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Post by Don Barone on Jun 9, 2017 19:31:41 GMT -5
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Post by Don Barone on Jun 9, 2017 21:13:09 GMT -5
Damn it happened again !
Nice long post and I deleted it somehow ... I could just scream.
Okay let's try again ...
In earlier posts I have shown how while searching the internet I found a guy who had used tan of an angle to be 1/2 base and had used 1000 for the radius and 1111 for the diagonal. The numbers he used were not quite exactly the correct number for the Pi angle getting 51. 84696 while Pi angle is 51.85397
I decided to try 1111.1111... or 1000 x 10/9ths for the diagonal and found that when multiply it by √3 / 3 x 10,000 and found that 10/9ths of this gave us 6415.00 which we immediately will recognize as G1 + G3 x 10 ! or 641.5 x 10. So now without using any measurements systems at all we have defined the large pyramid as 440 and 201.50 for the small but all numbers were obtained from mathematical formula and never lifting a tape measure.
The pyramids give us these possibilities:
G1 + G2 = 851.00 G1 + G3 = 641.50 G2 + G3 = 612.50 G1 + G2 + G3 = 1052.50
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The breakthrough last night came when I decided to see what using G2 + G3 = 612.50 would give me. I honestly can't believe I had not down this in over 19 years of research at Giza ... I decided to calculate the diagonal .... and as I said the number was so amazing I decided to use twice G2 + G3 = 612.50 x 2 or 1225.00 and so this is what I did. Here is that diagram ...
Diagonal was 1732.41 and if we use 612.03 we get 1732.50 precisely. So now I no longer needed the rectangle at Giza as I had been able to draw this diagonal length by using the bases of the pyramids provided ... Okay so let's clean it up a bit ...
So now instead of having to use an arbitrarily drawn Giza Rectangle G2 and G3 have kindly done the job for us and given us the length we need. So now in my other work I claimed that G1 was Mercury and 440.00 and 57,939,050 km and Mars was 1732.50 or 227,939,100 but now we can do that without using any other line than the diagonal. So now lets draw in "Mercury" by moving it into position ...
. PLEASE NOTE: NO GIZA RECTANGLE !!!!!!!! Stay tuned as next I will plot ... Venus ... then Earth ... and then complete the inner solar system by plotting The Sun !
cheers and I hope you are enjoying ... there is tons more coming.
Don Barone
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Post by Don Barone on Jun 10, 2017 5:36:54 GMT -5
Okay so now we will quickly plot Venus.
I had many times mentioned that 1/2 base of G1 times the ratio of Mercury to Venus of 1.8685 (108,208,000 / 57,909,050) equaled 220 x 1.8685 to give us 411.07 and then last night while looking at my diagram I realized that 440 or base of G1 x 1.8685 would equal 822.14 and suddenly saw a simple yet elegant way of plotting this on our diagram ... observe: . So now we have Mercury = 440.00, Venus = 822.00 and Mars at 1732.50. Only two left to plot. Earth which is a little tricky and then the correct placement of The Sun .
Stay tuned ...
Cheers Don Barone
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Post by Don Barone on Jun 10, 2017 20:06:42 GMT -5
Hi all ... a few things to add ...
Here is the diagram for defining Venus using G2 or The Pyramid of Khafre. Now finding Earth has been a challenge and I still have not found it exact but have found it twice to 0.9948 degrees correct. Here is how I did it.
First of all we have to calculate the value we are looking for in order to find it. If Mercury = 1 then Earth = 2.5833 ( if you need to know where this is figure is coming from I think perhaps you should consider looking at earlier threads) Since Mercury has been set as the value "440.00 cubits" then Earth would be 2.5833 x 440.00 or 1136.652. So in other words since we have assigned Mercury base of G1 or 440 then Earth must equal 1136.652 + or - . Finding it has proven to be very difficult.
Here is the neatest way to find it. The reason I am showing this first is that it is the easiest of the two to understand. I started with the belief that using only these three pyramids we msut be able to find the four inner planets and The Sun so we should be able to solve it with just 201.5 and 411.00 (411.04) and 440.00 ... they have given us all the other answers we have asked for but this one is rather tough.
Here is the diagram I came up with: So what you see here is G3 in a basically 4 x 4 configuration and we have 201² x 2 and then √ and we get 40401 x 2 = √80802 and equals 284.26 and times 4 ( there are four of them) to get 1137.03. So now let's combine all the images and remember we have only used the measurements of The Giza Pyramids!
