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Post by Don Barone on Mar 20, 2018 15:15:37 GMT -5
Hi all ... I have been thinking ... why is it that the math I have presented over the last two decades in regards to The Giza Plateau Rectangle and The Solar System seems to fit so closely ? It was just that thought that was going through my head after finding the fact that "The Megalithic Yard" and "The Great Pyramid and it's probable design blueprint" were intimately linked and based on the square root of 3. (see Megalithic Yard thread for the proof) And so it was that I was pondering the amazing fact, which by the way has been refused to be acknowledged by "those other researchers" discovered by me that The Great Pyramid and Pyramid of Khafre are precisely in the ratio of THE SQUARE ROOT OF 3 AND PHI with The Great Pyramid being square root of 3 (makes perfect sense now that I have discovered that "The Megalithic Yard AND The Great Pyramid blueprint were based on this self same number ... namely THE SQUARE ROOT OF 3 !!!) and The Pyramid of Khafre equaling Phi. However I reasoned that there had to be more and it had to be able to be shown quite simply so that a grade school student could understand it. I have, over the years, tried thousands of images that prove my theory but it has failed to capture the imagination of a lot of people so I began to think how could I show it more visually excitingly and still be true to my roots ... that The Giza Plateau was, as Clive Ross called it so many years ago ... "The World's Oldest Book of Astronomy". The idea came to me as I was thinking well if The Great Pyramid is built on the square root of 3 as well as The Megalithic Yard on this same number, square root of 3 and I had already decided that if I made The Great Pyramid's base the square root of 3 and combining all of this the base of Khafre turns out to be the value of Phi one of the other most important numbers in the history of mathematics. I found it (and still do) amazingly odd that the two, actually three, most important numbers in mathematics and the key to virtually everything, square root of 3 and Phi and Pi which has already been found and proven in my Great Pyramid Blueprint Design would be found in two random pyramids, BOTH DESIGNED BY THE SAME PERSON, IMHOTEP ... I mean really ... what are the odds. Still this didn't graphically show how the solar system fits into all of this and that my friends in what this thread is hoping to do. I am hoping that by the end of this thread, both you and your children will totally understand it.
Emhotep Don Barone
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Post by Don Barone on Mar 20, 2018 16:25:40 GMT -5
Hi all ... have to go out tonight (our regular Trivia Night at the local place) but I wanted to leave you with this diagram. It is our INNER solar system drawn with the semi major axis' (average orbital distance from The Sun) distances drawn to scale. Obviously the planets themselves can't be drawn to scale ... Study this picture and I will post more tonight if I haven't had one too many Cheers Don Barone
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Post by Don Barone on Mar 21, 2018 8:43:29 GMT -5
Okay ... a few things to note or realize before we dig into the meat. 1) All planets orbit The Sun in an elliptical ... not circular manner. As an example we will use Mercury. It's closest approach to The Sun in it's orbit around The Sun is 46,001,200 km or 0.307499 of an AU and called The Perihelion, AU standing for Astronomical Unit and referring to Earth's average distance from The Sun in kilometers which has been standardized to "Originally conceived as the average of Earth's aphelion and perihelion, it is since 2012 defined as exactly 149,597,870,700 meters (about 150 million kilometers, or 93 million miles). Mercury's furthest distance from The Sun is 69,816,900 km or 0.466 697 AU and called The Aphelion. To calculate the Semi major axis we simply add the closest and furthest distance from The Sun and then divide by two so thus for Mercury we get 46,001,200 km + 69,816,900 km = 115,818,100 and divide by two gives us 57,909,050 km which is the number I will use for the semi major axis of Mercury. Now most people use as a base in our solar system The AU or Astronomical Unit however the secrets are revealed ONLY IF WE USE ... THE SEMI MAJOR AXIS OF MERCURY ! Many legends are told of how Mercury is "the messenger of The Gods" So I have come to believe, after years of study, that the messages Mercury is bringing from "The Gods" (in my opinion The Gods being ... "The Planets" and "The Sun") are mathematical.. 2) That hidden within the "mathematical" messages of Mercury one can find some amazing ratios that correspond to some of the most important numbers in our universe. These being ... sq rt of 2, Pi, Phi and of course sq rt of 3. 3) That if one looks closely enough and studies enough one will find how and why and when the measuring systems we use on Earth came to be ... And now as Barnum once said ... On with the show ... !
