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Post by Don Barone on Apr 28, 2017 18:14:08 GMT -5
Hi Charlotte et al ... Well it appears that once again the neurons in my brain have become agitated and some new ides are occurring to me. Two days ago I chanced to re-read an old thread where Gary Osborn, a once friend of mind, had suggested some ideas concerning a circle and a square. I had never agreed with his ideas but from his diagram I chanced to discover an ingenious way of finding a 3, 4 and 5 sided right angled triangle using only a circle with diameter 5 units and the sqaure that encloses it and I will give you the diagrams below. First we start with the circle.  Then we enclose it in a square ...  Now the original problem I proposed was what was the length of the side of the square whose chord length was the same length as it's height off the ground as illustrated in the diagram below.  I strongly suggested that it had to be 4 and thus beautifully illustrated the 3, 4 and 5 sided right angled triangle as illustrated in the diagram below ... Firstly I drew these lines ...  and then substituted these values ...  and there it has sat for over two years ... until last night and I decided to start drawing more lines ... ( I love drawing lines ) and found that this simple diagram yielded more than I had ever even dreamed of. And so I will post last nights work. However before I do that there is one observation, not my own, that a line drawn from the top right corner to the middle of the bottom line in the sqaure MARKS THE POINT OF THE 4 DISTANCE ON THE CIRCLE AS SHOWN IN THE DIAGRAM BELOW !!  NOW AS WE GO ON WITH THIS STUDY PLEASE TRY TO REMEMBER IT'S SIMPLE ROOTS. ONE SINGLE CIRCLE ENCLOSED IN IT'S CONTAINING SQUARE AND ONE DISTANCE ... OF 5 UNITS NOTHING ELSE IS NEEDED (other than a straight edge and a compass) and also please always try to remember that instead of this 3, 4 5 sided right angled triangle we could just as easily use ... The Pyramid of Khafre or P2 ! It is at this point I will take a short break and ask a very simply question. Which do you think came first ? The Circle or The Square ? Much, much more to come ... Cheers Don Barone . |
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Post by Don Barone on Apr 28, 2017 18:45:54 GMT -5
Okay just a couple of more image for this evening ... In this next diagram I would like you to take very special note that in the bottom right hand corner we have a simple 1,2 sq rt of 5 triangle but in the form .. 0.5, 1.0 and 1.118034 units. Now on other boards I have been taken to task because it was claimed that the ancients could not have measured Phi or 1.618034 when in this diagram you can see how easy it is by simply adding 0.5 (short side and 1.118034 (the hypotenuse and by drawing an arc down to the base line one could easily measure Phi !!!!!!! And of special interest and note if one uses the perimeter of the square which equals 20 units (4 x 5) and my 1.618034 (0.5 + 1.118034) one can easily arrive at my contender for the cubit ... 20.618034 INCHES !!!!! (20.00 + 0.5 + 1.118034 - 1 which is height of small triangle) But now the image and again I must remind you that all of these were arrived at from a simple circle with diameter of 5 and the enclosing circle. NO OTHER MEASUREMENTS WERE NEEDED !!!!!!! Diagram #1  Diagram #2  Diagram #3  Diagram #4  Remarkable that so many irrational numbers can be got from such a simple diagram but there is tons more for I promised you a Masonic Tsunami and for that I have to thank Charlotte for she gave me the piece I needed to tie it all together ... But that is for another time and maybe day ... Cheers Don Barone . |
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Post by Charlotte on Apr 29, 2017 9:35:12 GMT -5
Masonic Tsunami Warning ... Red alert, dramatic this, but I do like the geometry as little as I can follow. I'd say the circle came first cause it's better to be rounded than square  Don't want to distract you, maybe later Tesla's key to the Universe, numbers 3, 6, and 9? |
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Post by Don Barone on Apr 30, 2017 10:25:54 GMT -5