Mercury = 440.00 and diameter of G1 while Mars equals 1732.50 and diagonal of square of 612.50 (G2 + G3) Venus equals base of G2 x 2 or 822.00 "cubits"And then Earth ...And now we will combine them but before we do we will move Mercury to center stage with all the others and here is the final diagram .. almost ..
May I present "The Clive Ross Memorial Solar System" and I just want to say .. I think Clive would be pleased. And now to complete this picture ... And reinstating the Giza Rectangle as a guide ...there is a lot more ... but later ...
Cheers Don Barone
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Post by Don Barone on Jun 10, 2017 20:55:35 GMT -5
And now just a couple of brain teasers ...
2 heights + 1 base = Venus and at the same time base x Pi = Earth
What numbers are we ?
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1 ------------------ x 1000 then divided by Pi = Earth 2 heights + 1 base
==================================================================== ___________________________ Base of pyramid "a" minus 1 / 2 base of pyramid "b" = √number of days in an Earth Year
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√9.9 / √3 = ratio of what two heavenly bodies in our solar system ?
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Total of all 3 pyramids in cubits x 4Pi = number of "inches in pyramid "G1" added to "G3"
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Cheers Don Barone
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Post by Don Barone on Jun 10, 2017 22:25:23 GMT -5
Okay now for some new truth and some neat new revelations. Let's go visit The Great Pyramid again but this time what I am going to show you, is as far as I know, going to be revealed here for the first time. Okay let's get The GP front and center. Now how many of us have multiplied these numbers and drawn circle after circle yet there was one relationship staring us in the face and we had missed it. Allow me to fill in the "height" in both cubits and "inches" and for the base as well: And then a couple of circles we have all seen. And then like a zillion times before I multiplied 440.00 by Pi and got the same answer I had got a zillion times before but tonight was going to be different because just a few moments before I did this I also had calculated the ratio between two planets ... and my heart skipped a beat for they seemed to match. Okay so 440.00 x Pi = 1382.30 ... now I had seen this number many, many times but tonight it was resonating with me ... I have, as many know, claimed for many years that The Great Pyramid is showing us Mercury and Earth but I had been unable to find Venus both in The Great Pyramid and on The Giza Plateau. Well I have put the latter to rest but could I do the former as well ? YES !!!! I had been dividing and figuring out ratios when I chanced to divide the semi major axis of Earth and Venus. Most of us know the ratio as 1 Earth and 0.723324 Venus ... but this night I went the other way and divided Earth at 149,598,261 kilometers by Venus at 108,208,000 km and got 1.38251. Then I moved onto other things and one of the next things I did was multiply base of G1 by Pi or 440.00 by Pi and got ... are you ready for this ... 1382.30 and I noticed right away that the first 4 numbers were a match which would give us at the very least a 0.9999 accuracy. So if Earth was going to be 1.38251 x 1000 or 1382.51 then Venus would have to be 1000 ! So I looked and wondered if I could find 1000 within the measurements of The Great Pyramid and smiled as I realized that 280 + 280 + 440 = 1000 !!!!!! or 2 heights + 1 base = Venus and base x Pi = Earth Sweet and the beauty is that the formula is in seked 5.5 ... not in any of the numbers I choose or you choose to use. It is simply in the ratio of 5.5 to 7. So base is 11 x Pi = 34.55752 or Earth while 7 + 7 + 11 or 25 = Venus (34.55752 / 25.00 = 1.38230 Now what do yo think about that ? It will also work for 1/2 base and height as we get 140 + 140 + 220 or 500.00 and 200 x Pi = 691.50 and oh wow we have seen these numbers many times in "The Giza Rectangle" and 691.50 / 500.00 = 1.38230 and the ratio of Earth to Venus ... 0.99985) Who would have thunk it .... the picture that is worth the thousand words ... Cheers Don Barone
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Post by Don Barone on Jun 11, 2017 9:07:18 GMT -5
And I submit for your inspection ... 440 / 12 = 36.6666666... 36.66666666 x 3.1831 (1/Pi x 100) = 11671.36 Diameters of Planets: Mercury = 4878 Mars = 6794 Mars + Mercury = 11672.00 (ratio = 0.99995) and now to Base of pyramid "a" minus 1 / 2 base of pyramid "b" = √number of days in an Earth Year G2 minus 1/2 base of perfect Pi base of G1 (439.823) = √100 times the number of days in an Earth Year 411.035 - 219.9115 = 191.1235 191.1235² = 36528.19225225
