Recent Geometric Discoveries Pertaining to The Giza Plateau

[Don Barone]

Hi all ...

Well as always just when I think there is no more to find at Giza something or someone comes along and hands me an idea and off I go. Case in point this time is Gary Osborn and his signature image (he has many) of The Earth, The Moon, Mercury and his 23.5 degree angle. Here is that image.



Now because it is what I do and is in my nature I decided to check some measurements of this diagram and what I discovered is as always breathtaking in it's simplicity. I managed to discover within this image all three of The Giza Pyramids and of course the ratio of Mercury to Venus. I will let the image speak for itself but I will just quickly add that the distance of 1/2 Mercury (and also could be and is Earth) in this image when compared to where the 23.5 degree angle lines end of the larger Earth circle give us the ratio of not only Mercury to Venus but of G1 to G2 and of course in turn gives us the ratio of sq rt of 3 divided by Phi. It is all there. It is very neatly done and I guess proves once again that "The Creator" being a master geometrist kept it simple.

An image:



This image is amazing. If we use 9067.7 instead of 9068.8 for the size of Mercury (Earth) and use our number of inches in a metre of 39.37 ( x 100 or 3937) and add this number to 1 / 2 9067.7 we get for "Venus" and "G2" 9067.5 / 2 + 3937 = 8470.75

HOWEVER if we allow "Venus" or "G2" to equal 8471.9 the exact size of the north side of G2 we get this ... 8471.9 - 3937 = 4534.9 ( x 2 = 9069.8) which is within 0.3 of an inch of the south side and 0.4 of the north side.

All in all a nice discovery hidden within Gary's image and the angle of the tilt of our Earth.

Oops nearly forgot G3. The circle above is the circle of what remains and there is a thin white line dividing the circle in half and the distance between the two sloping 23.5 lines on this centre line appears to be precisely the distance of G3. Hard to believe when we consider that Clive Ross determined that the distance of the base of G3 was 1 /2 the diameters of Mercury and Mars added together.

Enjoy !

Cheers

[Don Barone]

Hi all and here is something else I stumbled onto while I was playing with the diagram above. I decided to calculate the diagonal of triangle with sides G1 (9068.6) and G2 (8477.63) and noted something very interesting. Here is the measurements of Petrie at Giza:



Now in this diagram I have noted in the past the measurement from the centre of G1 to centre of G2 directly in a southerly direction and we note that this distance is 13932. Now I have noted elsewhere that 13166 / 13932 is equal to 0.9450 and is precisely what the distance is from centre of G2 to centre of G3 in an westerly direction. Now just recently I have noted that 8472 which is rounded off from 8471.9 when squared gives us 71773089.61 and when we take the reciprocal of this we get ... 1.39328e-8 which is a very neat trick that the builders built into the layout to once again emphasize the overall design and plan they intended.

Enjoy.

Don

[Don Barone]

Quick addendum to first post. Unfortunately when we multiply 3937 x 1 divided by tan of 23.5 we only get 9054.48 inches and thus this can not be correct. Lowest value we can get is 9067.4 / 2 + 3942.62 (9067.4 / 2.29984)  or 8476.32 which is ... well here are Petrie's figures for G2.

[Charlotte]

Haven't seen you here in a while, Don. The overall design and plan they intended ... the question who "they" might have been remains in my mind in which there is much amiss about the Snefru, Khufu, Khafre, Menkaure succsession, and other things.

Happy Springtime

[Don Barone]

Happy Springtime indeed as we suffer through an ice storm of sorts ...

Anyway moving back to Giza here is Gary Osborn's image superimposed three times over The Giza Rectangle. Very interesting fit ..




This second one looks to fit but it does not as G3 is only 201.46 cubits while half base of G2 is 205.52 cubits so it is right of centre by about 4 cubits



Cheers
Don