Post by ariston on Jun 25, 2007 6:17:32 GMT -5
Dear Brethren,
Pistones' Giza Grid
My rendition of the Geometrical design present at Giza presents us with a question at conception. Was this the GENESIS or was it how it was perceived, ala Classical Greece.
We find that the shorter axis of the site is 1414 Royal cubits.
This value is repeated in the distance from the centre of Khufu, to the center of Menkaure. 1414 being root2*1000.
This 1414 by 1414 gives us sq of equal sides.
With this we can inscribe a grid of nine internal sqaures, with equal values on the base of 471.333RC.
1414/3=471.3333
9 internal squares at 471.333=The Giza Grid
Taking 1.4142, the square root of 2, which defines a diagonal from the square base and applying it to 471.33 a progression can be made,
471.333*1.4142=666.561RC
so
1414 (by 1414)/3=471.333*1.4142=666.66
The Giza Grid with 9 squares at 471.33rc has diagonals of 666.6rc
Therefore the grid with nine squares, each square being criss-crossed twice, and within the grid, 666.6 occurs on the surface level 18 times.
This is basic geometry and not difficult to conceptualise.
So then we find that 1414*PI=4444/5=888.8
Using the square root of 3=1.732, which defines the internals of the Vesica a continuance can be gleaned.
1414*PI=4444/5=888.8*rt3/2(.866)=
769.7*rt3/2(.866)=
666.6/rt2(1.4142)=
471.33*3=
1414rc
This my friends is possibly how the builders encoded the value in the grid, but definately how the Gnostics perceived it.
Kind Regards
Latona
Pistones' Giza Grid
My rendition of the Geometrical design present at Giza presents us with a question at conception. Was this the GENESIS or was it how it was perceived, ala Classical Greece.
We find that the shorter axis of the site is 1414 Royal cubits.
This value is repeated in the distance from the centre of Khufu, to the center of Menkaure. 1414 being root2*1000.
This 1414 by 1414 gives us sq of equal sides.
With this we can inscribe a grid of nine internal sqaures, with equal values on the base of 471.333RC.
1414/3=471.3333
9 internal squares at 471.333=The Giza Grid
Taking 1.4142, the square root of 2, which defines a diagonal from the square base and applying it to 471.33 a progression can be made,
471.333*1.4142=666.561RC
so
1414 (by 1414)/3=471.333*1.4142=666.66
The Giza Grid with 9 squares at 471.33rc has diagonals of 666.6rc
Therefore the grid with nine squares, each square being criss-crossed twice, and within the grid, 666.6 occurs on the surface level 18 times.
This is basic geometry and not difficult to conceptualise.
So then we find that 1414*PI=4444/5=888.8
Using the square root of 3=1.732, which defines the internals of the Vesica a continuance can be gleaned.
1414*PI=4444/5=888.8*rt3/2(.866)=
769.7*rt3/2(.866)=
666.6/rt2(1.4142)=
471.33*3=
1414rc
This my friends is possibly how the builders encoded the value in the grid, but definately how the Gnostics perceived it.
Kind Regards
Latona