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Post by Don Barone on Mar 21, 2018 9:13:29 GMT -5
The first image I am going to post is an illustration showing the semi major axis' of the inner planets remembering that semi major axis is simply the average of a planet's closest and furthest distance from The Sun in any given orbit. Illustration #1 Now following in our original plan to use Mercury as a mathematical messenger I am going to simplify this immensely and instead of using the unwieldy 57,909,050 km I am going to simply call the distance 1 MU (Mercury Unit) Now the numbers I will be posting will simply be the semi major axis of the other planets in kilometers DIVIDED BY 57,909,050 to give us our simplified version of our solar system . Here is the math to further simplify things: 108,208,000 / 57,909,050 = 1.868585 149,598,261 / 57,909,050 = 2.5833313 227,939,200 / 57,909,050 = 3.9361585 ... and here is the illustration remembering that 57,909,050 kilometers has been reduced to 1 MU or 1 semi major axis distance of Mercury. Illustration #2 Now that we have done that it is time to visually show you why it all works at Giza. For within these numbers is an amazing mathematical relationship which I believe I am the first to discover. It is the basis for really all my work at Giza and it is the reason it all works so nicely. Hidden within these numbers if one steps outside the box and remembers the four important numbers, sq rt 2, Pi, Phi and sq rt of 3, one will see what I have seen and once seen correctly it can never be forgot. You will notice that to the left of The Sun in my diagrams is a second Mercury which I have placed equal distance from The Sun and which is also equal then to 1 MU or 57,909,050 kilometers. Now to the purest who will argue that the orbit is not circular I will agree however call it a mirror image if you will ... and from this comes the revelation that solves Giza ... and that is for next time ... Cheers Don Barone
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Post by Don Barone on Mar 21, 2018 10:31:21 GMT -5
Okay to see this all clearly it is imperative to remember my discovery that if one calls the base of The Great Pyramid the square root of 3 or 1.732050807569 then The Pyramid of Khafre equals the value of Phi or 1.618033988749895. The proof of that has been given many times but let's show it one more time ... base of The Great Pyramid is 9068.9968 "inches" while base of The Pyramid of Khafre equals 8472.00 "inches". Ratio is 9068.9968 / 8472.00 (Petrie has north side as 8471.9) = 1.0704670443814919735599622285175 so therefore if we multiply Phi by this number we should get the square root of 3. Thus 1.0704670443814919735599622285175 x 1.6180339887498948482045868343656 = 1.7320520616458961731236878831662 and squared gives us 3.0000043 and correct to 4 millionths (4/1,000,000) !!!!! Close enough I should think. But now the fun part and the new part. A new way to visually show this. I really hope you enjoy this and that it might even prompt a comment since I can't remember the last time anyone commented on any of my posts. (other than Charlotte of course) As I was thinking about things I suddenly had the realization that I had claimed that the base of The Great Pyramid was twice the semi major axis of Mercury so we will start with that illustration ... Illustration #3 But I have made other claims for this I have also claimed the this square's side measurement is also the square root 3 so let's add that information ... But I also claimed that the base of The Pyramid of Khafre equals the semi major axis of Venus so let's show that ... And I have also claimed that this is Phi so let's add that ... So now let's combine the diagrams ... and let's label it ... And one final image for now ... Okay so just exactly what have I done here. It really is quite simple. I make the claim that 1/2 the base of The Great Pyramid is representing the semi major axis of Mercury. I further make the claim that this is equal to 1/2 the sq root of 3 making the total base equal to the sq rt of 3. I further make the claim that the distance to Venus is represented by the value Phi in relation to the base of The Great Pyramid when it is given the value of sq rt of 3 ... Okay so let's check the math to see how we have done ... 2 MU's = sq rt of 3 = base of G1 = 9068.9968 2MU = 1.73205080769 = base of G1 = 9068.9968 Base of G2 = Phi = 1.61803398875 = 8471.9 "inches" Now my first claim is that G1 = sq rt of 3 and G2 = Phi Let's check and see how our solar system does ... G1 is 2 MU's = 57,909,050 x 2 = 115,818,100 km but also I claim equals sq root of 3 or 1.73205080769 For this to work out exact 115,818,100 / 108,208,000 (semi major axis of Venus) should equal Sq rt of 3 / Phi ... Solving we get ... 115,818,100 / 108,208,000 = 1.07032745238 Sq rt of 3 / Phi = 1.73205080769 / 1.61803398875 = 1.07046626932 1.07032745238 / 1.07046626932 = 0.999870 So our solar system checks to sq rt of 3 and Phi to within 13/100,000ths !!!!!!!!!!! And this is why Giza works. It is becasue G1 and G2 are in the ratio of sq rt of 3 to Phi and Mercury and Venus are as well. Now how many people do you suppose know that ? But there is a bit more so hang in there ... Cheers Dob Barone
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Post by Don Barone on Mar 21, 2018 12:30:10 GMT -5
Another easy and quick way to check my math is to call 1 MU or semi major axis of Mercury 1/2 of the sq rt of 3 or 0.86602540378443864676372317075294 thus if distance to Venus is equal to Phi we should get 1.6180339887498948482045868343656 / 0.86602540378443864676372317075294 = 1.8683447179254313929022372470961 and if we are correct this number times 57,909,050 shoudl give us the semi major axis of Venus ... so we have 57,909,050 x 1.868344718 = 108194067.7 so divide by actual of 108,208,000 to get a ratio of ...
