Post by Don Barone on Feb 13, 2009 9:52:59 GMT -5
Hi all ...
If one divides the base length of G1 by 16 and then times that by 15 we get 412.5 (440 / 16 x's 15)
If we assume that G2 is of the 3, 4 and 5 right angled variety we would get IF we set the height at 275 base as (1/2 base x's 1.33333333333333333 or .75 times height = 1/2 base = 206.25 x's 2 = 412.5
Seems maybe, just maybe 412.5 is a good measurement for G2.
HOWEVER
If we set height at 274 we get 411.00
Hmmmm ....
Ratio of G1 to G2 is 1:1.0705596107055961070559610705596 (440 / 411)
1.0705596107055961070559610705596 divided into square root of 3 times 1000 =
1732.0508075688772935274463415059 / 1.0705596107055961070559610705596 = 1617.8929134336558355449555599066 or Phi to within [1618.0339887498948482045868343656 - 1617.8929134336558355449555599066 = 0.14107531623901265963127445963812 or about 2.9 inches over almost half a mile.
If we use 411.04 which is a value I have calculated earlier we would get ... 440 / 411.04 = 1.0704554301284546516154145581938
1000 times the square root of 3 = 1732.0508075688772935274463415059
1732.0508075688772935274463415059 / 1.0704554301284546516154145581938 = 1618.0503725979802789352762368468. This is Phi x's 1000 correct to within 0.016384 or 1/3rd of an inch over a distance of greater than half a mile.
Wonderful !!!
G1
Cole's average base = 230.364m
in/m = 39.370079
Cole's average base = 9069.439in
G2
Petrie's average base = 8474.875in
G3
Petrie's average base = 4153.633in
The distance in cubits depends on what cubit value you use.
If G1 = 440, then cubit = 20.612
Then, G2 = 411.155
And, G3 = 201.512
If cubit = 20.632,
then G1 = 439.581
And G2 = 410.764
And G3 = 201.320
Which values you use depends on your starting assumptions and analytic methods.
So were we to use 20.618033988 (20 + Phi) we would get:
G1 = 9069.439in / 20.618033988 = 439.8788
G2 = 8474.875in / 20.618033988 = 411.0419
G3 = 4153.633in / 20.618033988 = 201.4560
If we use the EXACT length of an Earth year we get this.
Year = 365.242199 days (365 days, 5 hours, 48 minutes, 46 seconds).
5 x's 365.242199 = 1826.210995
Now if we divide this by Pi we get:
1826.210995 / Pi = 581.30101396603711514070461509573
The exact measurement I show in this diagram.
G2 according to Petrie:
G2 = 8474.875in / 20.618033988 = 411.0419
Square root of (411.0419 x 411.0419) x 2 = 337910.88711122
Square root of 337910.88711122 is 581.30102968360549774003885640773
Difference is negligible:
581.30102968360549774003885640773
581.30101396603711514070461509573
-----------------------------------
000.000016
Amazing !!!
----------------
I have just been playing around with this and it is very interesting. Take it for what it is worth but it is definitely food for thought. I was just re-reading an old thread and re-examining my co-ordinates for The Sphinx from an old posting of Jon's when I noticed something most miraculous or as usual amazingly co-incidental I honestly don't think anyone has suggested this before but here goes. In an old posting of mine I posted this diagram:
As you can see I suggested that the center of The Sphinx was in The Phi proportions to the overall length of 1512 (+ or -) I was unsure of the correct co-ordinates and so never really checked it. However I was just having another look at this diagram of mine:
and after scaling it off the legend provided I noticed that it did not check.
Undeterred I pressed onward and decided to see where this point would actually fall. Here is that diagram:
So it now appears that the center line of what appears to be the most ancient of the buildings at Giza, The Sphinx Temple, is apparently set to the Phi proportions of a distance equal to the distance of 1512 which is the distance from center of G1 to the south base of G3 !
However as lovely and beautifully geomterically perfect as that is and coupled with these two postings of mine: www.hallofmaat.com/read.php?8,501832,503330#msg-503330 and www.hallofmaat.com/read.php?8,501832,503359#msg-503359 there is still more.
I have been trouble by the fact that the distance from the west side of G3 to the center of G1 is not what I had supposed it should be, I had calculated that it should be 1188 to make a proper large scale renditon of The Great Pyramid in the 1188 by 1512 (220 by 280). And then just today I had what I consider a small revelation. The corerct distance from the west face of G3 to center of G1 is about 1197.62, again as always + or -. I decided to see what angle is obtained when one divides 1197.62 by 1512 and here is the most surprising and amazing part. The angle obtained by dividing 1197.62 / 1512 = tan 0.79207671957671957671957671957672.
tan 0.79207671957671957671957671957672 yields 38.381925104351450983465201553755
The actual angle contained between the south west corner of G3 and the center of G1 is ... 90 - 38.381925104351450983465201553755
90 - 38.381925104351450983465201553755 = 51.618074895648549016534798446245
So as unbelievable as it may appear the angle shown in the diagram beleow is 51.Phi
How did they do it ? Why did they do it ? I have absolutely no idea.
But Phi is alive and well at Giza !!!
A small addendum.
Petrie had the measurment from west side of G3 to center of G1 as 24693 inches
To obtain a perfect Phi angle of 51.618033988749894848204586834366 we would need a distance of 1512 by 1197.6217567760787689843169168395 x's 20.Phi = 24692.60608687555174978795463285
A difference of 4/10ths of an inch over 1928.8446988556183842855054370353 cubits or 3/5ths of a mile !!!
