almost precisely 1 / 7th of 8 .
So what do we have now ? Well we have the orbital period of Mars (686.98 days) being virtually exactly 7/8ths of 1000 times the sine of 5.5 / 7
So 686.98 / 7 = 98.14 x 8 = 785.12 Not exactly but still pretty interesting
Perfect angle is 51.864 as opposed to 51.842
Worth considering I should think ...
785.714 / 686.98 = 1.1437218 x 7 = 8.006
Reasonable ...
Cheers Don Barone
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Post by Don Barone on May 17, 2017 20:41:11 GMT -5
Tough when your brain won't stop ... I had been thinking about the height of Pharaoh and Man and Woman and how they seemed to fit rather nicely with Pharaoh at 20.62 , Man at 18.00 and Woman at 16.875 ... but I had been formulating an idea based on a circle and Man inside and totalling 72 inches and so it was I played with Man at 72 inches and woman became 67.5 and it was nice but not of the earth shattering kind we are beginning to expect so the next I went to 90 inches and dividing by 18 we get 5 and 5 x 16.875 = 84.375 and again not a number that jumped up and slapped me in the face and then as always ( I don't where they come from) I decided to use 90 AS PHARAOH ! And this is what I got ... 90 divided by 20.62 (4.3647) and multiplied by 16.875 = 73.65422 a probable meaningless number to most of you but it looked very familiar to me as I knew I had seen it or a number close many times so straight to this website I went ... and found as I had thought that the number of inches in a hundred digits was 73.6352 ... but I like exact and this wasn't exact ... we had: 73.65422 and 73.6352 So I had already had an inkling what to do next so I simply divided 73.6352 (the actual number of inches in 100 Egyptian digits by 16.875 and got 4.36356740740741 and this time instead of multiplying by 20.62 I multiplied by .... are you already there ... do you know what I did ? Well I multiplied it by 20.625 ! and needless to tell you that 20.625 x 4.36356740740741 = 89.9986 and except for the rounding probably is exactly 90 ... So "Woman" is also equal to the number of inches in 100 Egyptian digits when ... PHARAOH IS EQUAL TO 90 INCHES AND 20.625 INCHES !!!!!!!!!!
And never count man out for if 90 inches = Pharaoh and 20.625 "Man" equals 78.5454545 AND IF WE DIVIDE BY 100 WE GET 0.785454545 AND THAT MY FRIENDS IS THE 1 / TAN OF 51.8519760755 WHILE 1 / TAN OF PI IS 51.85397401278 AND CHECKS TO WITHIN 0.99996 Very nice days work I should think and time for a rum and coke Cheers Don Barone
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Post by Don Barone on May 17, 2017 21:45:04 GMT -5
Well my 20.625 as Pharaoh and 18 as Man and 16.875 as Woman seemed to be able to solve anything so I figured before I went to bed (the rum and coke was great by the way) maybe they could solve the squaring of the circle problem and so it was I ended up with this diagram ... life is good And now for the icing .... So the Pharaoh at 20.625 x Pi = 64.79535 while 9/10th of "Man" at 18 / 10 = 1.8 x 9 = 16.2 Each side of square is 16.2 ... 16.2 x 4 = 64.8 ... CHECKS FOR 0.99993
No offence but this discovery is bloody brilliant !!!!!!!Cheers Don Barone
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Post by Don Barone on May 18, 2017 18:24:25 GMT -5
Good evening all. Well I am sure there are many of you out there that feel perhaps that last little bit of reasoning was far fetched ... but was it ? Man is inherently taller than Woman. I went online and they claimed it was becasue "Taller" men were more attractive to females and this bred taller men .. so I ask why were the women of these unions not taller as well. Why do women remain shorter than men ? Think upon it while I offer my two cents. In my opinion it is in "the genes" so to speak but I believe it goes much deeper than that. I believe that the absolute fabric of reality dictated the dimension of Man and Woman and these same dictates ... HOLD TRUE FOR THE SOLAR SYSTEM ! I am just starting to explore these possibilities but here is one I found but first a recap:
WOMAN = 157.5 = 16.875 = 62.008 inches = 3.006 cubits (@ 20.625 inches per cubit) MAN = 168.00 = 18 = 66 inches
So one could say that the average height of a woman in Ancient Egypt was 3 cubits + or - and I guess it is just an accident Mother Earth is the third planet from The Sun ... but there is a bit more, not much more, but a bit. 62 / 16.875 = 3.6740741 ... so what you might say ... well ... I always look to the solar system with any number I find and checking, this is what I found.