3,6, 9 is simply 1, 2 and 3 times 3 ... I find it hard to believe that all can be solved from these three numbers but hey what do I know compared to Tesla ? But on to a POSSIBLE Masonic link to all of this. Let us start with the same first two diagrams ... and then squaring it ... And now let us insert an emblem or image into the fray ...  And then drawing a few lines ...    Now in this diagram we can note our 3, 4 and 5 right angled triangle and we can also not that the diagonal from the left middle to the bottom right and from the right middle to the bottom left appear to intersect the base or points of the compass points EXACTLY ! Not sure yet of the proof of that but that can come later but for now we want to specifically focus on the ORANGE diamond ( a diamond in the rough ?) and it is important that we note its length. The sqaure is 5 units by 5 units and thus the point of each diamond is at the half way point or 2.5 units. To figure out the length we simply return to Pythagoras and use the old standby formula of a sqrd + b sqrd = c sqrd or 2.5 sqrd + 2.5 sqrd = c sqrd or 6.25 + 6.25 = 12.5 and the square root is 3.535534 !!!! Now why would I place several exclamation points after 3.535534 ? I would suggest you do some study of my last several points on geometry and I will be back soon to tie some of it in very nicely. Can't do it yet as it is still just a study in my head ... and I have to draw the iamges .... Cheers Don Barone . |
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Post by Don Barone on Apr 30, 2017 11:18:19 GMT -5
Okay let us press on. A while ago I came up with what I consider the finest bit of research I have ever done and that was when I found out that by using just sq rt of 2, sq rt of 3 and Pi I figured out how The Great Pyramid came to be designed as 906.89966 units or in reality IN INCHES ! But now I have come up with a design that allows us to easily calculate and draw The Pyramid of Khafre using just a circle and it's enclosed square and a known diameter of 5 units (However the 5 unit is not imperative as the ratios are the reality of the solution) and then like a bolt of lightning I realized something that to me was profound ... THE PRECISE SAME DIAGRAM CAN BE USED FOR BOTH PYRAMIDS. That is to say that the circle enclosed by the square can give us the easy solution to BOTH THE GREAT PYRAMID OF GIZA AND THE PYRAMID OF KHAFRE !!!!!!!!!!!!!!! It should have been obvious but the breakthrough for me was when I drew the diamond on the image that Charlotte had supplied to me. After doing the calculations for the length of the diamond it became instantly obvious to me that the following can be got with the simplest of tools. Please observe a little flash program I put together and then I will post the final iamge ... simple is as simple does ... The KISS principle in all it's glory for us to see. Master builders with the knowledge to see the simplest in all it's beauty ... preserved forever in the great pyramids of Egypt. Flash presentation:And the image ...  And the final proof I guess you would call it and what gave it away to me was that in The masonic diagram the diagonal of the diamond was 3.535534 while in the Great Pyramid diagram it was 353.553 a difference of exactly 100 times. Simply amazing and I will have to take a look at many things past to see how this ties in to all of that but I keep remembering Horus and Isis and Baby Horus and work I have done in the past and I start to maybe see even more ... time will tell. Hope you enjoy this latest "brain hiccup" of mine Cheers Don Barone . |
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Post by Don Barone on Apr 30, 2017 11:50:09 GMT -5
The next two images are from Kenneth Bakeman and I had done a very in-depth analysis of what his ides could mean. I will just post two images here to see if anyone (now that would be a change of pace) can tie the myth into the diagrams I have presented. I am drawing a blank for now.  .............  Have at it and good luck ! Cheers Don Barone . |
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Post by Don Barone on Apr 30, 2017 22:03:40 GMT -5
