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Post by Don Barone on Dec 30, 2010 21:28:52 GMT -5
The Megalithic Yard found in The Solar System and in Ancient Egypt as well. Hi all lurkers and regulars of this forum. I have returned here because finding The Megalithic Yard as a direct distance in our solar system has to rank among the most important things I have ever stumbled upon. Not only does it prove beyond a shadow of a doubt that it is real but that it is also based on our solar system as are all the others; the inch, the cubit, the kilometre etc. They are all based on The Solar System and do we need to wonder any longer what As Above ... So Below really means. Here is my post to Ma'at and at Graham's: Hi all. I suddenly had a thought that if The Cubit fit, and The Yard and The Inch fit and The Kilometre fit at Giza then surely The Megalithic Yard must as well and so we are off on another ride. The discovery of the Megalithic Yard
When the late Professor Alexander Thom surveyed over a thousand megalithic structures from Northern Scotland through England, Wales and Western France he was amazed to find that they had all been built using the same unit of measurement. Thom dubbed this unit a Megalithic Yard (MY) because it was very close in size to an imperial yard, being exactly 2 feet 8.64 inches (82.966 cm). As an engineer he could appreciate the fine accuracy inherent in the MY but he was mystified as to how such a primitive people could have consistently reproduced such a unit across a zone spanning several hundreds of miles. ... The Megalithic Yard equals 32.64 inches which equals 1.58308 cubits when we use 20.618034 inches as a Royal Cubit. I immediately recognized that number from earlier work and so we once again look outwards into our solar system to find yet another proof that all is one and all measurement systems are based on one another. Observe this image:  Unbelievably when we let the distance from The Sun to Mercury equal 1 cubit then the distance from Mercury to The Earth is One Megalithic yard. Unbelievable ! ... and beautiful to behold. Cheers Don Barone PS: Proof: 149,598,261 / 2.58308 = 57,914,680.66 Distance to Mercury = 57,909,100 Accuracy: 57,909,100 / 57,914,680.66 = 99.99 % Very, very nice indeed ! The Master's Hand at work ! 
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Post by Don Barone on Dec 30, 2010 22:05:13 GMT -5
12 inches = 30.48 centimetres
1 Megalithic yard = 32.64 inches
32.64 / 30.48 = 1.070866
The Great Pyramid = 440 cubits
G2 = 411.04 cubits
440 / 411.04 = 1.070455
So do we have here The Great Pyramid representing The Megalithic Yard and the distance from Mercury to The Earth and the two planets involved, Earth and Venus ? I have long thought that the indentations in The Great Pyramid were put there to show the differing radii of Earth and Venus. And does G2 represent 12 inches or 30.48 centimetres showing us perhaps that two different measuring system might indeed be involved in figuring out the clues here at Giza.
Cheers
Don Barone
PS:
To make it exact we would need 440 / 1.070866 = 410.88 and would you believe that this is 8471.59 inches and would you further believe that the north side of G2 as measured by Petrie is equal to ... 8471.9 or accurate to 3/10th of an inch.
Can we doubt any longer ?
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Post by Don Barone on Dec 30, 2010 22:18:24 GMT -5
1/2 of 1411.83 = 705.915
If we allow 705.915 to equal feet then we get 705.915 x 12 = 8470.98 inches and within ONE INCH of the exact measurement as given us by Petrie for the north side of G2 which is measured at 8471.9
This yields a result of 12 Venus years if we allow the diameter to equal the length of day of 224.7 on Venus ...
224.7 x Pi = 705.915 and this is feet measurement of G2
12 x 705.915 = 8470.98
All in all ... simply amazing.