Diameter of Earth in kilometres = 12756.28 (equatorial)
12756.28 / 3.6740741 = 3471.97 km
POLAR DIAMETER OF THE MOON = 3472 KILOMETRES ...
and on and on it goes ... where it will stop .... nobody knows
And this one found just before I was about to click to post ...
12756.28 / 16.875 = 755.93 and if claim feet we have in inches ... 9071.1 ... BASE OF THE GREAT PYRAMID IN INCHES !
AND THIS ONE WE ALREADY FOUND 12756.28 / 157.5 = 80.99 ( 9 SQUARED OR 81 !)
AND FINALLY THIS ONE ... MEAN DIAMETER OF EARTH = 12742 ... AND 12742 / 62 = 205.516 AND THE PRECISE HALF BASE OF G2
Awful lot of co-incidences this time around ...
Cheers Don Barone
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Post by Don Barone on May 18, 2017 18:57:43 GMT -5
And just now a simple but elegant break through in our understanding of what is going on ....
For 20.625 / 16.875 = 1.22222 and the numbers that give us that ratio are none other than ...
11 AND 9
So it would now appear that "Woman" is 9 and "God" or "Pharaoh" is 11
Well I am sure we can carry the ball a bit further from here ...
Cheers Don Barone
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Post by Don Barone on May 19, 2017 18:40:43 GMT -5
Anyway another little side trip. I guess something has always bothered me about my work at Giza. If one is to believe my theory that the inch, metre and foot are to be found at Giza and really the chance of The Ancient Builders using a modern foot and modern inch and modern metre back then are slim to none then the only "logical" conclusion is that it was built by a "modern" man" ... and unless we want to suggest Imhotep was a time traveller then it would seem that it is highly unlikely that I truly found what I thought I found and there had to be another answer ... and so it was this morning as I was looking again at the beautiful image of the possible solving of The Sakkara Complex and looking at the north and south side of 523.76 cubits a thought occurred to me ... I kept asking myself if I had ever come across a ratio or anything that could help prove I was right and then I had yet another insight when I realized sure 523.76 is 1000 times the number of millimetres in a cubit but since millimetres did not exist in The 3rd Dynasty there had to be another reason for this 523.76 and then I think I finally got it. All along I have always claimed it is in the ratios that the answer lies and the actual measurement is not important and so it was back to the solar system we go and call once again upon Mars and Earth --- Sekhmet and Geb or Set and Osiris ?
Anyway the first thing I decided to do was to finally ( I honestly don't know why I had never done this in over 18 years of research) to change all the distances of the planets of their semi major axis' into CUBITS !
They are:
Mercury: 110539823431 cubits Venus: 206554865187 cubits Earth: 285560984968 cubits Mars: 435102075877 cubits Ceres: 790266762110 cubits Jupiter: 1486131615827 cubits Saturn: 2736243131370 cubits Uranus: 5491155491082 cubits Neptune: 8596408804380 cubits Pluto: 11212598428674 cubits
So remember "kilometres" NO LONGER EXIST !!!!!!!!!
Okay then where will we get 523.76 cubits for the north and south wall at Sakkara ?
