
Post by Don Barone on May 29, 2020 15:24:39 GMT 5
Reading the article has given me a few ideas . Here is what is said of the vertical angle of The Pyramid of Meidum. And what is said of the width of the phases . Now I have to wonder if Egyptologists are pretending to be stupid or if they are simply brain dead when it comes to math . The y spout off measured angles but never once give a thought to the actual mathematical properties . They spout 73°20' and 74° never once realizing what was used to build the sides . It is very simple . They used a ratio of 3 to 10 and this yields as a Tan number 3.33333333333333 and the angle of this is 73° 18' 2.72" ... Gee do you think this is close enough . So it is painfully obvious that they used this to derive the angle . But why such a steep angle ? Anyway the article was nice enough to give us the width of each step and I came up with the following diagram . This is a work in progress and this is as far as I have gotten for now . It shows some interesting things which I have yet to analyze . My diagram #1



Post by Don Barone on May 30, 2020 21:55:13 GMT 5
Hi all . I have been trying to make Petrie's data fit but have been unsuccessful. Here are his notes: and here is my diagram using this data . He has the first step as 4667 inches and the second at 4267 . He has the height of first step as 571 inches and second step at 978 . I can't reconcile these four measurements . Maybe someone can see what I have done wrong . Here is my diagram : As you can see the line at 571 inches projected across to meet the slope of addition 9 should equal, according to Petrie 4667 inches however it scales and calculates to 4412 inches and the second of 4267 is not even close . Also there is no way I can get the large sloping middle section to fit . Anyway I will try again tomorrow



Post by Don Barone on May 31, 2020 8:52:38 GMT 5
I am presently trying to figure out how they would have built this pyramid . I find it unlikely that they would build just the core first (60 by 100 cubits) and then build to each side . My thought experiments say that they would have had to probably either build all slopes together or build the core to a certain height and then add to each side neither of which seem to be overly sturdy . Any ideas ? With a mastaba as a base it makes sense as you could just keep building smaller ones on top of each other but here there is no mastaba just a core with the burial chamber inside this core .



Post by Don Barone on May 31, 2020 10:34:07 GMT 5
Okay I have returned to the angle of the steps and have worked on how the builders might have got the angles they did . If it was just one block then you could say it was builder error but when it was an entire section then they must have used a template of some sort . Let me remind you of the angles Petrie found again . 73° 20' we have determined is simply tan of 10/3 or 3.333333... and gives us an angle of 73.3007557660064° or 73° 18' 2.72"
But what of two others ? 73° 54' and 75° ? Were these just errors or was there a template that works ? Here is one logical way they could have arrived at the Angles . 73° 54' is tan of 2 x ✓3 or tan of 3.46410161513775 and 75° can be arrived at by using ✓22/7 then times 10 then divided by 4.75
Here are two diagrams I quickly put together . But of course there is a much easier way to arrive at 75° but this would mean that the builders knew the equalateral triangle, the angles they contained and most disturbing of all they knew how to bisect an angle and this 2600 BCE The thing that gets to me the most is that no one has asked how and why this angle for the pyramid was chosen ... I can only shake my head ...



Post by Don Barone on May 31, 2020 11:03:16 GMT 5
I am still grabbling with how this pyramid was built . Since the core I assume was of jumbled pile of rocks it stands to reason that the "burial chamber" had to have been the very first thing built and the pyramid then built around it . Does this make sense to you ?