cheers
Don Barone
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Post by Don Barone on Dec 30, 2010 23:11:23 GMT -5
1 Megalithic yard = 1.58308 cubits 1.58308 cubits x 260 = 411.6 cubits 411.6 cubits = 8486.4 inches 8486.4 inches = 707.2 feet Sq root of 2 x 1000 = 1414.214 feet 1/2 1414.214 = 707.1 feet This is just 1/10 of a foot off and is exactly the distance that Perring measured for G2.  cheers Don Barone |
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Post by Don Barone on Dec 31, 2010 10:20:26 GMT -5
To the disbelievers: You seem to forget that I am using NASA's measurements. You also seem to think I have made errors. Could you point them out to me ? While I wait for you to answer here is the tasting of the pudding for you to ponder.  It is truly sad that people refuse to look at the obvious. The "creation" of The Universe, The Solar System and yes even ourselves must have followed the same principles. You all agree that a cubit was based on the anatomical lengths of a human body. Why then is it so hard for you to come to terms with the fact that The Solar System and probably The Universe itself followed the same blueprint. Simply put: As Above .... So Below Cheers and Happy New year ! |
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Post by Don Barone on Dec 31, 2010 11:05:48 GMT -5
These measures taken from Petrie's 1887 book:  and then inexplicably he states this which is an assumption of the fourth kind.  He ASSUMES the distance was supposed to be 360 cubits but I suggest that is was actually supposed to be 361.8034 cubits to check with the distance to Mars and the tie in to The Giza Plateau. Let's see how close the results are to MY assumption. I have suggested 361.8034 cubits times 20.618034 inches equal to 7459.675 inches and checking with the west side of the pyramid we find that it checks for 7460.3 - 7459.675 or 0.625 OR 6/10THS OF AN INCH OVER THE ENTIRE LENGTH OF THE PYRAMID !Yet you (the unbelievers) would have me believe that they used a cubit of 20.72 (+ or -) I should think it is YOU who would believe in tall tales and total speculation. Cheers Don Barone |
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Post by Don Barone on Dec 31, 2010 13:52:46 GMT -5
  The same ratios as the planets. Cheers Don Barone NOTE: These images seem to be in error ... I will leave them up while I try to figure out how I could have erred so badly. |
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Post by Don Barone on Dec 31, 2010 18:47:27 GMT -5
Hi all more ratios found in the lower planets of our solar system. Surely we must accept that ancient man knew all the measuring systems, the cubit, the metre, the inch and the Megalithic Yard. But what is humbling is that we can see, by looking at the planets how they are all inter-connected. Yet another proof:  Cheers Don Barone |
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Post by Don Barone on Dec 31, 2010 22:11:58 GMT -5
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Post by Don Barone on Dec 31, 2010 23:49:10 GMT -5
The solution for The Megalithic Yard appears to solve for squaring the circle  . The blue square equals the black circle .. EXACTLY.  Cheers and Happy New Year ! Don Barone |
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Post by Don Barone on Jan 1, 2011 1:48:09 GMT -5
Just FYI
Old Arabic Measures:
seir = 600 Arabic feet ~192 m Also noted as a stadion, a stadium-length.
Surprising 192 meters = 192 x 39.37 = 7559.04 inches
And very surprisingly this number converted to feet = 7559.04 / 12 = 629.92 and equalling EXACTLY the number of cubits from the base of G3 measured directly North to the south base of G2
ghalva = 720 Arabic feet ~230.4 m
Surprisingly 230.4 metres = 230.4 x 39.37 = 9070.848 and this is 1.3 inches larger than the largest side of The Great Pyramid which measures 9069.5. 9070.848 / 12 = 755.904 feet.
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Post by Charlotte on Jan 1, 2011 11:35:16 GMT -5
Happy New Year, Don and Family  It is a though the Giza Plateau is the 'Hall of Records" itself. I like the Vitruvian man, the Sun as his Crown, the Heart and the Navel, besides the Planets. Thanks for all this hard work which I know you enjoy, and the festive Clock. Love Charlotte |
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Post by Don Barone on Jan 1, 2011 20:25:21 GMT -5
Giza as The Hall of Records. Yes that is correct Charlotte. It is all there but one has to ask the question, surely The Ancients had to know that by the time we were able to discover the secrets hidden here we ourselves would already have the knowledge so the question arises ... Why go through all the trouble ? Was it to try and show us that life and knowledge and civilization is cyclic ? Perhaps. But here is yet another drawing.  .