Well that is where ratios come in for: (all measured in semi major axis'"
Mars - Earth / Earth x 1000 = 523.76 !!!!!!!!!!!!!!!! (actually 523.67)
435102075877 - 285560984968 = Now before I put this number down I honestly had no idea this is what it would equal. In fact I did it twice because I thought I had made a mistake and posted the wrong number but believe it or mot the difference in cubits between Mars and Earth = (approx) the semi major axis of Earth IN KILOMETRES !!!!! FOR THE ANSWER IS 149541090909 OR CHECKING WITHIN .9996 INTERESTING ... but now we take that number of cubits and divide it into the number of cubits to Earth and we get 149541090909 / 285560984968 = 0.523675 and times a 1000 = 523.675
But there is one more possibility that it could be but again that calls upon the Ancients to know the unknowable and so it is that (10 x Pi) / 6 = 523.598 ... I have used 6 because Sakkara is north 1, west 2, south 1 and east 2 giving total = 6
So the point I am making here is that even using cubits the ratio still holds true .... HOWEVER ... how can we ever hope to figure out how they knew the distances to the planets. It has to be hidden in the geometry and I will find it !
Cheers Don Barone
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Post by Don Barone on May 19, 2017 19:12:26 GMT -5
Hi all I hope you are enjoying yourselves ... I know I am ! Well I kept think I was missing something so I decided to check the ancient Egyptian measurements to see if there was one that was being overlooked and all were accounted for except .... THE POLE !!!!!!!! And interestingly doesn't it say in almost all the writing that the Egyptians used a knotted rope and POLES ! And the Pole was 62 cm (and isn't the height of Woman 62 inches and the height of The Step Pyramid at Sakkara 62 metres ) or 32 digits and since a cubit was 28 digits this makes The Pole 32/28 or 1.142857143 Now the sharp eyed among you will realize you have seen this ratio and number before.... We shall call it Mars revisited yet again for 5.5 / 7 = 0.78571 x 1000 = 785.71 and divided by number of days in a Martian Year (which the ancients would have counted same as us) of 686.98 = 1.1437222 and checking for 1.142857143 / 1.1437222 = 0.9992 So if you wanted to you could call The Pole or 32 digits 1000 x 5.5/7 and Mars = 28 or maybe 280 height of The Great Pyramid ... but I might suggest something else ... we have the height = 280 cubits (280 digits if we might) and in Poles this would be 280 x 28 / 32 = 245 ... so in this scenario Mars would be 280 ... regardless the ratio is 8 to 7 ! for 1.142857143 x 7 = 8.000 .... So I would suggest that The Pole played a very important role in all aspects of unit length measurement in Ancient Egypt ... Cheers Don Barone NOTE EDIT: Not sure how I do these things but a Pole was only 60 cm NOT 62
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Post by Don Barone on May 19, 2017 19:26:23 GMT -5
Just thought you might like this: Using distance to Mercury in cubits as a tan we get 1.10539823 and lo and behold it gives us the angle 47.865889 and of course we know the speed of Mercury is clocked at 47.87 km per second squared. But we had seen this elsewhere when we calculated the diagonal of The Great Pyramid and got 440 squared x 2 and sq rooted to give us 622.254 and divided by 13 gives us 47.8657 ... AN EXACT MATCH !!!!!!! Wonderful ... but what can it mean ?
Cheers Don Barone
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Post by Don Barone on May 19, 2017 20:35:27 GMT -5
Before going on I will post this .... from this websiteAnd height of Washington Monument is 555 feet ! But why mention this ... well I decided to add up our Man, Woman, God numbers and see what they totalled and they totalled ... for what it may be worth .... 55.5 !!!!!!!!! Kiss an angel good morning I always say Cheers Don Barone
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Post by Don Barone on May 19, 2017 21:31:55 GMT -5
Last one tonight ...
God / Man x Pi = Infinity ?
20.625 / 18 = 1.1458333 x Pi = 3.5997 (3.6 or 360 could represent circle or infinity ? Checks 0.99993)
Cheers ...