Post by Don Barone on May 31, 2020 12:48:29 GMT 5
I have been giving thought to what surrounds the "tomb" at The Pyramid of Meidum and in fact what exactly is this pyramid made of and exactly how it was constructed . Here is an image that gives food for thought . We all look at the images of the stages and it all looks neat and tidy with their 10 cubit width but few think about how this 10 cubit is constructed . On the inside and outside of each of these sloping sections is a pile, neatly placed on top of each other at an angle of between 73.3 and 75 ° but these rocks are only maybe 1 cubit in width ... so ... what makes up the space in between ? Sand ? Gravel ? Stone chips ? See if you can find out ... I couldn't Images Here is an image of what I mean . Not to scale but just a sense of what I am talking about



Post by Don Barone on May 31, 2020 18:20:05 GMT 5
Okay so I have been thinking . The Pyramid at Meidum was originally designed to be a seven step pyramid with basically six steps and the top platform being the seventh step . But why was it constructed the size it was . Better yet what was the size of this original pyramid and was there any rhyme or reason to it . With that in mind I have started to make inroads which I will offer up shortly . The thing to think on is what was the height of that original pyramid ? Any guesses ?



Post by Don Barone on May 31, 2020 23:01:44 GMT 5
Well I am ready to pull my remaining hairs out because I just can't get it to fit what is there . Here is an image of The Pyramid of Meidum : And now my revised drawing : And now Petrie's drawing and it appears to be wrong . It simply does not match what is there . If you compare it to the real thing it appears that the smallest level which one can assume is the exposed rock section IS IN THE WRONG PLACE . It does not match and I am not sure why . Help !



Post by Don Barone on May 31, 2020 23:19:00 GMT 5
This is what Petrie's drawing should look like not sure why it doesn't:



Post by Don Barone on Jun 1, 2020 9:32:07 GMT 5
I have been working on The Pyramid of Meidum and have come to the conclusion that the person or persons responsible for the final expansion at Meidum were not the same person/persons who built the initial 7 step pyramid and I offer this as a proof . Petrie managed to get several readings of the in situ casing stones and determined an angle of 51° 52' and since the base averaged 5682 inches he determined that the height was 3619 inches . I have stolen an inch off Petrie and called the height 3618.034 inches . Now what is interesting here is that Petrie quite logically called this pyramid 175 x 275 cubits However 3618.034 divided by 175 yields a cubit of 20.67448 inches and 275 times 20.67448 is equal to 5685.48 and an almost perfect match so Petrie I think was correct in his assumption . So it follows that if the same builder built the inner step pyramid we should logically find them using the same cubit, the one of 20.67448 inches but the results tell a different story . Here is a study I just did . It is quite interesting . I took Petrie's data and tried both cubits, the one of 20.67448 inches and our Giza standard of 20.62 inches here is the result. You will notice that by converting into meters some very interesting ratios are revealed . The Image: There are several things to notice. By using the 20.62 inch cubit what is revealed is that the one level seems to be precisely 105 cubits x 20.62 equals 2165.1 inches and a precise hit and interestingly also equals 55 (54.99) meters. Now the top is damaged by I contend that logic dictates that it is in all likelihood 66 meters to nicely equal 6 and 5 times 11 (6 x 11 = 66 and 5 x 11 = 55) But does this fit what is there ? The highest value Petrie uses is 2576 inches and this translates to 65.43 meters and the height of this pyramid is said to be between 65 and 65.5 meters . All very nice but what of 66 meters ? This equals 2598.425 inches and 126 cubits would equal 126 x 20.62 = 2598.12 and thus we can conclude 105 and 126 cubits . There is one more thing to point out ... The height of the top of this platform at Meidum is the same as that of The Pyramid of Menkaure ... now how about that ?



