The Mathematical Perfection of Giza: Found !!!

[Don Barone]

Hi all.

If you didn't think it was designed as a complete project before this is bound to convince you. I present the conclusive proof that the entire complex had to have been designed together.

First a couple of neat little things to whet your appetite:



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And now as clear a proof as I think I am ever likely to find that the entire project was conceived to be viewed together. May I present "The Perfection" that is Giza !



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Can anyone doubt any longer ?

Cheers
Don Barone

[Don Barone]

There is much more over at Ma'at and at Graham's. I am just too tired and lazy to transfer them here.

Cheers
Don Barone

[Charlotte]

Thanks Don, for the wonderful images and hard work, methinks you love it

I am following much over at GH, and like this especially:

"But it is true that plotting the recurrence of Venus' westward elongation from the Sun, over five conseutive synodic periods, will create the points of a pentagram. This period is approximately 584 days long, each period determining a different point of the observed pentagram—taking approximately eight years, five days to complete the figure. One would get a pentagram by picking any sunrise date on which the morning star is prominent and then repeating the observation at 584 day intervals following that date."

Have a great weekend
Love

Charlotte

[Don Barone]

Very, very nice, Imhotep was quite the mathematical and geometrical wizard ...

The probable measurements at Giza: (images and ideas for them are from Don Barone



Large Diagram: img846.imageshack.us/img846/3903/gizapetrieg201.png

Clive noted (he used 412 as a base) that if we allow a 3, 4 and 5 triangle for G2 we can note the following: If base is 410.927 then calculating for 3/4 for half base or would give us [205.4636 / 3 ] and then x 4 = 273.9515 and then we can note that if do do the exercise again we get [273.9514 / 3 ] x 4 = 365.2686 --- an Earth year ! NOTE: Actual is 365.2563 so accuracy is 99.997

But then we have to note that not all the sides are identical. This means that if the center is indeed directly over the center then the angles have to be different. We must then note of course that there is no apex. It is an assumed apex and we know what happens when we assume things. I am proposing that one of the sides would yield this ratio:

a sqrd + b sqrd = c sqrd

Where c = 343.4855

If we use 205.57 ( largest side of G2 measures 411.14 cubits) then "b" would equal the square root of 117982.28871025 - 42259.0249 = 75723.26381025

"b" then equals 275.1786 in height and since there is no apex who among you can prove this theory wrong ?

But why 343.4855 you may be asking yourself ?

Well I have shown many instances of Earth - Mars correlations on The Giza Plateau well here is another one. The Martian Year is 686.971 and so 343.4855 is 1/2 of a Martian Year while the same pyramid has shown us 3/4 ths of an Earth Year.

Quite a neat overall project by Imhotep one would have to concede.

But we are not quite done yet.

We have not shown [square root of 3 / 4] x 1000 or 433.0127 yet and we have not shown Phi yet either. Allow me to complete the geometrical and mathematical artistry of Giza.

If we allow 410.927 to equal Pi or 1.618034 then 1 equals 253.9668 and 1.73205 would equal 439.88 === PRECISELY THE BASE OF G1 !

But what of 433.0127 ?

Well observe the final image. Amazing seems such a feeble word to describe this genius.



db

[Don Barone]

A further image:

[Don Barone]

As a further proof of the correctness of this model let us try this.

Distance east-west = 1417.43 cubits

Distance from west side to center of G1 = 1417.43 - 219.94 = 1197.49

Ratio is 1417.43 / 1197.49 = 1.183668

1.183668 + 1 = 2.183668

439.88 / 2.183668 = 201.44 within 2/100th of a cubit to my value of 201.46 cubits

And then we have this as well. Not sure how it all ties in yet.

1197.49 / 2 = 598.745

598.745 x Pi = 1881.01

1881.01 / 1000 = 1.88101

686.98 (Mars year in Earth days) / 1.88101 = 365.22 Earth days

To be exact it would be 1149.40 and this would make 1/2 G1 as 439.83

And remember there are four sides to every story at Giza.



Sq rt of 7 / 4 x 1000 = 661.4378

1417.43 (width of Giza Plateau in cubits ) - 661.4378 = 755.9922

Number of feet in base of G1 AND 2 SYNODIC PERIODS OF SATURN !!! (Synodic period 378.09 days )

One of the probable heights or n-s at Giza equals 1731.8956

439.88 / 410.927 = 1.0704578

1.0704578 x 1000 = 1070.4578

1070.4578 + 661.4378 = 1731.8956

db

[Charlotte]

Hi Don,

Looks beautiful, but I can't follow the math so can't say either Yea or Nay, but like that there are four sides to every story at Giza, and wish we would know more about Imhotep, the Carpenter and Sculptor, near the head of the King, an interesting statement the AE made.