36528.2 / 100 = 365.282
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Reverse engineer it and we get ... 365.25 x 100 = 36525 and √36525 = 191.115 "x" - "y" = 191.115 Set value for "y" as 1/2 perfect Pi base or 439.823 or 219.9115 So "x" - 219.9115 = 191.115 x = 191.115 + 219.9115 x = 411.0265 BASE OF G2 TO WITHIN 0.0085 OF A CUBIT OR LESS THAN 2/10TH OF A SINGLE INCH OR 0.99998 (411.0265 / 411.035 = 0.99998) =============================================================================================== Value of the number in base of G1 is 9068.9968 G1 + G3 = 3.18309886 (1/Pi x 10) 9068..9968 + 4154.18 = 3.18309886 G1 = 2.18309886 = 9068.9968 G3 = 1.0000000 = 4154.1851 G1 + G3 = 9068.9968 + 4154.1851 = 13223.1819 = 1/Pi x 10
G1 + G2 + G3 = 439.823 + 411.00 + 201.46 = 1052.283 "cubits" G1 + G3 (in "inches") 13223.1819 -------------------- = ------------- = 1052.267 4 x Pi 12.56637 or put another way: 13223.1819 and value of G1 + G3 divided by 4 = 3305.795475 and divided by Pi = 1052.267accuracy = 1052.267 / 1052.283 = 0.99998 Much larger ImageMuch Larger ImageMuch Larger ImageMuch Larger ImageClick to see a much larger and clearer image:Hope you have enjoyed this presentation. Comments are allowed you know ... Cheers Don Barone
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Post by Don Barone on Jun 11, 2017 9:41:07 GMT -5
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Post by Don Barone on Jun 11, 2017 11:13:48 GMT -5
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Post by Don Barone on Jun 12, 2017 8:22:11 GMT -5
Hi all ... Very tired this morning as I drove my daughter and her husband to the airport at 3:00 AM and I haven't been to bed yet (although I did have a four hour nap yesterday afternoon) . I am sitting here watching the flight as it heads for Mexico and Cancun for a belated honeymoon ... (one year on June 18th) ... anyways onward ... As is my destiny I chanced to find an interesting diagram by Scott Ornott which I will post below ... Now everyone who ever points out the fact that 555.5 FEET ( x 12 ) = 6666 inches has failed to truly grasp what is truly going on. As I stared at this image I of course decided to calculate the height in real inches for the pyramid portion and was somewhat miffed that it came to 5772.92 instead of my now infamous 5773.50 ... for a moment I was puzzled but then the answer came to me. It is not 555.5 and 6666 but is in fact .... 555.555555555555... or 5/9ths x 1000 and 6666.666666666666666666666 or 6/9ths x 10,000 but actually in realty is simply 5/6ths x 12 to get 6/9ths x 10. When we make that all important adjustment we get for the height 5773.50 and all is as it was meant to be. A simple check for this is if we use the equilateral triangle of 3333.333333333333 as 1/2 base and since tan of 60 is 1.7320508075688772935274463415059 or square root of 3 exactly we get 3333.333333333 x 1.732050807... and we indeed do get .... 5773.50 ... so I think it is now a given that this is what The Great Pyramid was showing us and NOT SEKED 5.5 ... BUT WAIT .... MAYBE THEY USED BOTH !!!!!!!!! Very nice ... so we have the two circles of 6666.6666666666 diameter and the line that connects the two intersecting points ... EQUALS THE HEIGHT OF THE GREAT PYRAMID ... HOW NICE AND NEAT ! ... So the secret of these two circles is to have the correct diameter and this is now known to be 6666.66666666666 or 6/9ths x 10,0000 ... I really like this. and just now I realized ... and you are going to love this I just now realized that the distance across the center of the two interlocking circles is ... and I mean really how sweet can it get ... it is EXACTLY .... 10,000 !!!!!!!!!!!! Here is a nice giant size image to look at. It all makes sense now ... doesn't it ? Amazing the things you find when you least look for them ... I remember I used to say ... "Keep searching for The Truth and one day ... it just might find ... you ! " Cheers there is more on other topics but time for a coffee ... daughters plane is midway over The Gulf of Mexico ... Don Barone
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Post by Don Barone on Jun 12, 2017 21:56:07 GMT -5