Don Barone
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Post by Don Barone on May 21, 2017 7:26:59 GMT -5
Good morning all ... some interesting developments since last I saw you. As I mentioned earlier one of the main stumbling blocks with my theories is that I was using inches, feet and metres as well as cubits to convey my ideas when in reality it was usually just the ratio that proved the point. Here is a typical valid argument to my theories posted on Ma'at a while ago ... I have to say that other than a belief in time travel and time travellers it remained seemingly impossible for all these measurements system to have been used. I was convinced there had to be a simple, remember my theory of The Creator and "The KISS Principle" , answer and system that The Ancients used to explain our solar system and the more I pondered our new found 16.875 (Woman) and 18 (Man) and 20.625 (Pharaoh or God ) the more I became convinced that a simple answer lay just outside my reach and grasp and understanding. Could I unlock the secret of The Ancients ... well you tell me .. One of the most difficult things to do in this new research avenue of mine was to think ONLY in cubits ! I had to forget about inches and feet and metres and use only cubits and palms and digits and Poles if necessary. It was a lot harder than it appears to be. The first exercise I did as I had noted was calculate the distances to the planets using cubits, Here again are those numbers : Mercury: 110539823.431 cubits Venus: 206554865.187 cubits Earth: 285560984.968 cubits Mars: 435102075.877 cubits Ceres: 790266762.110 cubits Jupiter: 1486131615.827 cubits Saturn: 2736243131.370 cubits Uranus: 5491155491.082 cubits Neptune: 8596408804.380 cubits Pluto: 11212598428.674 cubits And I have divided by 1000 to get a sort of "kilocubit" to correspond to a kilometre ... Okay so that was a starting point and so I decided to see what the difference was in distances between the planets So between Ceres and Mars we have 790266762.110 cubits - 435102075.877 cubits = 355,164,686.233 So between Mars and Earth we have 435102075.877 cubits - 285560984.968 = 149,541,090.909 So between Earth and Venus we have 285560984.968 - 206554865.187 = 79,006,119.781 and finally between Venus and Mercury we have 206554865.187 - 110539823.431 = 96,015,041.756 Nothing immediately jumps out at you other than maybe 110539823 could be 1/4th of 440 and 206654865 of Venus is close to a cubit at 20.625 but although I sensed something was there I for the moment could not put my finger on it. And then I decided to try something mainly because I was convinced that the answers had to be simple and the The Ancients could figure it out using just their understanding of mathematics at the time and so it was that I chose 7 and 11, the two lucky numbers on the dice and the main numbers designed into The Great Pyramid to see if this could help me solve the problem .... But in among these ideas I also had long been formulating an idea and trying to come to grips why the inner planets behave differently than the outer planets. That Bode's Law seems to abandon the outer planets ... I have always been troubled by that. If there was a Creative design to the solar system it had to be simple and IT HAD TO APPLY TO ALL PLANETS ... and then A Tsunami of understanding washed over me and I finally saw the answer ... It had been staring at us all along ... it was simply .... As above ... so below. The trick as I have finally learned is knowing what that may mean. Here is what I have concluded. It goes back to the Biblical stories of Genesis where God separates the waters ... " ... And God made the firmament, and divided the waters which were under the firmament from the waters which were above the firmament: and it was so. " and also " ... So in some of my earlier work I have shown how this rainbow covenant of God could be referring to the asteroid belt and specifically Ceres and so it was that as I have always suspected that Ceres was a dividing line of sorts between the inner and outer planets , the inner rocky and hard and relatively small while the outer were giants and gaseous ... yet I remained convinced there had to be a connection and I think I have finally found it for above and below refers to the inner versus the outer planets and the line to define "above" and "below" is Ceres so here is a diagram to illustrate my point ... So I reasoned if this is true then the formula for solving the "Below" had to be the same as the formula to solve "The Above" and that is what our next post will deal with ... Cheers Don Barone
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Post by Charlotte on May 21, 2017 7:31:23 GMT -5
Glad you're having fun, Don, as they say: if I could understand your theories I'd support you. Cheers!