Post by Don Barone on Jun 1, 2020 12:44:33 GMT 5
Okay so I now claim that The Pyramid of Menkaure and The (original) Pyramid of Meidum (or at least one platform ) was the same height . The Internet gives two answers for the height of The Pyramid of Menkaure . They are 65 and 65.5 meters . See posted images: But as usual they just don't think . They post the angle as 51° 20' 25" which gives us 51.34027 and gives us a Tan 1.25000384770182 thus one half the base would be 65.5 meters divided 1.25000384770182 and we get 52.3998387048362 or 52.4 meters . Now this gives us 2062.98577578095 or 2062.99 inches x 2 = 4125.97 and the base of Menkaure is 4153 to 4157 so this can't be ... but yet they continue to publish the same rubbish year after year . However 65.5 meters IS 2578.74 inches and within 3 inches of what is given for the height of the final undamaged platform of The Pyramid of Meidum . Thus if we use 51.34027 we get 4157 / 2 = 2078.5 and if we multiply by 1.25 we get 2598.12 and that as we all now know is 126 cubits (20.62) and 66 meters thus we have proven Height of Meidum = Height of Menkaure = 66 meters = 126 cubits = 216.51 feet and interestingly 1/10th of the 55 meter level and 105 cubit level and 2165 inch level. All pretty simple so why don't we find it anywhere ?



Post by Don Barone on Jun 1, 2020 15:21:34 GMT 5
After a very careful analysis of the data supplied, even though apparently in error I have been able to make this diagram according to my presumed measurements. Looks like a pretty good match ., eh
The problem is I am still not sure what Petrie was measuring to .
Picture was in error



Post by Don Barone on Jun 1, 2020 19:14:41 GMT 5
Hi all very sorry about that last image still don't have it quite right but let's move on . Anyone who looks at The Pyramid of Meidum has got to have asked themselves what if any is the relationship in the bands we see and could it have been designed this way . With these thoughts in mind I undertook a mathematical analysis of The Pyramid of Meidum with Petrie's notes once again my guide. However before pressing on I have to bring your attention to not The Golden Ratio but The Silver Ratio. The Silver Ratio is simply the ✓2 + 1 to 1 or simply 2.4142135623731 . However in this triangle that gives us this I am concerned with the hypotenuse or the sq rt of the sq rt of 2 +1 squared +1 or sq rt of 6.82842712474619 or 2.61312592975275 or better simply 2.613 I will post a simple drawing which should make things clear and then we will move on and see what the point of this is .



Post by Don Barone on Jun 1, 2020 19:25:41 GMT 5
Okay here is a drawing with the numbers all worked out for you based on Petrie's notes . I have added the two missing platforms at 140 and 150 cubits (20.62 inches per cubit) . See if you can discover why I posted that Silver Ratio page .



Post by Don Barone on Jun 1, 2020 21:48:34 GMT 5
To get us started I will draw your attention to the distance of 1598 inches . Now I must mention that it does not matter what measurement system we use we really are only interested in the ratios . Here is the image again There are three measurements I want you to concentrate on . They are: 2598 inches = 66 meters = 126 cubits 2576 or within an inch and a half of 125 cubits and 1598 inches the distance from the 978 platform and the 2576 platform . Amazingly these three show us both The Silver and The Golden Ratio in it's simplest form . Lets start with 2598 divided by 1598 ... we get 1.625 and the simplest form of The Golden Mean is 13 and 8 and 13 divided by 8 equals 1.625
2598 / 13 = 199.846153 and then times our 8 gives us 1598.7
Next up we have 2576 divided 1598 and here we get 1.612 and an almost exact fit to our Silver Ratio . There are many more . See how many you can find .



Post by Don Barone on Jun 2, 2020 17:19:42 GMT 5
Hi I am busy working on things I am sure you will find interesting but as I am doing it I am asking myself ... Self why do you need to do this . Why can't you just pick up a book on Egypt and it would be there . But it isn't . They simply do not want to know what the builders were thinking when it was built . A building that can not be duplicated today and they still insist there were no blueprints and no rhyme nor reason . I have started an analysis, similar to what my mentor, sadly now passed, Clive Ross did at Giza . He thought every single measurement was important and this is how I am treating Meidum . But before proceeding in that front another strange thing I noticed . It has to do with the East Chapel and unless my eyes are playing tricks on me or the chapel was deep inside the pyramid there seems to be a problem . I will post the images first and then describe what I see as the problem . As I have never been there I could simply be misinterpreting the pictures . You tell me . This is the angle we are always shown but the other night I found this view of the east side . It shows a rather different story . The horizontal distance from the face of the well known part to the chapel just doesn't seem right to me . It is 81.5 feet down to the base but the distance out just doesn't seem right ...