Hi all well the discoveries seem to continue I suppose mainly because I continue to torture the numbers. After some unmentionable tortures they revealed this to me. I was convinced there had to be a way to tie G1 into G2 using my first diagram of circumference / sq rt of 3 = 906.8996 and our 5 unit radius circle and square of 5 units per side but try as I might I came to dead ends and then I supposed ... well maybe for this solution I have to go outside (the box ). Maybe to find this part of the solution it lay outside the 5 unit sqaure and perhaps at another level and so I proceeded to draw the sixth level and arrived at this diagram ...  But how could 600 tie into our diagram ? Well for a change I am going to let you think on it and allow you, you phantom readers, to post your solution on what I have found. However I will leave you two major clues .... 1) REMEMBER THE RATIO OF G1 AND G2 2) THE 600 SQUARE IS IMPORTANT Cheers and good luck ... Don Barone . |
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Post by Don Barone on May 1, 2017 6:40:46 GMT -5
Okay good morning. Had trouble sleeping last night so am up bright and early and ready to carry on. First a very quick recap ... In our first diagram we had this formula ... Pi / 2 = 1.5707963267948966192313216916398 x 10,000 = 15707.963267948966192313216916398 / (sq rt of 3) 1.7320508075688772935274463415059 = 9068.9968 which just happens to be exactly the base of The Great Pyramid in our modern day inches. Now perhaps many have not realized the significance of this ... what are the chances, I mean really all arguments of co-incidence aside, that using just Pi, sq rt of 3 and our multiplying factor of 10,000 (remember height of The Great Pyramid was determined to be sq rt of 3 / 3 and then times 10,000 for 5773.50 inches) would result in the precise number of modern day inches in The Great Pyramid's base. I mean really ask yourself what are the odds of this occurring unplanned ? But what of Phi ? I have determined that when The Great Pyramid is deemed to be "the sq rt of 3" The Pyramid of Khafre becomes "Phi" Recap of proof is posted below .... sq rt of 3 / Phi = 1.0704662693192697958259095291383 sq rt of 3 = 9068.9968 and base of The great Pyramid Phi = 9068.9968 / 1.0704662693192697958259095291383 = 8472.00615385876635968251502207 North base of The Pyramid of Khafre is, according to Petrie ... 8471.9 ... A precise match and proof of my discovery as noted above about the relationship of G1 and G2 ! So off I went on a typical Quixotic quest of mine to find out how Phi could fit into all of this and my diagram as posted below ... I tried several things but nothing seemed to be working and then I did this ... remembering of course that all that is allowed is sq rt of 2, sq rt of 3, Pi and Phi in the solving of the problem. And this is what I can up with .... As you can see above going outside the 5 square we ended up drawing a 6 square or 600 square and that led me to this ... Pi / 2 = 1.5707963267948966192313216916398 x 1,000 (this time) to arrive at 1570.7963267948966192313216916398 Now I had supposed that dividing by Phi would yield something I could use and so simply divided by Phi or 1.618033988... and came up with 971.42355 ... a number that appeared t mean nothing ... but I concluded it had to involve Phi so what else could I try ... and then I said to myself ... "Self why don't you try ... Phi .... SQUARED ! " Phi squared is 1.618033988 x 1.618033988 and gives us 2.6180339887498948482045868343656 and now what do you supposed we get when we divide 1570.7963267948966192313216916398 by 2.6180339887498948482045868343656 ... well interesting and thankfully for my diagram we get .... 599.99 !!!!!! Within 1/100th of our 600 unit square ... nice I thought but then realized I had seem this number 599.99 or something very close elsewhere and that is where we will head next time ... So now we have two equations .... the last one being ... (Pi / 2) x 1000 and then divided by Phi squared gives us 599.99 Cheers Don Barone . Cheers Don Barone . |
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Post by Don Barone on May 1, 2017 7:37:40 GMT -5