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Post by Don Barone on May 21, 2017 7:45:50 GMT -5
Glad you're having fun, Don, as they say: if I could understand your theories I'd support you. Cheers! Hi Charlotte ... "Keep it simple stupid" and always in the back of my mind the words spoken to Enoch ... "I have made my design to be so simple ( or easy) anyone can follow it." I think I am narrowing in on that final plan ... I have a feeling when I post the final simple result of what I have uncovered all will be able to finally see it ... ESPECIALLY WHEN THEY LOOK AT THE GREAT PYRAMID !!!!! Cheers Don Barone
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Post by Don Barone on May 21, 2017 9:05:09 GMT -5
Okay onward ... I have and everyone else has always used either Mercury or Earth as a starting point to calculate ratios and such when dealing with our solar system and therein lies the inherent error in all of our work. WE WERE STARTING AT THE WRONG END !!!!!!!! Okay please clarify this Don. Okay I will ... But first we have to grant a bit of leeway and concede that some of the gods of Ancient Egypt were indeed meant to represent the planets ... Good example being Osiris representing Earth and then there is Bastet: representing to some Venus but to others (like myself) Mars as I believe that the red disc is showing Mars and not The Sun And so it was that once again I took an unknowing step outside the box and decided to try to figure out a pattern .... STARTING WITH MARS !!!!!!The first thing I had to do was to break down the distance to the planets in simple numbers and so it was I decided to start with Mars and assign it certain easy whole numbers and see how the other distances to the planets fit in. So for example lets say distance to Mars is represented by 26 units so then each unit would be 1/26th of our distance of 435102075.877 cubits or now 1 units is 435102075.877 cubits/ 26 = 16734695.226 so we can now ignore all those unwieldy numbers and just concentrate on 26 for Mars. So Earth would be 285560984.968 / 16734695.226 = 17.06 so Venus would be 206554865.187 / 16734695.226 = 12.35 and lastly Mercury would equal 110539823.431 / 16734695.226 = 6.605 ... so now ignoring everything else including kilometres, metres, feet, and inches and everything we get the solar system broken down into bite size pieces of: Mars = 26 Earth = 17.06 Venus = 12.35 Mercury = 6.605 Well now that was just an example of what I did to get the results that follow ... the key to solving the cipher is finding out what value to assign to Mars ... so you will forgive me for going direct to my old stand by ... The Great Pyramid and choosing as a starting value .... 11 !
Okay so I want to emphasize what we have done here ... no longer do you have to worry about how many kilometres it is to Mars or how many miles or how many cubits ... it is now only 11 units ... I think we can all remember that ... So now let's calculate the other planets ... so if Mars = 11 then 1 unit would be 435102075.877 cubits / 11 or 39554734.170 so each unit or 1 = 39554734.170 so now let's calculate the other planets ... Mars = 11 Earth = 285560984.968 / 39554734.17 = 7.219 Venus = 206554865.187 / 39554734.17 = 5.222 Mercury = 110539823.431 / 39554734.17 = 2.7946 So if the base is Mars or 4 x 11 = 44 Earth = 28.876 Venus = 20.888 Mercury = 11.1784 So unfortunately not as close as I would have liked it to be: Mars = 11 Earth = 7 Venus = 5.5 Mercury = 2.8 But I think we are on the right path ... So now let's see what the outer or above planets can tell us ... I am going to switch back to kilometres because I have them basically memorized ... Neptune = 4,502,428,637.5 Uranus = 2,876,679,082 Saturn = 1,433,449,370 Jupiter = 778,547,200 Ceres = 414,001,000 Okay let's try that exercise again but this time we will start at Neptune and call it 440 (44 x 10) units or base of The Great Pyramid. So one unit now equals 4,502,428,637.5 / 440 or 10232792.358 ... so 1 unit = 10232792.358 so now let's solve for the rest of the outer planets ... Uranus = 2,876,679,082 / 10232792.358 = 281.12 (height of Great Pyramid = 280) Saturn = 1,433,449,370 / 10232792.358 = 140.08 ( or 1/2 height of Great Pyramid) Jupiter = 778,547,200 / 10232792.358 = 76.08 (or ?? = King's Chamber ?? ) Ceres = 414,001,000 / 10232792.358 = 40.46 ( or = Queen's Chamber ?? ) Okay simplifying this we have Base of The Great pyramid = Neptune Height of The Great Pyramid = Uranus 1/2 height of The Great Pyramid = Saturn King's Chamber = Jupiter Queen's Chamber = Ceres ... A nice starting point for further research ,,, So what is the net result of this ...and how does it relate to how the Ancients maybe having known the distances to the planets ... well to get the results that we do eventually get for our outer planets we get these results for one simple reason ... we have used a Pyramid or really a triangle of base 11 and height 7 and within this simple of simple triangles we can find all the distances to the planets ... oh not exact but certainly close enough for their purposes ... So in my opinion this is how they knew the distances to the planets ... somehow they figured out it was all in a simple formula and so they designed it into The Great Pyramid .... Nice and neat and .... SIMPLE !!!!!! Cheers and can you see it now Charlotte ? Don Barone