Post by Don Barone on Jun 2, 2020 20:04:34 GMT 5
Well it still looks like there is a platform missing here but let's move on . To start this off we need a very quick refresher course of what we found a Giza . First of all the base of the three pyramids in cubits .
G1 = 440
G2 = 411
G3 = 201.5 ____________________
Total = 1052.5 ____________________
We also found that 1 cubit was equal to 20.62 and 1 foot was equal to 12 inches
And lastly we found that the diameter of The Planet Mars was 6792 kilometers and the diameter of Mercury was 4879.4
Okay so what has this got to do with The Pyramid of Meidum ? Well
1052.5 (total of all 3) divided by 612.5 (total 2 + 3) = 1.71836734693878
1 cubit (20.62 inches) divided by 1 foot (12 inches) = 1.71833333
We also found that G2 + G3 (8472 + 4154) or 12626 inches divided by G1 at 9068.99 = 1.39221677386346
We also found that 6792.4 (Mars diameter) divided by 4879.4 Mercury diameter = 1.3920564003771
And now we get to Meidum and it's pyramid because one of the ratios I found was ...
Height of pyramid (as per Petrie) is 3618.034 inches while the top of the finished step pyramid was in all likelihood 2598.12 inches and we get this :
3618.034 / 2598.12 = 1.39255846535187
What you have to realize they are all interchangeable so that Mars diameter = G2 + G3 while Mercury diameter is equal to G1 while a cubit equals G1 + G2 + G3 and a foot equals G2 and G3
And height of Pyramid of Meidum equals Mars diameter and 2598.12 inches or 126 cubits and probable height of Pyramid of Menkaure and The Pyramid of Meidum equals diameter of Mercury.
Is this what they meant ? What can not be denied is that if you know the measurements and spacing on this pyramid using the simplest of survey techniques you would know where you are and could probably fill in any missing boundary markers lost in the annual flood . I still remain unconvinced that this was or was on it's way to being a perfect pyramid . Think about the pyramids he allegedly had built: Meidum, The Bent and The Red Pyramids all bizarre shapes and all in my opinion showing us how they mapped Egypt and ... The Sky



Post by Don Barone on Jun 2, 2020 21:09:37 GMT 5
And now just a little diversion . The Sun's diameter is So the diameter is 695,700 x 2 = 1391400 This would make the circumference 1391400 x Pi = 4371212.01820484 kilometers or we have this which gives us the circumference
So we have the circumference of Our Sun, our giver of life at 2,713,406 miles and it just so happens that 3,618,034 which is the height of Meidum divided by 1.33333333 or times 0.75 we get 2,713,525.5 and checks for 119 miles or basically a perfect match ...



Post by Don Barone on Jun 2, 2020 21:59:18 GMT 5
Okay here are some drawings I have been working on . If you look close on the ratio page the greatest error is only 1.2 inches . It would be great if you let me know what you think I have spent quite a bit of time on this trying to make it clear but to the best of my knowledge NO ONE has ever did a study like this before ... I ask simply ... why not ? With each new drawing I learn a little more and become more convinced it is not a collapsed mini Great Pyramid . I will keep trying to get them perfect but please note ... Petrie only lists two possible places for the 75° side of the first two slopes defining E1 and E2 however if it was built as they claim ... should he not have run into more in the passageway . I know it is said it is very damaged but why and when was the damage done as E2 seems to be fine . I will keep on digging . Hope you enjoy the diagrams .