108194067.7 / 108,208,000 = 0.999871 or 13/10,000ths !
So in conclusion we can affirm that the semi major axis of Mercury is 1/2 the square root of 3 and semi major axis of Venus is equal to Phi ... now how easy is that ?
cheers db
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Post by Don Barone on Mar 21, 2018 18:19:33 GMT -5
Okay time for a few new ideas ... or at least a new way of looking at things. First let's look at this diagram again ... Now I have shown many times before that the diagonal of G2 IN CUBITS when taken as a diameter of a circle the resulting circumference is equal to 5 times the orbital period (days in a year) of our own planet Earth ... Here is that diagram . By the way 20.62 x 411.035836 = 8475.55 and Petrie has the west side of G2 as 8475.5. The diagram: So if use sides of 411.035836 for G2 the resulting diagonal is 581.292454 and them times Pi to give us a circumference of 1826.184103. If we divide this by the number of days in an Earth Year we get 1826.184103 / 365.25 = 4.99982 and close enough to call it 5 orbits of planet earth in days ... but it gets a touch neater than that with a new observation I discovered today. Since we have tried to go back to the simplest and smallest units I decided to repeat this process but using Phi instead of 411.035836 and came up with this ... The sqaure root of (Phi sqrd + Phi sqrd) = Sq rt of (2.61803398875 + 2.61803398875) = sq rt of 5.2360679775 = 2.288245611271 which is our diagonal and if used as a diameter of a circle gives us a circumference of 2.288245611271 x Pi and equals 7.188735602 But the fun is just about to start . Since sq rt of 3 is so prevalent I decided to see what this number divided by sq rt of 3 which by the way is the base length of our blue square and representing base of G1 would give us and so I simply divided 7.188735602 / 1.73205080757 (sq rt of 3) to get this number ... 4.150418435. To most a meaningless number but I have played with these numbers for a very long time and instantly recognized it as a very important number ... for it is the number of times that a year on Mercury in Earth days will divide into the number of days in an Earth year. So we have 365.25 / 4.150418435 = 88.0035 and checking to the exact figure to a degree of accuracy of 87.969 / 88.0035 or 0.9996 . Nice additional proof that G1 is representing Mercury and G2 is representing Venus. So if allow the green circumference to equal one Earth year (365.25 days) the base of G1 is equal to one year on Mercury in Earth days (88 days) Cheers Don Barone
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Post by Don Barone on Mar 23, 2018 19:13:40 GMT -5
Good evening all. Some neat new things to show you tonight if I can get through it as I am very tired. Okay so as I was laying in bed last night with visions of all these things dancing in my head I suddenly was struck with what should have been so obvious to me earlier. This obvious fact was that whenever we saw Phi it could be the semi major axis of Venus and every time we saw sq rt of 3 it could represent the semi major axis of Mercury x 2. So keeping this in mind it is time to take another look at some of my earliest drawings ... here is one of my early favorites ... But the real all time favorite is this one ... where I noticed very early the reoccurring 1.071 ratio but was unaware of what it was ... We are going to re exam this image in the light of recent discoveries and revelations and what we shall find will ... well I always say astound but let's just say surprise you. Let's go right back to the basic Giza Rectangle .... the only thing I have decided to do for this time around is to call the right side of our rectangle 1000 x the sq rt of 3. This seemed an appropriate try since the sq rt of 3 had fit so predominantly into our previous solutions. And now let's add our most recent discovery ... And a second way of looking at this ... Well from these first couple of images it is obvious why I have claimed that The Great Pyramid or G1 represents Mercury and it is equally obvious why my claim of The Pyramid of Khafre or G2 being Venus seems to make sense as well but not as clear is my claim that G2 ALSO REPRESENTS ... THE SUN. How can we show this ? Well in the past I have used the fact that the equatorial gravity of The Sun is 274 m/sec/sqrd and that is also the height in cubits of The Pyramid of Khafre. But just today at work I found a very nice and illustrative way to prove my point and in a way help to prove The Giza Rectangle. The Key this time was using 1000 x sq rt of 3 or 1732.0508 for the side for that was the key ... Remember we can also call this twice the semi major axis of Mercury but let's not jump a head of ourselves. Here is an image ... Okay so the first thing I did was assume the ratio and got this diagram ... And this is what we get ... And in cubits .... A nice place to stop for today ... Cheers Don Barone