Hi all I had earlier discovered something else and was wondering how we fit into this diagram ... AND ALWAYS REMEMBER WE SIMPLY STARTED WITH A CIRCLE AND IT'S ENCLOSING SQUARE ... WE NEVER USED A MEASURING DEVICE OF ANY KIND .... WE SIMPLY DREW A LINE AND THEN REPRODUCED IT 5 TIMES IN A STRAIGHT LINE TO GET OUR DIAMETER AND THEN DREW THE CIRCLE AND THEN ENCLOSED IT IN A SQUARE. All other discoveries come from basic simple GEOMETRY !!!! And really what are the pyramids but giant geometric lessons !!!!!!!!!!!! Okay here is a formula I had found earlier ... [(Sq rt of 3 / Phi ) squared] x Pi = 3.599945 / 3.6 = 0.999985 or 99.99985 accurate To fit into our diagram let's do this ... Sq rt of 3 (1.73205) / Phi (1.618033988... = 1.0704662693192697958259095291383 and this number squared = 1.1458980337503154553862394969031 1.1458980337503154553862394969031 x Pi = 3.5999448445929799833473332599504 x 100 = 359.9945 So can we easily plot 360.00 on our diagram with what we already have and lo and behold it becomes but child's play when we see the diagram below ...  To accomplish this we simply move our 4 square over to meet the side of the 5 sided square and then draw a line from the top left corner of the 5 sqaure to the bottom right hand corner of the 4 square the resulting angle is tan 0.8 or 38.66 and 51.34 degrees and where it crosses our red circle gives us the chord distance of 360.00 units. A truly remarkable feat and an amazing diagram that just keeps on giving and giving ! But what of our solar system ? I have also claimed that Giza marks out our solar system ... Can we possible find correlations to maybe prove this ? Let's try ... If you have followed my work then you have most assuredly seen this diagram of mine. It is the diagram I used to PROVE that the distance from The Sun to The Earth and from The Earth to Mars was showing us the ratio of The Meter and The Cubit ... observe below ...  But again defying all conventions and the laws of probability we find that 1 meter + 1 cubit IN INCHES GIVES US 59.99 INCHES !!!!!! Nice. And what of the angle we get with a 5 by 4 right angled triangle this 51.34 ... can it tell us anything about Giza ? Well I would submit that it can only refer to G3 and The Pyramid of Menkare and thus nicely yields this result. The base of Menkare is pretty well agreed to be 4154 inches so what would the height be if we assume an angle of 51.34 ... we would get this result 5/4 = 1.25 1/2 base is 2077.00 (approx) Height becomes 2077 x 1.25 = 2596.25 or 125.91 cubits. so how does that agree with the "authorities" ? From wiki : Menkare's pyramid had an original height of 65.5 metres (215 feet) and was the smallest of the three major pyramids at the Giza Necropolis65.5 meters = 2578.74 inches ... 215 x 12 = 2580.00 And what of Petrie ? 81. For the angle of the Pyramid, the data are rather divergent and not only do different methods vary in result, but the measures of similar stones vary far beyond the errors of measuring the angle or judging of the surfaces.
By 7 measures on finished granite, in situ.
By 1st and 4th courses, in situ. at S.S.W.
By 6 single blocks of granite, shifted
By 9 pieces of limestone casing (brought to England) 50º 57' ± 28"
50º 42' ± 07"
51º 00' ± 09"
51º 58' ± 15"
Considering the various sources of error : that the dressed granite in situ. is very irregular; that the 1st course joint at S.S.W. may easily be estimated too far out; and that we have no guarantee in the moved granite blocks, or the limestone from the upper part, that the courses were horizontal (on the contrary, one granite block has two different joint surfaces, 1º 40' different); the best conclusion seems to be 51º 0' ± 10'. But from a consideration of the granite courses (see below), the angle would be 51º 10' 30" ± 1' 20"; and this might well be adopted, as being close to the very uncertain result from the measured angles.
Hence the height of the Pyramid would have been 2564 ± 15; or 2580.8 ± 2.0 by the granite courses.
So it is basically impossible to determine with any accuracy what the angle of G3 was as it varies from 50º 42' ± 07" to 51º 58' ± 15" so could indeed have a value of 51.34 or 51º 20' 24" So there we have it folks. A simple diagram that would appear to encode all three Giza Pyramids .... Very nice Cheers Don Barone |
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Post by Don Barone on May 1, 2017 7:50:32 GMT -5
Okay still one thing bothering me. In the diagram below we can find G3 or Pyramid of Menkare and G2 or Pyramid of Khafre but where is The Great Pyramid ?  Cheers Don Barone . |
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Post by Don Barone on May 1, 2017 7:52:56 GMT -5
Hmmm ... I think I will have to go up to the next level ....
Will be back soon with the final solution perhaps ...
