Post by Don Barone on Feb 14, 2017 0:44:07 GMT -5
Hi all one of the earliest memories I have of "my enlightenment" in 1998 is that the flood of insights I had was likened by me to Pandora's Box where once the "evil" was released, in my case the knowledge I had been given, it was impossible to unlearn what I had been given. Sort of like trying to put the genie back in the lamp. Once released it can never be forgotten or put back in the brain, thus the reason for the title of this thread. Imagine if you will that you are suddenly given the answers to everything ... all knowledge ... could you handle it ? I couldn't so my brain shut down or in reality shut off and I thought all had been lost but over the intervening 18 years it has returned in dribs and drabs and I have gradually regained some (not all unfortunately) of the insights and knowledge I held briefly. So as I am apt to do every once in a while I go over my old notes to see if I can see new things in what I had discovered and that leads us to this post. One of my last discoveries was the fact that the base of The Great Pyramid could be defined in simple equation form needing no unit measurement. All that was need needed was the equation as shown below:
[(Pi / 2)/ sq rt of 3] x 10,000 and solving we get 9068.9968 ... Now very few understand that the significance of this is that this equation that uses absolutely no unit measurements unbelievably gives us the number of inches in the base of The Great Pyramid ...
And now let us move on ... and we get these recent developments ... I am slowing coming to the realization that no unit measures are needed to understand The Giza Pyramids, one simply needs to know a few equations and to that end may I offer up this solution to G1 and G2 ...
First posted here:
Pandora's Box Re-visited
Posted by: Don Barone (IP Logged)
Date: February 12, 2017 12:46PM
Hi all. It has been and remains my contention that the pyramids can be linked as below ....
Height of G1 or The Great Pyramid = 5773.5 inches which is (within 1/10 or an inch) 280 [cubits] times 20.62 [inches] {20.62 x 280.00 = 5773.6}. This can also be written Sq rt of 3 / 3 then multiplied by 10,000. However reversing it backward if we allow height to equal [(sq rt of 3 / 3) x 10,000] and allowing the following diagram and The Pi angle and equation we get the base to equal 10 times the circumference of 906.899 inches.
G1:
But we have been there before but now think on this ... The Red Pyramid:
I suggest that the width of The Red Pyramid is simply [(sq rt of 3 / 2) x 10,000] or 8660.254 inches or 219.9705 meters or 419.9929 cubits when 1 cubit = 20.62 inches and the height of The Red Pyramid, despite all the other guesses that have been put forth is simply "height of The Great Pyramid divided by the sq rt of 2" or 5773.5 / 1.41421356 or simply 4082.4829 inches or 197.9898 cubits or 103.6951 meters .... However 4082.4829 can be written EXACTLY as 1/sq rt of 6 x 10,000 ... again using just equations !
Giving us this diagram ...
Thus it appears more and more likely that no unit measure was really needed nor do we have to know what unit was used. It is is keeping with the idea I have that it is universal in it's understanding and that no matter what unit is chosen it is not important for the pyramids can be solved by equation, and simple ones at that. However the curious fact that we arrive at 906.89968 for the circumference in our first diagram and the fact that there are 9068.99 inches (as a mean average distance in inches for the base of The Great Pyramid) had to make the "inch" the leading contender as the unit that might have been used.
But in all reality the heights and widths of at least these two pyramids can be defined using just simple equations and no unit measurement is needed. A breakthrough perhaps ...
Re: Pandora's Box Re-visited
Posted by: Don Barone (IP Logged)
Date: February 14, 2017 12:02AM
Further equations to consider ... ...
[(Pi / 2) / sq rt of 3] x 10,000 = base of Great Pyramid (in inches ? ) [ 9068.9968]
Therefore G2 equals {[(Pi / 2) / sq rt of 3] / sq rt of 3} X Phi then times 10,000 = base of G2 ( in inches) [ 8472.00615 ]
Again regardless of actual units used these equations solve for the base of G1 and G2 ... Now one has to ask how curious is it that the numbers derived from these equation equal precisely the number of inches involved. I am sure Alice would find this curiousor and curiousor as we once again start down the rabbit hole and attempt to do what the dormouse said and feed our heads ...
[(Pi / 2)/ sq rt of 3] x 10,000 and solving we get 9068.9968 ... Now very few understand that the significance of this is that this equation that uses absolutely no unit measurements unbelievably gives us the number of inches in the base of The Great Pyramid ...
And now let us move on ... and we get these recent developments ... I am slowing coming to the realization that no unit measures are needed to understand The Giza Pyramids, one simply needs to know a few equations and to that end may I offer up this solution to G1 and G2 ...
First posted here:
Pandora's Box Re-visited
Posted by: Don Barone (IP Logged)
Date: February 12, 2017 12:46PM
Hi all. It has been and remains my contention that the pyramids can be linked as below ....
Height of G1 or The Great Pyramid = 5773.5 inches which is (within 1/10 or an inch) 280 [cubits] times 20.62 [inches] {20.62 x 280.00 = 5773.6}. This can also be written Sq rt of 3 / 3 then multiplied by 10,000. However reversing it backward if we allow height to equal [(sq rt of 3 / 3) x 10,000] and allowing the following diagram and The Pi angle and equation we get the base to equal 10 times the circumference of 906.899 inches.
G1:
But we have been there before but now think on this ... The Red Pyramid:
I suggest that the width of The Red Pyramid is simply [(sq rt of 3 / 2) x 10,000] or 8660.254 inches or 219.9705 meters or 419.9929 cubits when 1 cubit = 20.62 inches and the height of The Red Pyramid, despite all the other guesses that have been put forth is simply "height of The Great Pyramid divided by the sq rt of 2" or 5773.5 / 1.41421356 or simply 4082.4829 inches or 197.9898 cubits or 103.6951 meters .... However 4082.4829 can be written EXACTLY as 1/sq rt of 6 x 10,000 ... again using just equations !
Giving us this diagram ...
Thus it appears more and more likely that no unit measure was really needed nor do we have to know what unit was used. It is is keeping with the idea I have that it is universal in it's understanding and that no matter what unit is chosen it is not important for the pyramids can be solved by equation, and simple ones at that. However the curious fact that we arrive at 906.89968 for the circumference in our first diagram and the fact that there are 9068.99 inches (as a mean average distance in inches for the base of The Great Pyramid) had to make the "inch" the leading contender as the unit that might have been used.
But in all reality the heights and widths of at least these two pyramids can be defined using just simple equations and no unit measurement is needed. A breakthrough perhaps ...
Re: Pandora's Box Re-visited
Posted by: Don Barone (IP Logged)
Date: February 14, 2017 12:02AM
Further equations to consider ... ...
[(Pi / 2) / sq rt of 3] x 10,000 = base of Great Pyramid (in inches ? ) [ 9068.9968]
Therefore G2 equals {[(Pi / 2) / sq rt of 3] / sq rt of 3} X Phi then times 10,000 = base of G2 ( in inches) [ 8472.00615 ]
Again regardless of actual units used these equations solve for the base of G1 and G2 ... Now one has to ask how curious is it that the numbers derived from these equation equal precisely the number of inches involved. I am sure Alice would find this curiousor and curiousor as we once again start down the rabbit hole and attempt to do what the dormouse said and feed our heads ...