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Post by Don Barone on Mar 23, 2018 20:51:15 GMT -5
Detailed explanation to follow tomorrow ... Cheers Don Barone
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Post by Don Barone on Mar 24, 2018 16:38:12 GMT -5
Square root of 3 = 1.7320508075688772935274463415059 Phi = 1.6180339887498948482045868343656 ======================================== Total of the two of these is = 3.3500847963187721417320331758715 From diagram then: 3.3500847963187721417320331758715 = 1732.0508075688772935274463415059 1 = 1732.0508075688772935274463415059 / 3.3500847963187721417320331758715 = 517.01700490451307237960242030277 517.01700490451307237960242030277 x 1.7320508075688772935274463415059 = 895.500 cubits 517.01700490451307237960242030277 x 1.6180339887498948482045868343656 = 836.551 Width of G2 = 411.035 and divide by 2 = 205.5175 add to 895.500 and we get 1101.0175 and checking to John Legon's 1101 to within less than 4/10ths of 1 inch db
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Post by Don Barone on Mar 24, 2018 17:47:24 GMT -5
A cute little trick at Giza ... 2 Mercurys + 1 Venus vertically 2 Venus' + 1 Mercury horizontally Cheers Don Barone
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Post by Don Barone on Mar 24, 2018 19:19:55 GMT -5
Interestingly the two circumferences both relate to the number of days in an Earth year ... Old news but on a new diagram ... Cheers Don Barone
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Post by Don Barone on Mar 25, 2018 8:16:23 GMT -5
Doesn't really relate to anything yet but ...
1 / Phi x 12 = Pi / Phi all divided by 10
1.6180339887498948482045868343656 x 12 = 19.416407864998738178455042012388 / and reciprocal = 0.05150283239582457068371556953047
1.6180339887498948482045868343656 / 3.1415926535897932384626433832795 = 0.5150362148004838650072651015744 / 10 = 0.05150362148004838650072651015744
Could equal the slope of The Great Pyramid of 51 degrees 50 minutes and 36 seconds ... and as a decimal we get 51.84333
Just doodling so far this morning ... have not had my coffee ..
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Post by Don Barone on Mar 25, 2018 11:28:20 GMT -5
Hi all ... I was just sitting here looking at some older images of mine and suddenly had a realization that every time I had used G1 or 440 I could have used the square root of 3 and every time I used G2 or 411.035 to 411.05 I could have used Phi. I am about to embark on a study of this and will let you know (here obviously) what results are forthcoming.
Cheers Don Barone
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Post by Don Barone on Mar 25, 2018 12:03:41 GMT -5
Okay let's take this as a first one. It was simply the first one I found in my scan of my hard drive. So what we have here is the diameter or Mercury can be represented by the sq rt of 3 or 1.73205 or of course The Great Pyramid or 440 cubits and is 4879.4 kilometers The diameter of Mars is equal to 6794 kilometers and thus would equal 6794 / 4879.4 x 1.73205 and equals 2.41168 And we know from earlier research that G2 + G3 = Mars diameter or 6794 kilometers or 2.41168 units Now since we know that G2 is Phi or 1.618033988 then G3 MUST EQUAL 2.41168 - 1.618034 and gives us 0.79364638 and reciprocal is 1.26000 Petrie says: "Considering the various sources of error : that the dressed granite in situ. is very irregular; that the 1st course joint at S.S.W. may easily be estimated too far out; and that we have no guarantee in the moved granite blocks, or the limestone from the upper part, that the courses were horizontal (on the contrary, one granite block has two different joint surfaces, 1º 40' different); the best conclusion seems to be 51º 0' ± 10'. But from a consideration of the granite courses (see below), the angle would be 51º 10' 30" ± 1' 20"; and this might well be adopted, as being close to the very uncertain result from the measured angles.