Awesome those Egyptians !!!
In the light
Don Barone
If one divides the base length of G1 by 16 and then times that by 15 we get 412.5 (440 / 16 x's 15)
If we assume that G2 is of the 3, 4 and 5 right angled variety we would get IF we set the height at 275 base as (1/2 base x's 1.33333333333333333 or .75 times height = 1/2 base = 206.25 x's 2 = 412.5
Seems maybe, just maybe 412.5 is a good measurement for G2.
HOWEVER
If we set height at 274 we get 411.00
Hmmmm ....
Ratio of G1 to G2 is 1:1.0705596107055961070559610705596 (440 / 411)
1.0705596107055961070559610705596 divided into square root of 3 times 1000 =
1732.0508075688772935274463415059 / 1.0705596107055961070559610705596 = 1617.8929134336558355449555599066 or Phi to within [1618.0339887498948482045868343656 - 1617.8929134336558355449555599066 = 0.14107531623901265963127445963812 or about 2.9 inches over almost half a mile.
If we use 411.04 which is a value I have calculated earlier we would get ... 440 / 411.04 = 1.0704554301284546516154145581938
1000 times the square root of 3 = 1732.0508075688772935274463415059
1732.0508075688772935274463415059 / 1.0704554301284546516154145581938 = 1618.0503725979802789352762368468. This is Phi x's 1000 correct to within 0.016384 or 1/3rd of an inch over a distance of greater than half a mile.
Wonderful !!!
G1
Cole's average base = 230.364m
in/m = 39.370079
Cole's average base = 9069.439in
G2
Petrie's average base = 8474.875in
G3
Petrie's average base = 4153.633in
The distance in cubits depends on what cubit value you use.
If G1 = 440, then cubit = 20.612
Then, G2 = 411.155
And, G3 = 201.512
If cubit = 20.632,
then G1 = 439.581
And G2 = 410.764
And G3 = 201.320
Which values you use depends on your starting assumptions and analytic methods.
So were we to use 20.618033988 (20 + Phi) we would get:
G1 = 9069.439in / 20.618033988 = 439.8788
G2 = 8474.875in / 20.618033988 = 411.0419
G3 = 4153.633in / 20.618033988 = 201.4560
If we use the EXACT length of an Earth year we get this.
Year = 365.242199 days (365 days, 5 hours, 48 minutes, 46 seconds).
5 x's 365.242199 = 1826.210995
Now if we divide this by Pi we get:
1826.210995 / Pi = 581.30101396603711514070461509573
The exact measurement I show in this diagram.
G2 according to Petrie:
G2 = 8474.875in / 20.618033988 = 411.0419
Square root of (411.0419 x 411.0419) x 2 = 337910.88711122
Square root of 337910.88711122 is 581.30102968360549774003885640773
Difference is negligible:
581.30102968360549774003885640773
581.30101396603711514070461509573
-----------------------------------
000.000016
Amazing !!!
----------------
I have just been playing around with this and it is very interesting. Take it for what it is worth but it is definitely food for thought. I was just re-reading an old thread and re-examining my co-ordinates for The Sphinx from an old posting of Jon's when I noticed something most miraculous or as usual amazingly co-incidental I honestly don't think anyone has suggested this before but here goes. In an old posting of mine I posted this diagram:
As you can see I suggested that the center of The Sphinx was in The Phi proportions to the overall length of 1512 (+ or -) I was unsure of the correct co-ordinates and so never really checked it. However I was just having another look at this diagram of mine:
and after scaling it off the legend provided I noticed that it did not check.
Undeterred I pressed onward and decided to see where this point would actually fall. Here is that diagram:
So it now appears that the center line of what appears to be the most ancient of the buildings at Giza, The Sphinx Temple, is apparently set to the Phi proportions of a distance equal to the distance of 1512 which is the distance from center of G1 to the south base of G3 !
However as lovely and beautifully geomterically perfect as that is and coupled with these two postings of mine: www.hallofmaat.com/read.php?8,501832,503330#msg-503330 and www.hallofmaat.com/read.php?8,501832,503359#msg-503359 there is still more.
I have been trouble by the fact that the distance from the west side of G3 to the center of G1 is not what I had supposed it should be, I had calculated that it should be 1188 to make a proper large scale renditon of The Great Pyramid in the 1188 by 1512 (220 by 280). And then just today I had what I consider a small revelation. The corerct distance from the west face of G3 to center of G1 is about 1197.62, again as always + or -. I decided to see what angle is obtained when one divides 1197.62 by 1512 and here is the most surprising and amazing part. The angle obtained by dividing 1197.62 / 1512 = tan 0.79207671957671957671957671957672.
tan 0.79207671957671957671957671957672 yields 38.381925104351450983465201553755
The actual angle contained between the south west corner of G3 and the center of G1 is ... 90 - 38.381925104351450983465201553755
90 - 38.381925104351450983465201553755 = 51.618074895648549016534798446245
So as unbelievable as it may appear the angle shown in the diagram beleow is 51.Phi
How did they do it ? Why did they do it ? I have absolutely no idea.
But Phi is alive and well at Giza !!!
A small addendum.
Petrie had the measurment from west side of G3 to center of G1 as 24693 inches
To obtain a perfect Phi angle of 51.618033988749894848204586834366 we would need a distance of 1512 by 1197.6217567760787689843169168395 x's 20.Phi = 24692.60608687555174978795463285
A difference of 4/10ths of an inch over 1928.8446988556183842855054370353 cubits or 3/5ths of a mile !!!
Awesome those Egyptians !!!
In the light
Don Barone