Cheers
Don Barone
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Post by Don Barone on May 1, 2017 8:19:31 GMT -5
Funny how it seems so obvious after you have the answer .... The final diagram ? And as you ponder this final diagram always remember we started with a simple square ( for I believe the square had to come first ) and then it's enclosed circle. No other measurement tool was needed ... It really is remarkable and I guess proves that THEY COULD HAVE DONE IT !!!!!!! If I figured it out could Imhotep have missed it ? I doubt it very much ! From here .... to eternity ?  Cheers Don Barone . |
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Post by Don Barone on May 1, 2017 8:26:26 GMT -5
And for clarity ...  Cheers until the next tsunami comes roaring in ... Don Barone . |
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Post by Don Barone on May 1, 2017 9:24:40 GMT -5
Well it seems that my brain is not quite done yet. If you have followed my work you will remember that I was convinced that The Osiris myth story was a mathematical encoding of something ... well now I think I have it !!!!! Let us return to Kenneth Bakeman's two drawings ... . Now I had done extensive work on this trying all manner of graphs such as these below ...  and this one ...  But you know what I was out thinking myself and it may be that the answer, whcih I always assumed was 360 /14 or a circle was in fact a great deal easier than that. It had to be as simple as the diagram I have shown in the posts above and now I think I have solved it beautifully ... Please observe ... Osiris curt into 14 pieces and perhaps the answer I have searched for for a very long time ... Simple is as simple does ... Please observe ANOTHER WAY TO CUT OSIRIS INTO 14 PIECES !!!!!!!  BUT THAT IS ONLY 7 YOU SAY ... WELL YES IT IS AND HERE IS THE STROKE OF GENIUS ...  And the real beauty of all of this as it all gets tied in together ... And yes you can not divide anything by 7 but it can be done easily ... if you start with the 5 square ... and I believe Moses tried to tell us that ...  Wow that is really nice ... !!!!!!!! And I think justifies and substantiates my previous findings that all the Osiris myths and other legends of Egypt were more than likely mathematical stories for as I saw in my first vision in 1998 ... if you wanted to hide knowledge, especially mathematical knowledge you would hide in within religion and make it a thing of reverence and worship for it would last a lot longer that way than any other possible way and so it is I will renew my quest of the mathematics of Ancient Egypt as hidden within the myths and legends although I think we have already managed to solve a great many of the mysteries of the ancient geometry of the Master Builders. For me a very satisfying day ... Cheers Don Barone . |
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Post by Don Barone on May 1, 2017 16:09:11 GMT -5
Image drawn to scale this time ...   |
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Post by Don Barone on May 1, 2017 16:20:41 GMT -5
Trying to find Isis ...  And a possibility ...  Cheers Don Barone . |
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Post by Don Barone on May 1, 2017 16:28:02 GMT -5
Perhaps a bit better fit ?  or maybe this ??  |
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Post by Don Barone on May 1, 2017 16:39:28 GMT -5
A bit clearer ?  |
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Post by Don Barone on May 1, 2017 17:06:47 GMT -5
A little better ?  |
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Post by Charlotte on May 2, 2017 8:11:24 GMT -5
Wow, Don, of course I'm overwhelmed, but glad you're searching to understand with us many other people. Osiris cut into 14 pieces is interesting and something to think about. I don't know what Tesla meant by the key to the Universe being the numbers 3,6,9, the only thing I can think of is the 3 stages of development of the embryo/fetus in the womb of a mother to be born a human being, the microcosm, as taught to us in so many ways: "Man, Grand Symbol of the Mysteries", Mr. Hall; "Man is the measure of all things", directly "Know Thyself", for when we do we'll know all things, it is written.
Again
Cheers
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Post by Don Barone on May 8, 2017 10:48:07 GMT -5
Damn I had a super long post and then I did something stupid and now it is gone ... sometimes these computers really piss me off ... but nevertheless let's start over ... but sadly it is never as good the second time as my patience is very thin . Okay let's try that again ... I am going to relate a little story that in my opinion proves that I am being guided or led by someone or something towards certain discoveries ... I have claimed this before but see what you think after this story. However before that I think it is imperative that we re-read something I wrote in October of 1998 at the peak of my Kundalini or enlightenment. Here is what I wrote: The Perfect Square
Prove all of this you say. I will be delighted to. It's in the Bible. Hidden within the most sacred of objects to be found there. The Ark of the Covenant. Whether it really existed or not is of no importance or relevance, for the secret I found is within it's measurements. What were these measurements. 2 1/2 cubits by 1 1/2 cubits. ....... The "Key" ...... Knowing that on top of the Ark was a "seat." In the Bible it is stated by "God" "Upon this Ark place a mercy seat." ..... The Mercy Seat ! This seat measured 2 1/2 cubits by 1 cubit. How do I know this measurement ? The same way Moses knew. The cubit is not only the length of a man's forearm is is also the length or distance from the knee to the floor ! ..... Even today this is the traditional height of any chair or seat !! .... So let's see what we have now. We have a square that measures 2 1/2 (2.5) cubits by 2 1/2 cubits. A simple square ? .... No not just any square. For within this square which is 2 1/2 cubits by 2 1/2 cubits ... if each side is multiplied by 20 ( the number of Egyptian inches that I contend is to found in the length of the cubit) we get 50 by 50. Thus the hypoteneuse, which is the square root of 50 squared plus 50 squared, by the grace of "God" or the biggest coincidence that has ever reared itself, the length is 70.71067811865475244.... Forever and ever Amen ! But why do I feel that the cubit was 20 Egyptian inches. Because if the cubit was 20 "inches", and perfection or completeness was represented by the circle , then the only number they could use was 20. For Lo and Behold 20 times the number for Isis (Or Isis "herself) which is 18 equals 360. It is "God's" word !! Co-incidence .... Perhaps .... But then why do we find these measurements ... IN THE 25TH CHAPTER OF EXODUS !!! ... HMMM ..... ALL THESE COINCIDENCES.