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Post by Don Barone on May 21, 2017 9:31:46 GMT -5
The one picture is worth a thousand words route ... I have shown Jupiter at the place where the shafts meet ... it is as good a guess as any to make it fit ... Cheers Don Barone
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Post by Don Barone on May 21, 2017 10:38:41 GMT -5
Okay let's go back to some of my other theories and use The "KISS" Principle to solve them. If we take the distance to Saturn we find that the distance to Mars x 2 x Pi checks almost exactly, Case in point" Distance to Saturn is 1,433,449,370, distance to Mars = 227,939,100 so we have 227,939,100 x 2 x Pi and we get 455878200 x Pi = 1,432,183,604 So how can we apply that to our 11 by 7 triangle ? We let's start this time with Mars = 70 or basically 1/4th of the height of The Great Pyramid so following our formula we would have 70 x 2 x Pi to get Jupiter and we find that Jupiter then equals 439.823 ... and as fate would degree an exact match for the base of our Great Pyramid ... Nice ... And we did not have to know anything other than the Pi triangle ... So again we can see that it was of no value to us to need to know the distances other than 70 for Mars as once again The Great Pyramid or 11 by 7 triangle (Great Pyramid) reveals the answers ... Another way to look at it is to let Mars = 280 (height of Great Pyramid) x 2 x Pi and we have Saturn = to 280 x 2 x Pi or 1759.29 and perimeter of the Great Pyramid is of course 4 x 440 or 1760.00 so once again The Great Pyramid which is simply an 11 by 7 triangle gives us the answer of the relationship between Mars and Jupiter And conversely we have if height is Jupiter ... King's Chamber = Mars ... case in point 280 (height of Great Pyramid) / 82.09 (height of King's Chamber) = 3.410890486052 and if we multiply this by semi major axis distance to Mars of 227,939,100 we get 3.410890486052 x 227,939,100 or 777,475,308 here is what Petrie has for the floor .... actual floor 1691.4 to 1693.7 ± .6 above pavement So to make The Great Pyramid exact we would get 778,547,200 (distance to Jupiter) / 227,939,100 (distance to Mars) = 3.41559302463 and divided into 280 gives us 81.98 or x 20.62 inches = 1690.4 or totally within Petrie's tolerances so once again a simple 11 by 7 triangle gives us the difference between Jupiter and Mars with height being Jupiter and King's Chamber being Mars ... Still working on "The Queen's Chamber" Cheers Don Barone
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Post by Don Barone on May 21, 2017 12:40:02 GMT -5
Okay here is some further explorations at The Great Pyramid using some old ideas and some new ... Here is diagram #1) and here is diagram #2) where I have drawn a vertical line through the centre of our pyramid and then a line at where the shafts would exit or 154 cubits Next I have drawn a rectangle enclosing The Great Pyramid as shown in Diagram #3) In Diagram #4) I have shown a triangles using 154 as height and 220 as a base ... In diagram #5) I have shown the ratio of 154 to 280 ... And in Diagram 6) I have labelled them ... Now if we let Ceres = 20 Mars will equal Ceres/20 x 11 or 414,001,000 / 20 x 11 or 2070005 x 11 = 227,700,550 (actual 227,939,100) and I have shown thsi in Diagram #7) Okay and now a word from The Bent Pyramid ... and what was the original angle started with ... Here are what the results are: so the lower part of The Bent Pyramid stars at the same angle as shown in The Great Pyramid and is simply tan 0.7 ... Break time ... Cheers Don Barone
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Post by Don Barone on May 21, 2017 15:41:58 GMT -5
Just a quick check to see if Jupiter could be correct ... db
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Post by Don Barone on May 21, 2017 16:12:28 GMT -5
And according to my calculations this is what I got ... Ceres = 414,001,000 / 10232792.358 = 40.46 ( or = Queen's Chamber ?? ) and this from Petrie .... You will note that the base of The Queen's Chamber is, according to Petrie from 834.4 to 834.9 inches above the pavement ... and 834.9 / 20.625 = 40.48 and my calculation of 40.46 cubits gives us 40.46 x 20.625 or 834.4875 and well within Petrie's tolerances so it would appear that my solar system within The Great Pyramid is absolutely correct ! Cheers Don Barone .