Hence the height of the Pyramid would have been 2564 ± 15; or 2580.8 ± 2.0 by the granite courses."So to work out exactly we would need the following: 440 / 1.73205 x .79364638 or 201.61 and not the 201.46 that we get ... Hmmm ? Petrie also got these results ... "By 7 measures on finished granite, in situ. By 1st and 4th courses, in situ. at S.S.W. By 6 single blocks of granite, shifted By 9 pieces of limestone casing (brought to England) 50º 57' ± 28" 50º 42' ± 07" 51º 00' ± 09"51º 58' ± 15" " If we assume 1.26000 was meant to represent the height or 126 x 20.62 = 2598.12 and base would be 201.61 x 20.62 = 4157.1982 (Petrie has south side of G3 as 4157.8 ... I kid you not ! ) So therefore the angle of the slope would be 1/2 of 4157.8 divided into 2598.12 and we get ... and I am doing the calculations as I type, and was not expecting this ... gives us precisely 1.25 and tan relating to 1.25 is 51.34 AND WELL WITHIN THE BOUNDS OF PETRIE'S DATE !!!! And so can we say now and definitively conclude that G1 is indeed representing Mercury and that G2 + G3 represents Mars ? But Mars has part of Venus in it and we will have to explore that at a later date. Cheers Don Barone
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Post by Don Barone on Mar 25, 2018 12:09:28 GMT -5
Addendum to above post. From Wiki: Slope 51°20'25 and in decimal is 51.34027777 and we got 51.340191746 Now you really have to ask yourself ... how lucky am I or how good were they ... Cheers Don Barone
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Post by Don Barone on Mar 25, 2018 12:10:46 GMT -5
Next we will examine Nick L. (and my) work on the foot, the cubit and the meter at Giza ...
Cheers Don Barone
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Post by Don Barone on Mar 25, 2018 14:42:22 GMT -5
Okay here are the three pyramids again ... And then we have this image ... But we also have this now ... So we have 1 Royal Cubit equaling 1.73205 +1.618034 + 0.793646 or 4.143731176 So the "foot" is represented by G2 + G3 or 1.618034 + 0.793646 or 2.41168036875So if 4.143731176 = 20.62 inches then 2.41168036875 SHOULD equal 12 inches ... let's see how we have done ... if: 20.62 inches = 4.143731176 then 1 inch = 4.143731176 / 20.62 = 0.2009569 Thus 12 inches = 12 x .200959 or 2.41148274083Checks for 2.41168036875 / 2.41148274083 = 0.99992It would appear that we were almost spot on when we claimed G1 + G2 + G3 represented The Royal Cubit and also when we claimed that G2 + G3 represented the foot AND Mars ! Cheers Don Barone
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Post by Don Barone on Mar 25, 2018 16:40:31 GMT -5
And in the close category we have this ...
A year on Venus takes 224.7 days so if we allow this as a diameter we get a circumference of 224.7 x Pi or 705.92. Now if we were to call these "feet" we would have a circumference in inches of 705.92 x 12 or 8471.00 inches and only about 1 inch difference from 8471.9 for the north side of G2.
Just thought I would mention it ...