Post by Don Barone on Jun 3, 2020 8:19:09 GMT 5
Well last night I may have stumbled on a very unusual revelation . We have gone through life, at least I have, of believing The Pyramid of Meidum was in the ratio of base 11 and height 7 which gives us a slope angle of 51.84277 . Now using Petrie's notes this is what we actually find . He even suggests as much in his notes . Not sure why and where he changed to 51° 52" ... Please observe Petrie has the slope of the passageway as 2247.6 inches and total height (720.7 + 362.1) 1082.8 inches . Using basic trig and the angle he supplies of 28° 26' or 51.4333333° we find that the angle is ... Please study the picture carefully and note all measurements are from Petrie's notes The base I used is average of east and west distances (5694.5 + 5675 = 11,369.5 divided by 2 gives us 5684.75)



Post by Don Barone on Jun 3, 2020 8:45:24 GMT 5
To clear things up a bit Petrie tells us that from where the descending passageway ends is 2544 inches to the north base. The horizontal distance of passageway calculated to 1969.58 . Subtract this from 2544 and we are left with 574.42 .
720.7 divided by 574.42 = 1.25465687
This is the Tan of 51.4333333
If the angle was 51.845 the distance would be 566.265 and all Petrie's notes would be wrong



Post by Don Barone on Jun 3, 2020 12:40:45 GMT 5
Okay it is getting more and more obvious that this pyramid was also mathematics in stone alah genius . I just couldn't believe that there wasn't a game plan and I think I have discovered part of it . By using the various layers on The Pyramid of Meidum and the edges of the platforms themselves a symphony of mathematical perfection reveals itself . They reveal all the key angles and so much more I have yet to discover . This image will also address the seeming anomaly of The East Face and the apparent position of the chapel . Here again is the east side of The Pyramid of Meidum And now my take on The Mathematics of Meidum I am going to study this further because with what we now know the pyramid itself becomes a gigantic survey instrument ... I am just going to have to learn how to use it



Post by Don Barone on Jun 3, 2020 15:10:36 GMT 5
Hi I have to once again post this picture of the east side of The Pyramid of Meidum and remember this is the side of the causeway . It still looks to me it is not on the 275 cubit square but is on the square of the original builders . And my image of what it appears to be . And just a note . We have found every major angle there is to find in this pyramid . We have: 75 & 15 72 & 18 60 & 30 45 Every angle involved in The Wood Pentagram except one that is 24 ° This is the angle between the radial spokes within the 15 point circle I couldn't seem to find it and then I decided to check the tan of this angle and it gave no clue I then checked the tan of the reciprocal angle and found that the tan of 66° is ... 2.246037 And I had to chuckle for was not the slope of the passageway as measured by Petrie 2247.58 and within an inch and a half . But surely this is a coincidence because The Ancient Builders did not know tan or decimals or inches ... or did they . So many, many, many coincidences enough to almost make you believe . The Pyramids, all seven of them, have a story to tell . We simply need to listen and learn the language ...



Post by Don Barone on Jun 3, 2020 21:32:06 GMT 5
Hi. I am in the middle of number crunching and I will post the latest image . However I just read that the original mastaba according to Petrie was 100 cubits square and 25 to 30 cubits high to allow for the construction of the sepulchre . So it could appear that the add ons were from 100 cubits to 137.5 . Regardless after rereading Petrie's notes I may have been in a hurry to call the sloping sides at 115, 105, 95, etc as he in his notes (I will have to find them again) states that they varied from about 9.38 + or cubits . I have used only 75 degrees I will have try the other two angles . I will also post John Legon's attempt at explaining the angles . First John And now revision #5 with revision #6 already underway but you get the idea . To solve this I am going to have to figure out what their end game was, draw it and then fill in the distances and the angles I get the feeling that like "his" other pyramids this one was mapping out Egypt as a geodetic survey monument and survey instrument as well as mapping Our Solar System . See other article in this board .