Hi all ... I would like to discuss The Vesica Piscis, the myths that surround it, the lies that are told about it and how it defines The Great Pyramid at Giza. Firstly for those who do not know what we are talking about here is an article that explains what it is. en.wikipedia.org/wiki/Vesica_piscisHere is a picture of it: I started thinking about this again when I saw this image posted by Scott Onstott: Here is a very large image to look at: imageshack.com/a/img922/7099/TivxaF.pngAs you will see he has the diameter of the circles as 555.5 feet and 6666.00 inches and like many, many others this is what is used. Since I claim that the height of The Great Pyramid is not only the square root of 3 but is 5773.50 inches. It is common knowledge that the line from the intersecting point of the two circles is equal to the square root of 3 so I decided to check and see if my 5773.50 fit his 6666.00 diameter. ... BUT IT DID NOT !!!!! Every time I checked I got 5772.92 AND NOT 5773.50 ,I WAS MOMENTARILY CAUGHT OFF GUARD BUT QUICKLY REALIZED WHAT THE ERROR WAS HERE AND THE ERROR THEY ALL HAD BEEN MAKING ALL THROUGH THE YEARS. Before I explain just a quick history of 555. It is of course the height of The Washington Monument ... en.wikipedia.org/wiki/Washington_MonumentI suddenly realized that it was not 555.5 feet and times 12 for 6666.00 inches but was in fact ... 555.5555555555555555555 and times 12 we get 6666.6666666666 or better 5/9 x 1000 and times 12 to get 6/9ths x 10,000. So they had all been wrong. It should be 5/9ths and 6/9ths and now when we calculate the middle line we do indeed get precisely and exactly 5773.50 or sq rt of 3 / 3 times 10,000. Link to a much larger image: imageshack.com/a/img922/1341/xInvzx.jpgAnd then speaking of 10,000 do you want to guess what the total diameter is of both circles ? Yup you guessed it 10,000 and the usual large image Okay now to check out other blatant lies told about this geometric form. Here is a typical diagram found on sacred geometry sites ... It would have you believe that this picture defines The Great Pyramid ... have a look: According to this diagram the pyramid in yellow is The Great Pyramid but can it stand up to geometric challenge ? Below is the mathematical challenge of this design and no it is not at all correct. The base using trigonometry is equal to 9148.5430 AND NOT 9068.9968. The design fails and all who would tell the uninformed that this is Sacred Geometry is so much nonsense. Some notes for the picture below ... red line is 10,000 becasue it is in fact still the radius of one of the large circles. large blue line is 5773.50 by definition and since it is cut in half the smaller blue line to the right is 5773.50 / 2 = 2896.75 Using √10,000 squared - 2886.75 squared or √91666674.4375 or 9574.2715 Now the bit that is left on the pink row is 10,000 - 9574.2715 or 425.7285 but to get the purple lien we have to take this off both sides and we get 9574.2715 (because we already have taken it off once) and then subtract 425.7285 again and we get 9574.2715 - 425.7285 = 9148.543But according to us it should be 9068.9968 so therefore this diagram lies and it is a fabrication and is worthless !!!! Click here for nice large imageThere is only one way to make it fit and that is shown by the image I post below. Click here for a nice super large imageAnd then this one to further explain ... And the nice large image.So once again I have flip flopped and determined that it was Pi and the circle that set the base for The Great Pyramid but 440 and 55 are very important as well so I think the builders have used both !!!! Cheers Don Barone
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Post by Don Barone on Jun 19, 2017 11:38:14 GMT -5
A little synopsis posted at Ma'at: Hi all anyone who has read DUNE's work over at Graham's knows he has done extraordinary research trying to prove that the ancients built The Giza Plateau using the modern inch. As most of you would probably rightly claim, short of time travelers, this is not a likely scenario. Yet his research is proven over and over and over again to be precise and correct. How is it then that this can be happening ? It is my contention that it is NOT THE INCH that he is finding but a mathematical number derived by the simple numbers, square root of 3 and Pi. As I have shown if we allow the height of The Great Pyramid to equal square root of 3 divided by 3 then times 10,000 ( I will show you why 10,000 a little later) we get a value of 5773.5027. It is just a number but it represents the height of The Great Pyramid and miraculously seems to also coincide with the modern number of inches involved in the same height distance. A rather neat coincidence that the number of inches would equal the mathematical solution to the height. So in my opinion the number of inches is simply a coincidence. The true number is simply sq rt of 3 divided by 3 times 10,000. I will post my diagram of discovery again to illustrate the point. My discovery that this was most likely was further bolstered when I found the following diagram: Here is the full size image: imageshack.com/a/img922/3034/EG9XfQ.pngWhat this diagram did not label is what the distance is