 And I have long advocated that the correct length for one of the sides of G1 was 439.82 cubits (9068.22 inches and checking almost exactly with Petrie's measurements at Giza) . What I had never realized that 1/2 that base is 219.91 and this is EXACTLY Pi x 7 x 10. Cheers Don Barone |
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Post by Don Barone on Jan 3, 2011 0:29:27 GMT -5
These diagrams are not accurate. The concept is good but Earth is not correct. I have left them up as a lesson to always triple check your workThe Inner Planets Simplified: A Simple Geometric Solution To A Seemingly Impossible Problem Hi all ... Can it be this simple ?  .  .  .  .  .  Is it identical to The Gravity Globe circles ?  Is it identical to Horus and Osiris Very nice I think. Cheers Don Barone
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Post by Don Barone on Jan 3, 2011 10:47:49 GMT -5
The Egyptian flag prior to 1922  .  Close but no cigar. Solomon ? The Sun and The Moon ? Cheers Don Barone |
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Post by Don Barone on Jan 3, 2011 11:13:48 GMT -5
Quite simple. One half the square root of three times Pi 1/2 sq rt of 3 * 3.1415926536 = 2.7206990464 Cheers Don Barone |
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Post by Don Barone on Mar 18, 2018 16:54:26 GMT -5
Hi all ... this is my second attempt as once again my new and improved mouse deleted the page I was working on but we press onward ... Not a whole lot to talk about this time around as it seems the neurons firing my brain seem to have retired at 68, only wish I could but enough of this to point. We are going to revisit The Megalithic Yard as I have come to the realization that it is part of and incorporated into the design of The Great Pyramid and thus has to be linked in other ways to other things (insert here: solar system) Firstly however I would like to post what I think will clear up my earlier posts on how I discovered the number of "inches" in the base of The Great Pyramid by using simply the basic sq roots and Pi. Here is the image. NOW PLEASE IF ANYTHING IS UNCLEAR ... PLEASE ASK FOR A MORE DETAILED EXPLANATION !!! As I said here is the image ...  And now here is the image I have used to show "The Megalithic Yard"  and the link where most of this can be found ... When we do the math we find that sq rt of 3 x 2 x Pi = 10.882796185405307103564469545853 and "The Megalithic Yard" is defined by me (and others) as 1/4 of this circumference or 10.882796185405307103564469545853 / 4 = 2.7206990463513267758911173864632 ... "units" for they are not feet or cubits or really anything until we define what the diameter was measured in ... it is only "feet" if we defined the diameter as sq root of 3 x 2 FEET ! Until then it is simply a number or a ratio as the 0.90689986 was in the first diagram ... From this however a great deal can be learned and a great deal of information flows from this observation and I will post some of that later. don't have the stamina for these long bouts anymore ... Cheers |
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Post by Don Barone on Mar 19, 2018 7:58:20 GMT -5
Good morning ... This is definitely not as easy as it used to be.
Anyway to make it all a bit easier to see I will multiply our red circumference which is 1/2 Pi x 10,000 to give us a value of 15707.963267948966192313216916398 then as before I will divide this circumference by sq rt of 3 and we arrive at our value of 9068.9968211710892529703912882111 which I contend is the value for the base of The Great Pyramid. In my opinion it is simply a co-incidence ( is it ? ) that this matches our measured value in inches. Now lets look at the second image where we show that sq rt of 3 x 2 x Pi is equal to four Megalithic Yards (10.882796185405307103564469545853) with one Megalithic Yard equaling 2.7206990463513267758911173864632 "units" ... now remember this is not feet ! It can only become feet if we assign a value of feet to the original drawing where the radius would then equal 1.7320508075688772935274463415059 FEET (sq rt of 3) For now it is simply a ratio of this diagram ...
If we use our calculated value as the base of The Great Pyramid we find that 1/2 of 9068.9968211710892529703912882108 or 4534.4984105855446264851956441054 equals 2.7206990463513267758911173864632 Megalithic "FEET" so therefore 1 Megalithic Foot would equal simply 4534.4984105855446264851956441054 / 2.7206990463513267758911173864632 or 1666.6666666666666666666666666667 or simply 10,000 / 6. Further to this we have the fact that in our pyramid (Great Pyramid) we have a height of sq rt of 3 divided by 3 then times 10,000 to give us our value 5773.5026918962576450914878050196 HOWEVER in our second diagram where we show the Megalithic Yard we have given the diameter a value of 2 x sq rt of 3 or 3.4641016151377545870548926830117 so now the ratio between the diameter of our Megalithic producing circle is 3.4641016151377545870548926830117 and divided into the height of our Great Pyramid of 5773.5026918962576450914878050196 we get of course ... (5773.5026918962576450914878050196 / 3.4641016151377545870548926830117 ) 1666.6666666666666666666666666667