Post by Don Barone on Jun 4, 2020 12:00:13 GMT 5
I think The Pyramid of Meidum may be the most beautifully mathematical wonder of them all . The ratios that are in your face now that we have analyzed Petrie's notes in greater detail can never be unseen . I trust that you will believe me when I say The Pyramid of Meidum I am about to present is not at all what I thought I would find but it too, like it's sisters is mathematics on a gigantic scale . Just before I post my latest image I want you to realize that by making it into a true pyramid it would have destroyed all the beauty it contained . No the outside base was never intended to be more than 47.5 cubits Observe the beauty that is Meidum Now that you have this image, take another look at The Pyramid of Meidum and smile as I do at the total genius of The Ancient Builders



Post by Don Barone on Jun 4, 2020 16:09:30 GMT 5
Hi all. Is this the secret of The Pyramid of Meidum ? Could they have been this clever ? May I present Exhibit 1 Now to tie it all into my ideas on how they surveyed it all . Enjoy



Post by Don Barone on Jun 4, 2020 23:59:21 GMT 5
Okay a couple of new things to consider but first I have to repost an image from one of my posts which I will now post in this board since it all seems to fit . But first the image . I came to this conclusion completely without knowing the measurements . The image: Okay so after designing a nice neat "new" Meidum I decided I had better check all my data and so that's what I did . I figured if the platforms were following such a neat orderly apparent order I figured I should be able to find the missing ones and so that's what is in this next image . This shows how it could have been done . If only I could measure the slope on the face of this section on The Pyramid . But this image made me realize that the unfinished small section in between the two larger smooth sections was actually in the middle of this section . I had come to realize that the apparent rough larger section near the bottom was part of the slope or part of the e3 section that was either never quite constructed or got pulled off in a collapse . So now in my Phi image I had called the small unfinished section 3 in my Phi sequence . Here are the key Numbers again 6.0 4.854 3.708 3.0 Where 6 is Phi and 3.708 is 1 Now in my earlier Phi diagram I had called the band 3 so I went looking for 4.854 and found that if we called 76.25 cubits 3 (1572.375 inches) then 4.854 equalled 123.375 cubits . I was a bit disappointed because we had not really found 123.375 although we could claim it was the inner side of the last slope of e2 but when changing it to inches got 2543.99 and precisely the distance that the inner end of the passageway was from the north face on the horizontal . Very nice and now we know what the bands really mean on this Pyramid ... and all this amazing math apparently about to be covered up and turned into a tomb ? I don't think so !



Post by Don Barone on Jun 5, 2020 11:33:10 GMT 5
The Solution and Solving of The Pyramid at Meidum . Amen



Post by Don Barone on Jun 5, 2020 16:14:13 GMT 5
So you thought you knew The Pyramid at Meidum well ... A fresh look at an engineering marvel . Whoever designed this was surely in cahoots with The Gods ... or ... were The Builders Gods themselves ? Yet another exhibit in "their" defense . Can we ever look at this pyramid in the old way again ?



Post by Don Barone on Jun 6, 2020 10:06:36 GMT 5
Hi as usual I am fine tuning my design . Look for revision #99 coming soon but as we wait for me to figure it all out ponder on this . The slope of the main body of the pyramid is said to be about 75° and in typical Ancient Builders style ... the slope begins, and yes you already know it, 75 cubits from the central axis . The sheer perfection of this design is beyond words . So how easy is it to duplicate this pyramid ? Just measure 75 units from center line make a mark . Measure up 105 of the same unit make another mark . Draw a horizontal line from your 105 mark and measure 45 of your units . Make mark . Join this mark with the mark on the ground at 75 units . And you have created the slope of The Pyramid of Meidum !
Really it is child's play when you think about . Sadly however we don't have exactly 75 units , According to Petrie it is only 74.71 units to the start point .
Here is the image to clarify things . It is this fact that I am now wrestling with to try to determine why this is so . Why 74.71 and not 75 exactly . With their obvious skill sure they could have measures exactly 75 cubits . Why didn't they ?
I am working on it.
The Image to follow immediately .