And further if as I have read somewhere the cubit was also at times 18 "inches." It still works. For a cubit of 18 "inches times a cubit of 20 "inches" still completes the thought. Amen ! This is taken from this link: donbarone.selfip.net/Chapter2.htmlI guess ever since then I had somehow somewhere deep inside me believed that the answer did indeed lay in a square 25 units by 25 units but I had been unable to prove it .. until now ? After posting this thread I decided to go to a mathematics board to see if I could get someone to prove my diagram defining the 3, 4 and 5 sided right angled triangle and how they can be found in a simple square enclosing a circle. I really didn't get the answer I needed but managed to find the proof myself. Here is that thread. Well a few days later as "luck", if you believe it was just luck, there was a posting by someone who asked if we could solve this problem for them. Here is the problem ,,,  My solution was r = 6a and I thought I was pretty clever but it was only a guess and I did not offer any proof although using a 15 by 15 grid or graph I came up with this iamge WHICH IS WRONG !  Well I was quickly taken to task and the correct solution was posted and it was supposedly r = 7/6 a. Ever the Doubting Thomas I decide to draw this solution to scale and here is what I got ...  and then for reasons that I really can't explain I decided to check the enclosed angles and lengths of various sides and this is what i got ...  And then this one followed ...  I then decided to duplicate my previous work here on the diagram and came up with this ...  But then an idea (where do these ideas come from ?) occurred to me. What would happen if we enclosed it all in a 25 by 25 PERFECT SQUARE ? And that will be my next post as I just want to post this so I don't lose it all again ... Be right back ... Cheers Don Barone |
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Post by Don Barone on May 8, 2017 11:38:35 GMT -5
Hi all since the top of the top circle extends an additional 7 units I decided to draw that square of 25 by 25 (18 + 7 = 25) So here is my first diagram ...  Since we had originally used an 18 by 18 grid to solve the problem I decided to draw that one in next ...  And finally we had also originally used a 12 by 12 grid for the smaller circle so I drew that in next ...  Now this image looked vaguely like a throne of an Egyptian god but I couldn't find a match. Now of course the next order of business was to draw in the two circles we had started with in the original problem ...  And now let's start to label our diagram with "known values"  Now let's add our most recent discovery ... the 5, 12 and 13 sided right angled triangle easily obtained from these two circles, 6 radius and 7 radius ...  I will stop this post here because my computer is acting up and I don't want to have to re-post this again ... Be right back . |
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Post by Don Barone on May 8, 2017 11:58:45 GMT -5
Okay carrying on with the next image we have this one ... What I did was duplicated the original discovery and drew in the 3 (15), 4 (20) and 5 (25) right angled triangle ...  Now in the earlier drawing using an 18 by 18 grid I had been unable to draw in properly The Great Pyramid angle or 440 /280 or 280 /220 or 22/28 and I found an ingenious way that this diagram allows for the solution of that problem ... observe as we locate G1 ... first be aware if we allow base = 22 units each unit would be 20 smaller units and the height would then go from 28 to 14 (14 x 20 = 280) ... Please observe the wonder of "The Perfect Square"  So let us now draw in our two pyramids, Khafre and The Great Pyramid arrived at with just simply circles and squares  And finally let's complete the triple play by adding G3 or Menkare's Pyramid ... Note here that I have determined that logic would dictate that G3 has to be in the form or 5/8 or 8 units in total base with 5 units in height or 16 units total base by 10 units height or 10/8 or 20 by 16 or 25 by 20 ... and now the plateau is complete ...  So there you have it ... Giza defined having never lifted a ruler ... Cheers Don Barone . |
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Post by Don Barone on May 8, 2017 19:42:01 GMT -5
And leaving no stone un-turned ....    It should be 6, 18 and then 19 but numbers can be so stubborn sometimes ... small concellation is that 18.97366 is the sq rt of 360 ! And then a far out idea ...  Cheers Don Barone . |
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