Cheers Don Barone
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Post by Don Barone on Mar 25, 2018 17:12:50 GMT -5
From earlier ... " ... So we have 1 Royal Cubit equaling 1.73205 + 1.618034 + 0.793646 or 4.143731176 " And we have this ... If Mars = 11 units then Ceres = 227,939,100 / 11 then times 20 and we get ... 414,434,727.3 amazingly close to our 4.143731176 and checks for 0.99985. So now can we claim that the three pyramids at Giza added together represent Ceres ? It is a thought to act on maybe later ... Cheers Don Barone
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Post by Don Barone on Mar 25, 2018 18:19:33 GMT -5
Some more doodling ... So a stylized Giza Rectangle and it's pyramids would go something like this ... G1: Height = 280.0 Base = 440.0 G2: Height = 274.0 Base = 411.0 G3: height = 126.0 Base = 201.5 ========================================================================= Total of all of these equals 1732.5 AND COULD BE THE SIDE LENGTH OF OUR GIZA RECTANGLE =========================================================================
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Post by Don Barone on Mar 26, 2018 13:51:14 GMT -5
Hi all we are going to try something that I don't often do ... we are going into ... THE THIRD DIMENSION ! I was re-reading this thread ... Masonic Tsunami Warning - Red Alert and came across some very valuable data which we can use in this thread ... We have discovered that sq rt of 3 / Phi = 1.0704662693192697958259095291383 Now in the other thread I posted I found this: Sq rt of 3 (1.73205) / Phi (1.618033988... = 1.0704662693192697958259095291383 and this number squared = 1.1458980337503154553862394969031 And probably because I have worked these numbers for so many years I felt that should I multiply by Pi I would get an interesting number and indeed I did when I got 3.5999448445929799833473332599504 ( divided by 3.6 and we get 0.999985) and that's where I left it but I suddenly saw another example clear as a bell and I will post it now. If we have a square with sides 1.0704662693192697958259095291383 we would get this configuration: And this would yield the following ... and now for the little gem I found ... thinking outside the box ... er... no ! Actually this time we are thinking INSIDE THE BOX and we get this final diagram ... So here we have nicely used all our major players ... Pi, Phi and Sq rt of 3 to achieve a nice three dimensional cube. Very nice I think Cheers Don Barone
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Post by Don Barone on Mar 26, 2018 14:11:34 GMT -5
And of course we have this gem to end this train of thought .... Now come on admit it ... isn't geometry fun ? Cheers Don Barone
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Post by Darkpiano on Mar 26, 2018 15:05:22 GMT -5
Today I wrote in my notebook, ((1/phi) + (1/phi)) is about 1.236.
6 * .523 is close to pi, 5 * .523 is close to (phi^2).
(1/(phi^(-3))) = phi^3 which is about 4.236
1 + 1 + phi + phi = 5.236
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Post by Don Barone on Mar 26, 2018 15:35:54 GMT -5
Hi Darkpiano
Yes 2 + 2 x Phi (same as you posted) = 5.236068
And interestingly 3 + sq rt of 5 (2.236068) also equals this 5.236068
An easy method of finding Phi on the computer (calculator) is to take sine of 18 degrees then times 2 then + 1 to give you 1.618033988
Since an inch is 2.54 cm if we allow 5.236068 (x 10 ) or 52.36068 cm we get a cubit as 20.61444
Cheers Don
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Post by Darkpiano on Mar 26, 2018 15:48:49 GMT -5
I saw a video on youtube that talked about taking 1 Foot, the Royal Egyptian Cubit, and the meter and putting them together and converting to feet. It equals about 6 feet.
The Royal Egyptian Cubit added to the Meter is about 5 feet.
0.524 meters is about 1.718 feet which is close to (e-1)
I have seen an equation phi is about equal to the square root of (5(((pi+1)/e)-1).
I rearranged the equation to be e is about equal to (pi +1)/(((phi^2)/5)+1)
and pi is about equal to (e ((phi^2)/5)+1))-1
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Post by Darkpiano on Mar 26, 2018 15:55:40 GMT -5
I made an error in pi is about equal to (e ((phi^2)/5)+1))-1. I'll need to look at how I typed it.
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Post by Darkpiano on Mar 26, 2018 15:58:42 GMT -5
((e ((phi^2)/5+1))-1) is about = to pi.
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Post by Don Barone on Mar 28, 2018 7:57:26 GMT -5
Hi again all ...
I have been thinking if this is indeed how "The Creator" brought his solar system into being then it should follow a logical and easy geometric pattern to follow and should come from the simplest of building blocks, 1 and 2. Can we do this ? Well ... stay tuned .
Cheers Don Barone
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Post by Don Barone on Mar 28, 2018 9:12:10 GMT -5
Okay shall we give it a go ? Step 1: And "the hand of god" moved over "the void" ... And a final image in this series showing ... maybe ... one of the points of creation. And also to show how simple it is to create the distance square root of 3. ... and since in our earlier work we have labelled "the square root of 3" both the base of The Great Pyramid of Giza AND the semi major axis of Mercury we are half way toward showing the simple solution to Mercury and Venus ... oh yes speaking of Venus we will find that next ... Cheers Don Barone ... and always remember "The Creator" among other things was the master geometrist !
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