So therefore ONE MEGALITHIC "FOOT" = 1666.66666666... "PYRAMID UNITS OR 'INCHES' so rather nicely tying in the two diagrams and showing how the two are related. So could The Great Pyramid be a "megalithic" monument from the dimmer past ? Feel free to weigh in with your opinions
Will try to continue later
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Post by Don Barone on Mar 19, 2018 8:36:50 GMT -5
Ok just a very quick post to clear one little nagging question up ... HOW COULD ANCIENT MAN HAVE DEVISED THIS NUMBER SINCE IT INVOLVES THE SQUARE ROOT OF THREE ? Actually it is quite simple. Simply take a measurement of one unit then double it ... Here is how to do it: 1) Draw unit length label it 1 unit 2) Double it making sure to mark the halfway point 3) With radius 2 units draw a circle. 4) Join point where half mark touches circle to vertical diameter line 5) Done  using "blue" line as our new radius draw a second circle  Take 1/4 of circumference = 1 Megalithic yard Done  So in my estimation this was the value for the Megalithic "Yard" or ratio. It is my contention that ancient man would have simply measured 1/4 of the circle and would explain rather nicely why none of the measurements ever checked exactly and why they may have differed in different regions and eras but I am certain that this is how the Megalithic Yard was perceived and originated. At least that is how it happened in my reality ... |
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Post by Don Barone on Mar 19, 2018 9:46:37 GMT -5
Hi again ... Now that we have nicely tied in The Great Pyramid and The Megalithic Yard lets take it one step further and revisit some earlier diagrams I did ...  Since we now have determined that 1666.6666 "inches" or "units" is equal to ONE MEGALITHIC "FOOT" Let's see what our diagram can produce in Megalithic "Feet" This diagram now becomes ...  . |
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Post by Don Barone on Mar 19, 2018 17:17:13 GMT -5
Just a very quick short post for now ... Rather than go through the steps on this diagram to get our 9068.9986 base measurement I have just stumbled onto a much easier way to arrive at this number ... ...  We have determined that The Megalithic Yard is 2.7206990463513267758911173864632 "Feet" ... so I simply decided to see what the ratio was to our modern yard since one yard equals 3 feet so I decided to divided The Megalithic Yard by three and what do you suppose it equals ? ... 2.7206990463513267758911173864632 / 3 = 0.90689968211710892529703912882108 ... Nice - so now we have these equations equaling each other ... (Sq rt of 3 x 2 x Pi ) then divided by 4 [to get MY] then divided by 3 so this equals (sq rt of 3 x 2 x Pi ) divided by 12 = (Pi / 2 ) then divided by sq rt of 3 both equal to 0.90689968211710892529703912882108 and very nicely and neatly proving that The Megalithic Yard and The Great Pyramid are intricately linked ... Cheers |
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Post by Don Barone on Mar 19, 2018 17:42:10 GMT -5
Okay one more observation before we call it a night ... In this diagram ...  ... I have determined that the distance from Mercury to Earth is equal to The Megalithic Yard ratio. This equals 2.7206990463513267758911173864632. The difference in the semi major axis' of Mercury and Earth is (Earth) 149,598,261 - (Mercury) 57,909,050 to give us a value of 91,689,211 so if this equals 2.720699... then 1.0000 would equal 91,689,211 / 2.7206990463513267758911173864632 = 33700607.615150416817177641462473 (one "foot") So now let us divided this "one foot" value into the semi major axis of Mercury of 57,909,050 and we nicely get 1.7183384543478217936832013014985 and since we divided by ONE FOOT OUR ANSWER IS ALSO IN FEET AND IS 1.7183384543478217936832013014985 FEET and this would equal IN INCHES ... (drum roll please) ... 20.620061452173861524198415617982 inches and of course equals THE ANCIENT EGYPTIAN ROYAL CUBIT TO A DEGREE OF ACCURACY OF 20.62 / 20.620061452173861524198415617982 = 0.999997 accurate ... Now how do you suppose it ended up way up there ? Cheers |
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Post by Darkpiano on Mar 26, 2018 22:39:14 GMT -5