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Post by Don Barone on May 21, 2017 17:05:57 GMT -5
Another one .... And for those who have read my old threads a lot of these were found in The Giza Rectangle suggesting, at least to me, as I stated many years ago ... The Giza Rectangle is just a mirror image of The Great Pyramid ... or vice versa. Cheers Don Barone
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Post by Don Barone on May 21, 2017 19:57:54 GMT -5
Just had a very long post I was working on get deleted by my stupidity ... sometimes it is very frustrating ... Will try again later ... right now am very ticked off at my computer .... db
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Post by Don Barone on May 21, 2017 20:26:36 GMT -5
Okay I guess everything to a purpose ... Pyramid of Userkaf I had posted how it was interesting that Userkaf had designed his pyramid to be 93.3333 by 140.00 which happened to be 1/3 of the height of The Great Pyramid and 1/2 of the height ... 280 / 3 = 93.333 and 280 / 2 = 140 but what is amazing about this is that by doing this one gets 93.3333 / 70 or 1.3333 and in fact is a 3, 4 and 5 sided right angle triangle exact in the proportions of The Pyramid of Khafre ... I had not known that it was this easy to go from a 7 / 5.5 pyramid to a 3,4 and 5 sided right angled triangle and showed a firm link between G1 and G2 I thought ... there was lots more but for now that is the important thing ... Cheers Don Barone
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Post by Don Barone on May 21, 2017 22:53:44 GMT -5
Bouncing back to The Bent Pyramid .... additional thoughts So we have 30, 60, 90, 120 , 150 and 180 cubits easily marked out ... Cheers Don Barone
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Post by Don Barone on May 22, 2017 8:00:46 GMT -5
Hi all well never any rest for the wicked and never a dull moment at Giza ... case in point: I have been formulating an idea or theory about Giza and as part of the background I decided to get some information on cones and pyramids because in actuality that is really what we are dealing with. So here are the two formulae: Pyramid: Volume of a pyramid: 1 -- x (a squared × h) 3Volume of a cone:
The volume of a cone is exactly one third the volume of a cylinder of the same height.
Volume of a cone = 1/3 (Volume of a cylinder)
1 = -- x (Pi x r2 x h) [∵ Volume of a cylinder = Pi x r2 h ] 3
Okay so let's do our Great Pyramid first: Pi x 440 squared x 280 = 1 = -- x 193600 x 280 3 1 = -- x 54208000 3 = 18,069,333.33 cubits = 2,583,283 cubic metres or (91,227,778 cu ft) " as per Wiki " Ratio cubic cubit to cubic metre = 1:6.995 probably = 7 ? ( actual = 6.95531 using 20.625 inches while 20.62 = 6.96037) ) Ratio cubic cubit to cubic foot = 0.198 and probably 0.2 ? ( actual = 0.19695 ) Ratio of cubic metre to a cubic foot = 35.341 (almost 1/10th of sq rt of 2 / 4 x 100 = 353.5534 ) Volume of a cone:
1 = -- x (Pi x r2 x h) 3
1 = -- x (Pi x 220 sqrd x 280) 3 1 = -- x (Pi x 48400 sqrd x 280) 3 1 = -- x (Pi x 13552000) 3 1 = -- x (42574863.6) 3 = 14,191,621.2 Ratio between the volume of a pyramid and a cone = 1:0.7853982 or the tan of the seked angle !!!!!!!!!! 1.27324 = angle 51.854 AND THE PERFECT PI ANGLE !!!!!!!!! So tan of the pyramid angle is the ratio between the volume of a pyramid and the cone ... and only in the 4 / Pi tan special case is the ratio 4 / Pi ... Cheers Don Barone
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Post by Don Barone on May 22, 2017 8:25:17 GMT -5
Hi all I just checked another pyramid and the answer is always the same ... the difference between volume of a pyramid and the cone will always be 4 / Pi !