Cheers

Charlotte

[Don Barone]

Hi Charlotte the math is very easy. Just get out your Windows calculator and just do what it says to do in the brackets.

Eg: sq rt of 3 is 1.73205

divide 1.73205 by 4 and we get 0.4330127

multiply this by 1000 = 433.0127

So simple ...

But now a new idea found.

... In astronomy, Kepler's laws of planetary motion are three scientific laws describing orbital motion, each giving a description of the motion of planets around the Sun.

Kepler's laws are:

1) The orbit of every planet is an ellipse with the Sun at one of the two foci.

2) A line joining a planet and the Sun sweeps out equal areas during equal intervals of time.

3) The square of the orbital period of a planet is directly proportional to the cube of the semi-major axis of its orbit.

The laws are named after a German astronomer named Johannes Kepler (1571–1630), who proposed them in the early 1600s. Kepler was able to summarize the carefully collected data of his mentor—Tycho Brahe—with three statements that described the motion of planets in a sun-centered solar system. Kepler's efforts to explain the underlying reasons for such motions are no longer accepted; nonetheless, the actual laws themselves are still considered an accurate description of the motion of any planet and any satellite. ... en.wikipedia.org/wiki/Kepler%27s_laws_of_planetary_motion

An image ...



Large image: img844.imageshack.us/img844/3889/gizakeplersolved002.png

Giza remains full of surprises.

(559.0734 x 10)² = 31256306.658756

Cube root of 31256306.658756 = 315.00145

Exact would be 559.0695

599.0695 - 353.5534 = 205.5161 x 2 = 411.0323

Nice.

[Don Barone]

In the diagram if 205.52 or 1/2 base of G2 is representing distance to Earth then 568.33 (2 x 568.33 = [1136.66 x 12] / 31 = 439.99) is representing distance to Ceres almost, well exactly. (99.9994 %)

However we have said that G2 is representing Venus so therefore 205.52 should represent 1/2 distance to Venus of 108,208,930 /2 or 54,104,465 568.33 then this represents the distance of Earth to The Sun (54104465 x 2.7653269755 = 149,616,536. 149598261 / 149616536 = 99.998%

Still very interesting that the ratio of Earth to Ceres = 1/2 Venus to Earth (semi major axis distances used)

[Don Barone]

Building on the previous post I offer this:

Interesting.

I had noted that 1/2 108,208,930 or 54,104,465 goes into Earth's semi major axis the same number of times that Earth itself divides into the distance Ceres is from The Sun.

(Earth) 149,498,261 / (1/2 Venus) 54,104,465 = 2.7649892

(Ceres) 413,690,604 / (Earth) 149,598,261 = 2.76534367

Well I decided to try another one and found this.

(Mars) 227,939,100 / (1/2 Venus) 54,104,465 = 4.21294434757

Not at all interesting until we square it and get 17.74890008

And then even more interesting when we square it once more and get 315.0234539

(Ceres) 413,690,604 / (1/2 Venus) 54,104,465 = 7.64614536

Again not too interesting until we take the square root of 7.64614536 and find that we get 2.7651664 almost exactly in the middle of the other two.

(Jupiter) 778,547,200 / (1/2 Venus) 54,104,465 = 14.389703327

Again apparently meaningless until we discover that 14.389703327 divided by the number of AU (Earth Astronomical Units) or Semi-major axis of Jupiter 778,547,200 km (5.204267 AU) or 14.389703327 / 5.204267 AU = 2.76498176 what we find above for Earth divided by 1/2 Venus.

There appears to be a formula here somewhere ... I will keep digging.

Meanwhile for clarity I have made this.



And as you ponder this chart remember that 1/2 Venus is also equal to 205.52 or 1/2 base of G2

And take special note that 439.82 / 1.07032017 is equal to 410.924 or 3/1000ths of a cubit off my value of 410.927 as shown in the diagram below.

[Charlotte]

Hi Don,

Unless I really applied myself to the subject, it wouldn't do me any good to do the calculating, your domain, mine is History

Cheers

Charlotte