between the top meeting of the circles or top of the pyramid and the other meeting of the circles. Well I filled it in for everyone: Here is the full size image: imageshack.com/a/img922/3105/zacBfK.pngAs you can see in the large image the middle distance is none other than our 5773.052 number or sq rt of 3 / 3 x 10,000 ! The diameter of the outer large circle is 6/9ths x 10,000 or 6666.66666 which if we use "inches" translates into 555.55555555 "feet" or 5/9th x 1,000 ! But there is still a bit more to discern. What we needed to do was calculate the size of the enclosing rectangle and we get, very nicely I might add, the following: Here is the larger full size image: imageshack.com/a/img924/4631/jC6YD7.pngThis diagram reveals to us that the overall width encompassing both large circles of The Vesica Piscis ( see link here for a description) en.wikipedia.org/wiki/Vesica_piscis which we find is 10,000 ! The diagram also shows the number of "feet", the number of "cubits" and of course our 9068.9968 solving of the sq rt of 3 and Pi problem. You will also notices an equilateral triangle and it is remarkably in the size of our large circles, 6666.666666 on it's three sides . But now how to get that number 9068.9968 / 2 or 4534.4984 for base of the larger triangle. This can be solved very easily by this simple procedure. First thing we do is draw a circle with diameter 5773.0527 as below: Here is full size larger image: imageshack.com/a/img924/1002/81yXfM.pngAnd the we simply rotate it to the right (or left) 1/4 turn or 90 degrees and we get this result: Here is the full size final image: imageshack.com/a/img924/862/GH8bbQ.pngOne quarter of the circumference defines 1/2 the base. And Pi and sq rt of 3 is all we have used (except a compass to draw the circle and a straightedge to draw the lines). It is amazing how our modern inch so closely matches what was in my opinion the original design of The Great Pyramid. Regards Don barone
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Post by Don Barone on Jun 25, 2017 13:14:44 GMT -5
Hi all here is a new website I am working on ... not sure which thread to put it in here for the time being. Hope you enjoy ... Half done at the present time ... Newest website at Altavista Cheers Don Barone
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Post by Don Barone on Jun 27, 2017 7:41:47 GMT -5
Well it appears that I have erred big time. I sent my site to John Legon and he was very quick to point out that Dash DID NOT re-survey The Giza Plateau as I had thought but had simply converted Petrie's data to the new coordinate system of The Giza Mapping Project of Goodman and Lehner (1984) to a degree of accuracy of 1/10th of a meter. All Dash did was to re-survey The Great Pyramid in 2015. Well this throws a rather giant monkey wrench into things however my original premise that depending on the north point used will determine the ratio of the vertical to the horizontal stands as proven... You really have to wonder why no one in ONE HUNDRED AND THIRTY SIX YEARS (136) has ever decided to re-measure The Giza Plateau. I mean really how the devil will they ever determine one way or the other whether there is a Pan Generational Plan at Giza if they refuse to study or collect the data. With my background in surveying maybe I should volunteer !
Cheers Don Barone
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Post by Don Barone on Jun 27, 2017 11:25:42 GMT -5
Hi all .. again this post is difficult to place in appropriate thread so I will just go ahead and post it here. A while ago I was trying some things with triangles and pyramids using certain values of tan units such as Pi / 4 or 0.785398 and 4 / Pi or 1.2732395 ... what I found is that if we assign the height as 4 units (280 cubits or 7 ) and half the base as Pi (220 cubits or 5.5 ) the slope side distance is 1618.99 ...and hints of Phi ...If we use 1/2 base is Pi / 4 or 785.2982 then height is 1000.00 and slope angle is 1271.5543 but then I decided to see what a pyramid of 4/Pi and Pi / 4 would give us and I got a pyramid of 1/2 base or 785.2982 and a height of 1273.23995 and then I decided to calculate the slope and before reading on what do you suppose the slope distance was ? Well anyway here is the diagram ... Well believe it or not when we find the sq rt of 4/Pi² x 1000 + Pi/4² x 1000 we get √1273.239545² + 785.3981634² or √1621138.9383 + 616850.2751 or √2237989.2133 or 1495.991047 x 100,000 and this checks to the distance that Our Earth is from The Sun on average to a degree of accuracy of 149598261/149599104.7 = 0.999994 A very interesting "co-incidence" Click here for a larger view of that last image.Cheers Don Barone
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