1 Foot + 1.718 Feet + 3.281 Feet = 5.999 Feet which is close to 6 Feet.
1 Foot + 1.718 Feet = 2.718 Feet. (e is 2.7182818284590452353602874713527...)
1.718 Feet is about 0.524 Cubits.
3.281 Feet is about 1 Meter.
1.718 Feet + 3.281 Feet is 4.999 or about 5 Feet.
(1.718)/3.281) + phi^2 is about equal to pi
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Post by Don Barone on Mar 27, 2018 9:13:50 GMT -5
Hi DP (sorry it is easier) Yes I had long ago got the fact that 1 cubit plus 1 meter equals 5 feet but the obviousness of adding 1 foot to the mix completely eluded me. Bad me ! Yes we have 20.62 (cubits) + 39.37 (meter) + 12 (foot) and they equal 71.99 inches and close enough to 6 feet to make me happy. These are very old iamges of mine ...   Drawing a blank on what the "foot" could relate to at the moment ... Cheers and good find |
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Post by Darkpiano on Mar 29, 2018 2:17:00 GMT -5
From the video I watched, he explains that the foot represents the original unity or Divine and the 5 representing the microcosm, 6 representing the macrocosm. 1 foot + cubit (e-1 feet) = e
The video also claimed the pyramid of Giza has 12 Math constants.
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Post by Don Barone on Apr 2, 2018 9:38:17 GMT -5
Hi DP ... Found your video ... Very interesting and I will try to incorporate it into my research in The Solar System as well as The Giza Rectangle ... The 12 Constants of The Great Pyramid
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Post by Darkpiano on Apr 2, 2018 16:47:00 GMT -5
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Post by Don Barone on Apr 2, 2018 20:19:48 GMT -5
Hi DP ... I found his accuracy wanting. He found his constants but the average accuracy was 99.94 ... I prefer to see 99.988 or better ... not happy even with 99.97 ... however this is cute ...  Diagonal 9068.9968 for base and 5773.50 for height yields ... diagonal of 12825.4983 and (2 x Diagonal) + Height = 31424.4966 inches and 10,000 Pi = 31415.93 and checks for 31415.93 / 31424.50 = 99.97 As to sq rt of 3 well 31424.4966 / (2 x 9068.9968) 18137.9936 = 1.732523304 ... sq rt of 3 = 1.73205081 checks for 99.97 meanwhile the math constant "Y" = 0.57721. and ours here is 1.732523304 and reverse is 0.577193 and checking to 99.997 and much closer ... Regards Don Barone |
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Post by Hector Black on Jan 15, 2023 19:38:25 GMT -5
Hi All, It is my beleif that the diagonal of any square which has 4 equal side lengths each being a Metre in length = a Metre plus half of a Megalithic Yard of .82944 metres , IE the diagonal= 1.41472 metres ( simple but accurate ) please check the astounding work of the late DH Leahy 82944 & the Four Fundamental Forces & The God Particle dgleahy.com/p22.html. Kind Regards Hector Black, Peebles, Scotland. peeblesblack@googlemail.com |
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Post by Hector Black on Jan 16, 2023 10:15:12 GMT -5
Hi All,
I forgot to add this to my previous post the number 1.41472 is a RATIONAL NUMBER as opposed to post-Greek irrational ratios for calculating or i should say approximating any given square or circle This type of logic would appear to be in accord with the thinking behind pre-Pythagorean geometry (not using degree/angles),rather using very accurate RATIONAL number lengths within the base and height of any given right angled triangle to obtain or determine a Rational number hypotinuse thus producing for example what we nowadays would term AN ANGLE stemming from the centre of a circle IE the radius or the diagonal of a square. I know this sounds like a load of gobbelygoop until one studies the findings of what is known as PLIMTON 322 a Babelonian clay tablet which has turned on its head the our understanding of ancient Mathematics and Geometry beautifully explained by Daniel Mansfield & NJ wildberger School of Mathematics & Statistics UNSW Sydney. PLEASE NOTE the number 1.41472 has 6 digits the Plimton system uses a base 60.
Kind Regards Hector Black.https://www.google.com/search?q=plimpton+322+pythagorean+triples+youtube&sxsrf=AJOqlzXw55PdRqgtwaqxRQjRJZvjZMl-Pw%3A1673880841707&ei=CWXFY-nxKoWjgQaBpr-gDQ&ved=0ahUKEwipmt2HrMz8AhWFUcAKHQHTD9QQ4dUDCA8&uact=5&oq=plimpton+322+pythagorean+triples+youtube&gs_lcp=Cgxnd3Mtd2l6LXNlcnAQAzoKCAAQRxDWBBCwAzoGCAAQFhAeOgUIABCGAzoECCEQFToFCCEQoAE6BwghEKABEApKBAhBGABKBAhGGABQxCZY_EJghkloAXABeACAAZcBiAGDCJIBAzAuOJgBAKABAcgBCMABAQ&sclient=gws-wiz-serp#fpstate=ive&vld=cid:79977154,vid:L24GzTaOll0
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