Post by Don Barone on Jun 9, 2015 11:25:35 GMT -5
In the picture below is one of my earlier "discoveries",
It was never fully developed or commented on but the distance from The Great Pyramid to The Step Pyramid at Sakkara scales to 8.91268 miles which is the diameter of a circle with the circumference of 28 miles (1/10th of height of The Great Pyramid in cubits) Now 8.91268 miles is equal to 564707.2 inches which when divided by 8471 inches (base of G2 yields 66.66 ... interesting at the very least and when divided by 20.61 (possible number of inches in a cubit in G2 construction) we get 27400. (rounded) or 100 times height of G2 in cubits - 274.00 cubits actually 274.02 )
The point of this I think is to show that there is an overlying geometry possible that ties in all the pyramids of The Old Kingdom's 3rd and 4th Dynasties.
And the angle formed by the Bent - Red center line scales to about 66.? degrees and 23.? degrees which surprisingly (or maybe not) matches the latitude of The Tropic of Cancer (23.33) and Tropic of Capricorn (66.67)
Or maybe .... 23.5 degrees !!!!!!!!!
Now just to make it a little more interesting 28 / Pi yields our diameter but if we multiply the circumference of 28 by Pi we get 87.9645943 and The Orbital period of Mercury is 87.969098 which checks for 0.9999488 ... again what I would call interesting. So we can say that the orbital period of Mercury divided by 28 gives us Pi to a degree of accuracy of 0.999949 ... Nice and easy to remember ... 28 times Pi = length of a orbital period on Mercury or a length of a year on Mercury ... and now you have the rest of the story ...
Diameter of circle of circumference of 28 miles = 8.9126768131461388030574907488608 miles
8.9126768131461388030574907488608 x 5280 = 47058.933573411612880143551153985 feet
47058.933573411612880143551153985 x 12 = 564707.20288093935456172261384782 inches
Base of G2 is 8471.9 inches
564707.20288093935456172261384782 / 8471.9 = 66.65650006
ALMOST THE EXACT SAME ANGLE AS SHOWN IN THE DIAGRAMS I POSTED ...
So very nice and simple really ...
Cheers
It was never fully developed or commented on but the distance from The Great Pyramid to The Step Pyramid at Sakkara scales to 8.91268 miles which is the diameter of a circle with the circumference of 28 miles (1/10th of height of The Great Pyramid in cubits) Now 8.91268 miles is equal to 564707.2 inches which when divided by 8471 inches (base of G2 yields 66.66 ... interesting at the very least and when divided by 20.61 (possible number of inches in a cubit in G2 construction) we get 27400. (rounded) or 100 times height of G2 in cubits - 274.00 cubits actually 274.02 )
The point of this I think is to show that there is an overlying geometry possible that ties in all the pyramids of The Old Kingdom's 3rd and 4th Dynasties.
And the angle formed by the Bent - Red center line scales to about 66.? degrees and 23.? degrees which surprisingly (or maybe not) matches the latitude of The Tropic of Cancer (23.33) and Tropic of Capricorn (66.67)
Or maybe .... 23.5 degrees !!!!!!!!!
Now just to make it a little more interesting 28 / Pi yields our diameter but if we multiply the circumference of 28 by Pi we get 87.9645943 and The Orbital period of Mercury is 87.969098 which checks for 0.9999488 ... again what I would call interesting. So we can say that the orbital period of Mercury divided by 28 gives us Pi to a degree of accuracy of 0.999949 ... Nice and easy to remember ... 28 times Pi = length of a orbital period on Mercury or a length of a year on Mercury ... and now you have the rest of the story ...
Diameter of circle of circumference of 28 miles = 8.9126768131461388030574907488608 miles
8.9126768131461388030574907488608 x 5280 = 47058.933573411612880143551153985 feet
47058.933573411612880143551153985 x 12 = 564707.20288093935456172261384782 inches
Base of G2 is 8471.9 inches
564707.20288093935456172261384782 / 8471.9 = 66.65650006
ALMOST THE EXACT SAME ANGLE AS SHOWN IN THE DIAGRAMS I POSTED ...
So very nice and simple really ...
Cheers