But let's have a look at The Bent Pyramid ....
Let's calculate the volume of the existing base and the height WITHOUT the bend.
We would get (360 squared x 200) / 3 and this equals 8640000 and the number of seconds in a 100 days ...
And we have established that the cone is 1.2734 x pyramid and this equals 8640000 x (4 / Pi) = 11000789.666
or 8640000 x Pi/4 = 6785840
And just as a note here
360 (base) x 180 (1/2 base) = 64800 and divided by 4 = 16200
64800 / 20.625 = 3141.81 or 1000 x Pi to an accuracy of 0.99993
Interesting ...
Cheers Don Barone
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Post by Don Barone on May 22, 2017 9:17:10 GMT -5
And just a few things ... A sqaure of 81 units has as it's perimeter 4 x 81 or 324 and interestingly sq rt of 324 is 18 ... 81 backwards ... Base of Bent = 360. 360 sqrd = 129600 / 4 = 32400 and sq rt = 180 Base of bent = 360 and times 2 = 720 and divided by Pi = 229.183118 and times 1000 = 22918.3 and ... well just have a look at this drawing of Clive's: You will notice Clive has the distance from centre of east side of G1 to west side of G3 on a horizontal line as 29218.5 inches and we came up with 22918.3 for a difference of 6300.2 or basically the perimeter of The Giza Rectangle .... EXACTLY ... Nice and interesting For we have 1417.5 x 2 + 17325.5 x 2 = 6300 !!!!!! So I would propose that Clive was .2 of an inch out and it shroud be 29218.3 !
I mean that is pretty interesting ... becasue it comes from 360 (degrees) or base of The Bent Pyramid in cubits doubled and then divided by Pi ... Extremely interesting .. at least to me ... Cheers Don Barone EDIT: And just as a sidelight here and I have pointed this out before ... Clive has the distance from centre of G2 to centre of G3 on the horizontal as 9445 and if we divide by 10,000 we get 0.9445 and this is the tan for angle 43.36511 or 43° 21' 54" and the agreed upon angle of both The Red Pyramid and the top of The Bent Pyramids is 43° 22" minutes ( Wiki and others 43°22', top ) SECOND EDIT: This time we multiply 720 x Pi to get 2261.95 and times 10 gives us 22619.5 and Clive has distance from centre of G1 to centre of G3 on the horizontal as 22607 out about 12 inches ? Cheers Don Barone
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Post by Don Barone on May 22, 2017 10:57:28 GMT -5
Well with my work on the location of the sloping passageway at The Pyramid of Khafre and my work with the Bent Pyramid I guess it was time to take a new look at my old friend The Great Pyramid. Here is what I have come up with ... The first thing I did was to scale where the sloping passageway crosses the baseline and it came up with 352 and that left 88 to the right of it and 88 is 1/5th of 440 ( 440 / 5.0 = 88 ) I then calculated the vertical and got 132 ... 132 from 280 = 168 ... and where have we seen that before Next I was curious where and why they put a bend in the passageway and found to my delight that it scaled to 360 cubits !!!!! This left 80 and isn't 80 x 5.5 440 It was making a lot of sense to me and then I calculated the lower portion and found that it scaled to 66 cubits and again we have seen this before in the height of man at 66 inches ! And it all fits nicely and is easy to calculate because the slope of the passageways is 26.565 or the angle produced from a seked of 0.5 ... or 2 ... There is more but the diagram was getting crowded ... Cheers Don Barone
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Post by Don Barone on May 22, 2017 11:07:03 GMT -5
Just noticed this as I was closing the drawing. This is classic Cheers Don Barone
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